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WorksheetsMIDTERM QUIZ PHYSICS FOR ENGINEERS
Total questions: 50
Worksheet time: 49mins
A book is lying at rest on a table. The book will remain there at rest because
there is a net force but the book has too much inertia
there are no forces acting on it at all
there is no net force on the book
there is a net force, but the book is too heavy to move
A hockey puck slides on ice at constant velocity. What is the net force acting on the puck?
equal to its weight
zero
less than its weight but more than zero
depends on the speed of the puck
Which law is this picture illustrating?
Law 1
Law 2
Law 3
You kick a smooth flat stone out on a frozen lake. The stone slides, slows down and eventually stops. You conclude that
no net force acted on the stone
a net force acted on it all along
the stone has a natural tendency to be at rest
the force pushing the stone forward finally stopped pushing on it
Consider a cart on a horizontal frictionless table. Once the cart has been given a push and released, it move with constant velocity. What would have to be done in order to have the cart continue with constant acceleration?
push the cart longer before release
change the mass of the cart
push the cart continuously
push the cart harder before release
A 10 kg object experiences a net force of 20 Newtons. Calculate the object's acceleration.
2 s2m
0.5 s2m
200 s2m
3.33 s2m
A box is accelerated to the right across rough ground by a horizontal force Fa. The force of friction is Ff. The weight of the box is Fg and the normal reaction is Fn. Which is the free-body diagram for this situation?
Two blocks of weight 5 N and 2 N are attached to two ropes, X and Y.
The blocks hang vertically. The mass of the ropes is negligible. What is the tension in X and the tension in Y?
7N, 7N
7N, 2N
5N, 2N
5N, 3N
A cart of mass 4.0 kg is being pulled with a force of 24 N. The cart accelerates at 3.0m s–2. An unknown friction force also acts on the cart. What is the net force on the cart?
6.0 N
8.0 N
12 N
24 N
A constant force of 12 N is applied for 3.0 s to a body initially at rest. The final velocity of the body is 6.0m s–1. What is the mass of the body?
1.5 kg
6.0 kg
24 kg
36 kg
A box is pulled by a tension force with an unknown magnitude to the right. The box experiences a constant friction force equal to 20 Newtons. The box has a mass of 10 kg and experiences an acceleration of 5 m/s^2 to the right. What must be the magnitude of the tension force applied to the right?
50 Newtons
70 Newtons
30 Newtons
150 Newtons
An object has a mass of 30 kg and an acceleration of 2 m/s^2. What must be the net force on the object?
60 N
45 N
15 N
0.067 N
A 20 kg bike accelerates at 10 m/s2. What was the force?
30 Newtons
2 Newtons
200 Newtons
10 Newtons
The distance between the Earth and the Moon centres is 3.8 × 108 m. The mass of the Earth is, me= 5.97 × 1024 kg
and the mass of the Moon is, mm = 7.36 × 1022 kg. What is the gravitational force between the Earth and the Moon?
(G = 6.67 × 10-11 N m-2 kg-2)
2.03 x 1021 N
2.03 x 1020 N
4.03 x 1020 N
4.03 x 1022 N
The mass of the Sun is 2.0 × 1030 kg and the mass of the Earth is, me = 5.97 × 1024kg. The distance from the Earth is 1.50 × 1011km. What is the gravitational force between the Sun and the Earth?
(G = 6.67 × 10-11 N m-2 kg-2)
1.54 x 1022 N
2.54 x 1022 N
3.54 x 1022 N
4.54 x 1022 N
A rocket of 2.5 x 104 kg moves from Earth to the moon. The mass of the Earth is me = 5.97 × 1024kg. Calculate the Earth’s gravitational force on the rocket when its distance from the Earth is 1.0 x 109 m. (G = 6.67 × 10-11 N m-2 kg-2)
9.95 N
8.95 N
10.95 N
9.81 N
A 300 kg satellite is orbiting around the Earth at the height of 550 km. Given that the mass of the Earth is 5.97 × 1024kg and the radius of the Earth is 6.37 × 106 m. What is the value of gravitational acceleration at the location of the satellite?
(G = 6.67 × 10-11 N m-2 kg-2)
8.32 ms-2
9.81 ms-2
7.39 ms-2
5.65 ms-2
Newton’s Universal Law of Gravitation states that the gravitational force between two objects is directly proportional to the product of masses of the two objects and inversely proportional to
distance between the two objects.
square of the product of the body’s radii.
square of the distance between the centres of the two objects.
cube of the distance between the centres of the two objects.
If the distance between two particles is doubled, what
happened to the gravitational force between them?
Is reduced to one-fourth of the original value
Is reduced to half of the original value
Becomes double
Becomes four times
If the mass of the Earth becomes four times, what will happen to the value of g?
Double
No effect
Half
Four times
You are talking to your friend who is sitting 1.5 m in front of you. If your mass is 60kg and your friend's mass is 50 kg, what is the gravitational force between you and your friend?
A 6.9 x 10-8 N
B 8.9 x 10-8 N
C 9.5 x 10-8 N
D 1.3 x 10-7 N
Two identical bowling balls attract each other with a gravitational force of
3.0 x 10-9 N. The mass of each of the bowling ball is 6.1 kg. What is the distance between their centres?
A 0.83 m
B 0.91 m
C 1.60 m
D 6.20 m
The mass of Mars is 6.42 x 1023 kg. The acceleration due to gravity on its surface is 3.71 m s-2. What is the radius of Mars?
A 3.4 x 106 m
B 6.4 x 106 m
C 7.8 x 106 m
D 11.5 x 106 m
What is the mass of a planet with a radius of 3.39 x 106 m and a gravitational acceleration of 3.71 m s-2 on its surface?
A 2.7 x 1023 kg
B 3.8 x 1023 kg
C 4.7 x 1023 kg
D 6.4 x 1023 kg
A sphere with mass 100 kg is brought to the top of a mountain of height 6000 m. What is its weight there?
A 960 N
B 975 N
C 980 N
D 981 N
