WorksheetsUnit 6 AB Test Review
Total questions: 81
Worksheet time: 4hrs 4mins
What does this picture represent?
Left Riemann Sum
Right Riemann Sum
Middle Riemann Sum
Trapezoidal Sum
What does this picture represent?
Left Riemann Sum
Right Riemann Sum
Middle Riemann Sum
Trapezoidal Sum
What does picture represent?
Left Riemann Sum
Right Riemann Sum
Middle Riemann Sum
Trapezoidal Sum
Find the right-hand Riemann Sum, with three sub-intervals indicated by the table.
28
16
34
23
Find the Left-hand Riemann Sum, with three sub-intervals indicated by the table.
28
16
34
23
Use a midpoint Riemann Sum to approximate the area between 0 to 3 with 3 subintervals.
14
7
26
11
Use 3 trapezoids to determine the approximate area of the shaded area.
12
9
10
5
Based on the table, use a trapezoidal sum of 4 sub-intervals to estimate the area under the curve.
32.5
40.5
78
160
Select the correct integral notation for the summation below:
n→∞limk=1∑n(n2)[2(4+n2k)2]
∫46 2x2 dx
∫02 2x dx
∫24 2x2 dx
∫46 x2 dx
Select the correct integral notation for the summation below:
n→∞limk=1∑n(n4)[(−5+n4k)2+3(−5+n4k)+5]
∫−54 −5x2+x+5 dx
∫−54 x2+3x+5 dx
∫−5−1 x2+3x+5 dx
∫−1−5 x2 −3x +5 dx
Select the correct integral notation for the summation below:
n→∞limk=1∑n(n5)[4(n5k)]
∫45 4x dx
∫05 4x dx
∫05 x dx
∫45 x dx
Select the correct integral notation for the summation below:
n→∞limk=1∑n(nπ)[cos(π+nπk)]
∫0π πcosx dx
∫π2π −cosx dx
∫0π cosx dx
∫π2π cosx dx
Select the correct integral notation for the summation below:
n→∞limk=1∑n(n5)[1−5(−2+n5k)2]
∫−23 1−5x2 dx
∫−23 5x2 dx
∫16 5x2 dx
∫−21 1−5x2 dx
Select the correct integral notation for the summation below:
n→∞limk=1∑n(n3)[(n3k)3]
∫36 x3 dx
∫03 x3 dx
∫03 x dx
∫03 x + 3 dx
What is the upper limit?
n→∞limk=1∑n(n−6)[(3−n6k)2−5(3−n6k)+2]
−3
−6
3
5
What is the lower limit?
n→∞limk=1∑n(n7)[4(−4+n7k)+2]
4
2
7
−4
Select the correct summation notation for the integral below:
∫05 x4+2 dx
n→∞limk=1∑n(n5)[2(n5k)4]
n→∞limk=1∑n(n5)[(5+n5k)4+2]
n→∞limk=1∑n (n5)[(n5k)4+2]
Select the correct summation notation for the integral below:
∫−23 x2+11 dx
n→∞limk=1∑n(n5)[(−2+n5k)+11]
n→∞limk=1∑n(n5)[(−2+n5k)2+1]
n→∞limk=1∑n(n5)[(−2+n5k)2+11]
Which of the following definite integrals represent the area of the shaded region? (Scaled by ones)
∫03 x2+3 dx
∫13 x2+3 dx
∫31 x2+3 dx
∫13x2 +3 dy
Which definite integral represents the area of the region enclosed by y=9−x2 and the x-axis.
∫03 9−x2dx
∫33 9−x2dx
∫−33 9−x2dx
∫3−3 9−x2dx
If ∫25 f(x)dx=5 and ∫45 f(x)dx=π, find ∫55 f(x)dx.
−π
0
−0
π
If∫25 f(x)dx=5 and ∫45 f(x)dx=π, find ∫54 f(x)dx.
0
−1
−π
π
∫25 f(x)dx=5 and ∫45 f(x)dx=π, find ∫24 f(x)dx. If
π−5
2
5−π
−(5−π)
x: 0 2 4 6 8 10 12
f(x): 7 11 20 25 18 14 9
Using 5 subintervals, calculate the distance traveled using a left sum.
360
420
396
390
Evaluate the indefinite integral.
A
B
C
D
Evaluate the indefinite integral.
A
B
C
D
Evaluate the indefinite integral.
A
B
C
D
Evaluate the indefinite integral.
∫(2x+2x−3−6x−4)dx
x−x−3+2x4+C
−2x+C
x2−x−2+2x−3+C
2x2+2x−2−6x−3+C
Evaluate the indefinite integral.
∫(16x3+5−6x−3)dx
4x3+5+3x−3+C
4x4+5x+3x−2+c
16x4+5x−6x−2+C
15x+C
1.What should "u" equal in this integral?
csc(x)
csc2x
sin(x)
cos(x)
∫xn dx
1/nxn +c
1/(n+1)xn+1 +c
1/(n-1)xn-1 +c
1/n +c
∫sec2x dx
tanx +c
-cotx +c
secx +c
-cscx +c
∫410f(x)dx =
2π + 3
4π + 3
2π - 3
π - 3
Solve by substitution
∫ x (x2 + 7 )(1/3) dx
(3/4) ( x2+ 7 )(4/3) + C
(3/8) ( x2+ 7 )(4/3) + C
( x2+ 7 )(4/3) + C
(3/2) ( x2+ 7 )(4/3) + C
Solve using substitution
(1/2)*sin(π1/2)
(1/2)*(cos(π1/2)-1)
π
0
Solve using integration by parts
3t(e2t)/2 - (e2t)/4 + C
3t(e2t)⋅2 - 3(e2t)⋅4 + C
3(e2t) - (e2t)/4 + C
3t(e2t)/2 - 3(e2t)/4 + C
Let f be an even function
∫010 f(x) dx = 8
∫07 f(x) dx = 3
Find ∫710 f(x) dx
11
24
5
8/3
Hasil dari ∫(2x+3)2 dx = ...
34x3−3x2+9x+c
34x3+3x2+9x + c
34x3−6x2−9x+c
34x3+6x2+9x+c
43x3+6x2−9x+c
∫ 16−x22xdx can be solved by
inverse trig integration
the natural log pattern
completing the square
u-substitution
∫ 4+9x2 dx can be solved by
natural log pattern
inverse trig integration
partial fractions
u-substitution
∫ x2−x+1x2dx must be solved by first
completing the square
finding the partial fractions
using u-substitution
performing long division
∫ x2+13x−1dx can be solved by first
using inverse trig
separating the integral into two fractions
completing the square in the denominator
using the natural log pattern
