WorksheetsGenetics Review
Total questions: 54
Worksheet time: 1hrs 7mins
Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.
Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the
bluest hair in the valley.
What are the possible Genotypes for the offspring?
RR, RB, BB
RR, RB
BB, RB
RB
Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.
Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the
bluest hair in the valley.
What are the possible phenotypes for the offspring?
Red, Purple, Blue
Red, Purple
Blue, Purple
Purple
Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.
Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the
bluest hair in the valley.
What is the probability a child would have red hair?
0%
25%
50%
75%
100%
Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.
Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the
bluest hair in the valley.
What is the probability a child would have Blue hair?
0%
25%
50%
75%
100%
Oompahs can have red, blue, or purple hair. The allele that controls this trait is incompletely dominant. Use R for red and B for blue.
Orville Oompah has Purple hair and is married to Opal Oompah who brags that she has the
bluest hair in the valley.
What is the probability a child would have Purple hair?
0%
25%
50%
75%
100%
In some chickens the gene for feather color is controlled by codominance. The allele for Black is B and the allele for white is W. The heterozygous phenotype is known as erminette (Black and white spotter)
Two Erminete chickens are crossed with each other.
What is the Genotype for box #1?
BB
WW
BW
In some chickens the gene for feather color is controlled by codominance. The allele for Black is B and the allele for white is W. The heterozygous phenotype is known as erminette (Black and white spotter)
Two Erminete chickens are crossed with each other.
What is the phenotype for box #4?
Black
White
Erminette
In some chickens the gene for feather color is controlled by codominance. The allele for Black is B and the allele for white is W. The heterozygous phenotype is known as erminette (Black and white spotter)
Two Erminete chickens are crossed with each other.
What are the probability the offspring would be Erminete?
0%
25%
50%
75%
100%
In some chickens the gene for feather color is controlled by codominance. The allele for Black is B and the allele for white is W. The heterozygous phenotype is known as erminette (Black and white spotter)
Two Erminete chickens are crossed with each other.
What are the probability the offspring would be Black?
0%
25%
50%
75%
100%
In humans hemophilia is a recessive (h) X-Linked trait.
A male offspring was born with hemophilia, but both parents are normal.
What would the parents Genotypes have to be for this to happen?
XHXH, XHY
XHXh, XHY
XHXH, XhY
XhXh, XHY
In humans hemophilia is a recessive (h) X-Linked trait.
Cross a mom who is a carrier for hemophilia with a dad who has the disease.
How many children would have the disease?
0%
25%
50%
75%
100%
In humans hemophilia is a recessive (h) X-Linked trait.
Cross a mom who is a carrier for hemophilia with a dad who has the disease.
How many children would have the disease?
0%
25%
50%
75%
100%
In humans hemophilia is a recessive (h) X-Linked trait.
Cross a mom who is a carrier for hemophilia with a dad who has the disease.
How many would be male with the disease?
0%
25%
50%
75%
100%
In humans hemophilia is a recessive (h) X-Linked trait.
Cross a mom who is a carrier for hemophilia with a dad who has the disease.
How many would be female with the disease?
0%
25%
50%
75%
100%
"Bent" is a dominant X-linked gene in mice. It results in a short, crooked tail. A recessive allele produces normal tails.
If a normal-tailed female is mated to a bent-tailed male, what are the chances of a male having a bent tail?
0%
25%
50%
75%
100%
"Bent" is a dominant X-linked gene in mice. It results in a short, crooked tail. A recessive allele produces normal tails.
If a normal-tailed female is mated to a bent-tailed male, what are the chances of a male having a normal tail?
0%
25%
50%
75%
100%
Mrs. Canal is type A and Mr. Canal is type O. They have three children named Greg, Rosalind and Biff. Greg is type 0, Rosalind is type A and Biff is type AB...
Can BIFF be there son? Explain
Yes because he has a portion of A in his blood like his mom
Yes because his dad is type O and that is a universal donor
No because his sister is type A blood
No because neither parent has the B allele
Mrs. Canal is type A and Mr. Canal is type O. They have three children named Greg, Rosalind and Biff. Greg is type 0, Rosalind is type A and Biff is type AB...
What is Mrs. Canal's genotype? How do you know?
IᴬIᴬ , because Rosalind is A
Iᴮi because Biff is AB
Iᴬi because Greg is type O
ii because it is a universal donor
Mrs. Canal is type A and Mr. Canal is type O. They have three children named Greg, Rosalind and Biff. Greg is type 0, Rosalind is type A and Biff is type AB...
What is Mr. Canal's Genotype?
IᴬIᴬ
IᴮIᴮ
IᴬIᴮ
ii
Punnett Square: Type AB father and type O mother. What are the percentages of each offspring?
Type A: 50%, Type B 0%, Type AB 50%, Type 0 0%
Type A: 50%, Type B 50%, Type AB 0%, Type 0 0%
Type A: 25%, Type B 25%, Type AB 25%, Type 0 25%
Type A: 0%, Type B 0%, Type AB 50%, Type 0 50%
What is the Genotype for Type A that had a type O parent
IᴬIᴮ
Iᴬi
IᴬIᴬ
ii
What is the Genotype for Type 0
IᴬIᴮ
Iᴬi
IᴬIᴬ
ii
What is the Genotype for Heterozygous Type A Blood
IᴬIᴮ
Iᴬi
IᴬIᴬ
IᴮIᴮ
What is the Genotype for Homozygous "B" allele
IᴬIᴮ
Iᴮi
IᴬIᴬ
IᴮIᴮ
Two parents think their baby was switched at the hospital. The mother has blood type O, the father has blood type AB and the baby has blood type B.
Complete a punnett square and then answer the question. What possible Genotypes COULD the baby have inherited from the parents? (what genotypes could the parents produce)
Iᴬi
IᴮIᴮ
Iᴮi
ii
Two parents think their baby was switched at the hospital. The mother has blood type O, the father has blood type AB and the baby has blood type B.
Complete a punnett square and then answer the question. What is the mother's genotype? What is the father's genotype?
Mom genotype is IᴬIᴬ, Dad genotype is IᴬIᴮ
Mom genotype is ii, Dad genotype is IᴮIᴮ
Mom genotype is ii Dad genotype is IᴬIᴮ
Mom genotype is ii Dad genotype is ii
Two parents think their baby was switched at the hospital. The mother has blood type O, the father has blood type AB and the baby has blood type B.
Complete a punnett square and then answer the question. Was the baby switched at birth? (Do they have a baby that is not theirs? )
No, the baby is type B which is possible when Dad is AB
No, the baby is theirs - it has type B just like the mom
Yes - neither parent is type B so it must have been switched
The blending of two traits is known as ---
incomplete dominance
codominance
A condition in which both alleles for a gene are expressed so that both traits are visible is known as ---
Codominance
Incomplete dominance
What type of inheritance pattern is shown here?
Codominance
Incomplete dominance
Some flowers are controlled by codominance. Red flowers (FRFR), blue flowers (FBFB) and Speckled flowers (FRFB).
Cross a red flower with a speckled flower. What is the phenotypic ratio?
50% red, 50% speckled
25% red, 25% blue
100% blue
A red flowered plant (RR) is crossed with a white flowered plant (WW). The gene for petal color in these plants expresses incomplete dominance. What percentage of the offspring will have red (RR) flowers?
0%
25%
50%
100%
In fruit flies, eye color is a sex linked trait. Red (R) is dominant to white (r). What is the sex and eye color of flies with the following genotype: X R X r ?
male with white eyes
female with red eyes
male with red eyes
female with white eyes
Look at this cross: XB XB x Xb Y
What proportion/percent of the male children are colorblind (b)?
100%
75%
25%
0%
Colorblindness is a recessive X-linked disorder.
Which genotype represents a male with normal vision?
XN YN
Xn Yn
XN Y
Xn Y
A genotype where only dominant alleles were passed on
from both parents for one trait
BB AA TT LL
Homozygous Recessive
Homozygous Dominant
Dihybrid
Heredity
A genotype where one dominant and one recessive allele was passed on from both parents for one trait.
Bb Aa Tt Ll
Allele
Homozygous Dominant
Homozygous Recessive
Heterozygous
A genotype where only recessive alleles
were passed on from both parents for one trait
bb aa tt ll
Heredity
Homozygous Dominant
Homozygous Recessive
Phenotype
What is the genotype for a homozygous dominant offspring?
In flies, red eyes (R) are dominant to brown eyes (r) and brown bodies (B) are dominant to yellow bodies (b). A fly with genotype (RRbb) is mated with a fly that is (rrBb). What fraction of the offspring will have red eyes and yellow bodies?
1/4
2/4
3/4
1/2
