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Worksheetscalculus
Total questions: 130
Worksheet time: 10hrs 40mins
Point M with coordinates (3,4) is the midpoint of the line AB and A has coordinates (-1,6). What are the coordinates of B?
(1,5)
(2,10)
(7,2)
(1,2)
y=4x-2
y-3=-1/4(x-8)
What type of triangle is this?
Equilateral triangle
Scalene triangle
Acute triangle
Isosceles triangle
What type of triangle is this?
Scalene triangle
Equilateral triangle
Obtuse triangle
Actue triangle
What type of triangle is this?
Acute triangle
Obtuse triangle
Equiangular triangle
Right triangle
What type of triangle is this?
Acute triangle
Equiangular triangle
Obtuse triangle
Right triangle
The line inside this triangle is called
an angle bisector
a perpendicular bisector
an altitude
a median
The line insider this triangle is called
an altitude
a perpendicular bisector
a median
an angle bisector
What is true about the median.
Cuts the side of a triangle into 2 equal parts.
It is always inside the triangle.
It passes through the midpoint of the side of the triangle and the opposite vertex.
All of the above
If you found the midpoint of line segment AB, what should you do next to find the equation of the perpendicular bisector?
Use the midpoint and one of the points from AB to write the equation
Use the midpoint and slope perpendicular to AB to write the equation
Use the distance and midpoint to find the equation
Use the midpoint and slope of AB to write the equation
What is the equation of the line that passes through the points
(6, 5) and (4, -3)?
y= 4x- 29
y= 4x - 19
y= 4x + 19
y=-4x -19
What is the equation of a line that is perpendicular to the line y = 3x + 2 and goes through the point (3, -4)?
y = 3x - 2
y = -1/3x - 5
y = 3x - 4
y = -1/3x - 3
Points A(1,3) & B(-3,5) are the endpoints of a chord on a circle with centre not at the origin. What is the equation of the perpendicular bisector of chord AB?
y = 2x + 4
y = 2x + 6
y = -2x + 6
y = 2x - 6
Triangle ABC has vertices at A(1,5), B(-2,-2) and C(7,-1). What is the length of the median from B the nearest tenth of a unit?
2.5 units
6.7 units
7.2 units
9.1 units
What is the shortest distance (to the nearest tenth of a unit) between the origin and the line y = 2x - 10?
3.8 units
4.5 units
5.0 units
10.0 units
What is the area of triangle ABC which has vertices at A(-3,6), B(5,2) and C(1,-6)?
35 square units
40 square units
50 square units
55 square units
(x - 3)2
(4x+3)(2x-1)
(2x-1)(x+3)
10x + 15
x2 - 5x
k2+7x+10
x2 - 9x + 18
x2-5x-14
v2 + 3v - 88
4x3+14x2-30x
x2 - 49
3x2 + 18x +15
Hint: Factor GCF first.
3v2 - 4v - 7
x2 - 36
3x² + 5x - 12
8x3-27
9x2-6x-8
Write the explicit formula for the geometric sequence.
3, -12, 48, -192, ...
an = 4(3)n-1
an = 3(4)n-1
an = -4(3)n-1
an = 3(-4)n-1
What is the 14th term of the geometric sequence?
3, 9, 27, 81, ...
14,348,907
4,782,969
1,594,323
45
Find the partial sum S6 for the geometric series.
−54+8−80+...
S6 = 21,845
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Which of the series below is CONVERGENT?
a1=4
an=an−1⋅(1.5)
an=−n2−8n+106
an=(105)n
an=5n+6
n=4∑∞2(0.5)n−1
(a)
k=1∑∞(52)k Find the sum
52
32
0
∞
Expand (2x+4y)3
8x3+48x2y+96xy2+64y3
40x3+160x2y+320xy2+320y3
32x3+48x2y+96xy2+64y3
8x3+16x2y+32xy2+64y3
Calculate the coefficient of a4b6 in the expansion of (a+b)10 .
(a)
Find the binomial coefficient
(a)
Consider the expansion of (x+b)30 .
What is the 4th term's coefficient?
(a)
Which of these is the first step in mathematical induction?
Prove the statement is true for the first element in the set.
Show that if the statement is true for the first k elements, then it is true for the (k+1)st case.
Prove that the problem you are working on is the base to all proofs.
None of these are correct.
Which of the following is the induction step in mathematical induction?
Show that if the statement is true for the first k elements, then it is true for the (k+1)st element in the set.
Show that the statement is true for the first few elements in the set.
Show that your math problem is different from all other math problems.
None of these are correct.
When using mathematical induction to prove : i=1∑ni2=6n(n+1)(2n+1) . In step #2, after you have made your assumption, what are you trying to prove? (What is your goal?)
i=1∑k+1i2=6(k)(k+1)(2k+1)+(k+1)2
Sk+1=6k(k+1)(2k+1)
k=1∑n(k+1)2=6(k+1)(k+2)(2k+3)
Sk+1=(k+1)2
In the principle of mathematical induction, what is the term for the first condition?
Base case
First case
Inductive case
Introductory case
What is the mathematical term for the second condition of the principle of mathematical induction?
Base case
First case
Inductive case
Introductory case
What is the third step in Mathematical induction?
P(1)
P(k+1)
P(k)
n=k
1 + 3 + 5 + 7 + . . . + (2n − 1) = n2
On the basis of this assumption, [The statement is true for n = k:
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2]
What must we show next?
The statement is true for n = 1:
(2)(1) − 1 = 12
The statement is true for n = k:
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2
The statement is true for n = k + 1:
1 + 3 + 5 + 7 + . . . + (2k − 1) + (2k + 1) = (k + 1)2
Let P(n) = 2n − 1. Evaluate:
a) P(k)
b) P(k + 1)
a) P(k) = 2k − 1
b) P(k + 1) = 2n + 1
a) P(k) = 2k + 1
b) P(k + 1) = 2(k + 1) - 1
a) P(k) = 2k − 1
b) P(k + 1) = 2k + 1
1 + 3 + 5 + 7 + . . . + (2n − 1) = n2
To prove this by mathematical induction, what will be the induction assumption?
The statement is true for n = k:
1 + 3 + 5 + 7 + . . . + (2k − 1) = k2
The statement is true for n = 1:
(2)(1) − 1 = 12
The statement is true for n = k + 1:
1 + 3 + 5 + 7 + . . . + (2k − 1) + (2k + 1) = (k + 1)2
What is the first step in Mathematical Induction?
P(k)
n=k
P(k+1)
P(1)
What do you call the statement to be prove?
Inductive statement
Structure
Conjecture
Given
Find the first 6 terms of the sequence.
13, 19, 25, 31, 37, 43
7, 13, 19, 25, 31, 37
1, 7, 13, 19, 25, 31
7, 12, 17, 22, 27, 32
Find an explicit rule for the nth term of the sequence.
an= 15+(n-1)4
an= -15+(n-1)4
an= -15+(n-1)3
an= 4n -19
Use the formula Sn to find the sum of the first five terms of the geometric sequence.
22
2/3
18
21
Find the sum of the arithmetic series using a formula.
516, 240
516,242
116, 242
506, 242
Find the sum of the geometric series.
248
124
120
240
Find the limit. Hint: Where is the horizontal asymptote?
3/7
0
∞
−∞
Find the limit
6/5
0
∞
−∞
Find the sum of the infinite geometric series, if it exists. n=1∑∞8(51)n−1
8
8/5
10
Does not exist
Find the sum of the infinite geometric series, if it exists. 21−35+950−27500+...
205
19.5
108.75
Does Not Exist
What is the formula to find the nth term of an arithmetic series?
a_n = a_1 * (n-1)d
a_n = a_1 + (n-1)d
a_n = a_1 - (n-1)d
a_n = a_1 / (n-1)d
Find the sum of the arithmetic series: 2 + 5 + 8 + 11 + ... + 23, if there are 8 terms.
132
100
78
56
Write the summation notation for the arithmetic series: 3 + 6 + 9 + ... + 27.
∑(3n+3) from n=1 to 9
∑(3n) from n=1 to 9
∑(3 + 3n) from n=1 to 9
∑(3n-3) from n=1 to 9
What is the formula to find the sum of an arithmetic series?
n(a - l)
n(a + l)
(n/2)(a - l)
(n/2)(a + l)
Find the sum of the arithmetic series: 10 + 15 + 20 + ... + 50, if there are 9 terms.
275
400
240
325
Write the summation notation for the arithmetic series: 4 + 8 + 12 + ... + 40.
∑(4 + 4n) from n=0 to 9
∑(4 + 2n) from n=0 to 10
∑(4 + 5n) from n=0 to 8
∑(4 + 3n) from n=0 to 9
What is the formula to find the nth term of a geometric series?
a * r^(n-1)
a * r^n
a + r^(n-1)
a * (r-1)^(n-1)
Find the sum of the geometric series: 2 + 4 + 8 + 16 + ... + 256, if there are 6 terms.
340
768
510
1020
Write the summation notation for the geometric series: 5 + 10 + 20 + ... + 320.
∑(5 * 2^(n+1)) from n=1 to 7
∑(5 * n) from n=1 to 7
∑(5 * 2^(n-1)) from n=1 to 7
∑(5 + 2^(n-1)) from n=1 to 7
What is the formula to find the sum of a geometric series?
S = a + r
S = a / (1 - r)
S = a * r
S = a - r
Which trigonometric ratio should you use?
Tangent Ratio
Sine Ratio
Cosine Ratio
Any ratio
Which trigonometric ratio should you use?
Tangent Ratio
Sine Ratio
Cosine Ratio
Any ratio
Cos 60 = 10 /AB
cos 45o = ....
212
213
21
313
cos 60o = ....
212
213
21
313
cos 30o = ....
212
213
21
313
tan2x + 1 =
csc2x
sec2x
sec2x - 1
cscx
1 - sin2x =
cos2x
cos2x+1
csc2x
tan2x
Simplify (sec2x)(1 - sin2x)
-cos(x)
1
-1
-sin(x)
Simplify (Hint: you will need to FOIL first)
sinθ
cot²θ
tan²θ
cos²θ
Simplify...
cos(θ)cot(θ)sin(θ)
sec(θ)
1
Simplify...
sec(θ)
csc(θ)
secxtanx
cosx
cscx
cotx
sinx
tan2x + 1 = secx
cos 2 x + sin 2 x=
Which trigonometric ratio should you use?
Tangent Ratio
Sine Ratio
Cosine Ratio
Any ratio
Which trigonometric ratio should you use?
Tangent Ratio
Sine Ratio
Cosine Ratio
Any ratio
Which trigonometric ratio should you use?
Tangent Ratio
Sine Ratio
Cosine Ratio
Any ratio
Which trigonometric ratio should you use?
Tangent Ratio
Sine Ratio
Cosine Ratio
Any ratio
