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WorksheetsPractice with the Trig Identities
Total questions: 26
Worksheet time: 4hrs 25mins
sec(u)
cos(u)
tan(u)
sin(u)
cot(u)
cos(-u)
cos(u)
-cos(u)
sin(u)
-sec(u)
sec(u)
Select all that are Pythagorean Identities.
sin2(u) + cos2(u) = 1
sin2(u) - cos2(u) = 1
tan2(u) + 1 = sec2(u)
cot2(u) + csc2(u) = 1
cot2(u) + 1 = csc2(u)
sin²θ
cosθ
tanθ
1- sin²θ
csc²θ
sec²θ
cscθ
1
Which could be a first strategy to simplify the left side?
Rewrite into sines and cosines
Combine fractions
Factor common factor (GCF)
Distribute
Combine like terms (add or subtract)
What could be our first strategy to simplify the right side?
Rewrite into sines and cosines
Combine fractions
Factor common factor (GCF)
Distribute
Use a Pythagorean Identity
Simplify to a single trig expression
−cosx
cosx
1
tan2x
sinx
Which of the following is the same as cos (A+B)
sinAcos B + cos A sin B
sin A cos B − cos A sin B
cos A cos B + sin A sin B
cos A cos B − sin A sin B
Which of the following is equivalent to tan (A−B)
tan A − tan B
1+ tanAtanBtan A −tan B
1− tanAtanBtan A +tan B
cos Bsin A
cos (α-β) =
sin α cos β + cos α sin β
sin α cos β - cos α sin β
cos α cos β - sin α sin β
cos α cos β + sin α sin β
If cosA=53 where 0°≤A≤90° and sinB=135 where 90°≤B≤180° find cos(A+B) .
(No Decimals accepted!)
(a)
If sinθ = 54, where 0≤θ≤2π,find sin2θ
2512
2524
−2524
53
If sinθ = 5−4, where π≤θ≤23π,find sin2θ
2512
2524
−2524
53
If sinθ = 5−4, where π≤θ≤23π,find tan2θ
7−24
724
−2524
2524
a solution to
sin θ = √(3) / 2 ?
π / 3
2π / 3
5π / 3
7π / 3
π/6,2π/3
7π/6
7π/6, 11π/6
Which of these is equivalent to 2cos2x − 3cosx = 0 ?
-cos2x = 0
cosx(2cosx + 3) = 0
cosx(2cosx − 3) = 0
cos x = ⅔
Why doesn't 2cosx − 3 = 0 have solutions?
cos x is never bigger than one
cos x is never equal to a fraction
Actually, this equation does have a solution, x = π
This equation will have a solution tomorrow.
tanx=tanxsinx
x=0, 2π, π
x=0, π
x=0, 2π
No solution.
2cos2x=3cosx−1
x=0, 6π, 611π
x=0, 3π, π, 35π
x=0, 3π, 35π
x=32π, π, 34π
Solve: 5tanx+3=6tanx+4; [0, π]
-1
43π
43π,47π
4π,43π, 45π,47π
Solve the equation for 0°≤θ≤360° . Select ALL correct answers. tanθ=−3
60°
120°
240°
300°
Simplify: 21−cos2x
−sin2x
sin2x
0
cos2x
Solve over the interval [ 0, 2π ) : sin2x+sinx=0
0, 32π, π, 34π
2π, 32π, 23π, 34π
0, 3π, π, 35π
2π, 3π, 23π, 35π
2sin(3x)cos(3x)=
sin(6x)
sin(6x)cos(6x)
cos(6x)
sin(3x)
