WorksheetsStructural Theory
Total questions: 71
Worksheet time: 2hrs 33mins
Structural member design primarily for bending
Beam
Column
Slab
Tie Rod
Structural member primarily for compression
Tie Rod
Slab
Beam
Column
Structural member experiences both bending and compression
Frames
Trusses
Beam Column
Column-Beam
Loads that are permanent in magnitude and location
Earthquake Load
Live Load
Dead Load
Super imposed dead load
Humans, Motor vehicles, moving loads are what type of loads?
Dead load
Live load
Dead and Live load
selfweight
It refers to a system of connected parts used to support
a load.
(a)
It is the prediction of the performance of a given structure
under prescribed loads and/or other external effects such
as support movements and temperature changes.
(a)
It is the science and art of planning, designing, and constructing safe and
economical structures that will serve their intended purposes.
(a)
Based on the slides provided, which among the following is NOT part of the Typical Structural Engineering Project Flow?
Inspection of trusses
Planning Phase
Estimation of loads
Preliminary structural design
Which among the choices is NOT part of the structural analysis?
Analysis Methods
Outputs
Inputs
Loads & Actions
These are structural members subjected to a tensile
force. It is also known as bracing struts.
Trusses
Columns
Beams
Tie Rods
These are usually straight horizontal members used primarily to carry vertical loads. They are also usually primarily designed to resist bending moment.
Cables and Arches
Beams
Columns
Trusses
These are often in building and are composed of beams and columns that are either pin or fixed connected. The strength this is derived from the moment interactions between beams and the columns at rigid joints.
Frames
Cables and Arches
Columns
Trusses
These are members referred to as beam-columns and generally vertical and resist axial compressive loads referred to as columns. It is also subjected to both an axial load and a bending moment.
Cables and Arches
Beams
Trusses
Columns
This member may be selected when the span of a structure is required to be large and its depth is not an important criterion for design.
Beams
Trusses
Columns
Tie Rods
These are two other forms of structures used to span long distances. One is usually flexible and carry their loads in tension, while the other one must achieve its strength in compression since it has a reverse curvature to that of the cable.
Tie Rods and Trusses
Columns and Beams
Cables and Arches
Columns and Beams
In structural analysis, the configuration of the structure is represented by...
construction model
analytical model
design structure
engineering blue prints
Structures may be represented as either a plane structure (2D) or a space structure (3D).
TRUE
FALSE
Analytical models may be represented by...
tributary lines
line diagram
tributary areas
beams and columns
Flexible connections prevents relative translations and rotations. While Rigid connections prevent relative translations but allows relative rotations.
TRUE
FALSE
Given this symbolic representation, what type of support is this?
Rocker
Roller
Link
Hinge
Given this symbolic representation and reaction, what type of support is this?
Roller
Fixed
Rocker
Hinge
Given this symbolic representation and reaction, what type of support is this?
Rocker
Link
Hinge
Fixed
A structure is considered to be internally stable, or rigid, if it maintains its shape and remains a rigid body when detached from the supports.
FALSE
TRUE
An internally stable structure is considered to be statically indeterminate internally if all its support reactions and/or member forces can be determined by solving the equations of equilibrium.
TRUE
FALSE
These are notations for determining statical determinacy of structures EXCEPT
m = number of members
j = number of joints/connections
c = number of internal hinges
s = number of structure failures
In order to determine the statical determinacy of a structure, the number of unknowns (reactions, member forces) and the number of equilibrium equations must be compared.
TRUE
FALSE
All are the correct conditions in Beams EXCEPT
U < E: stable
U > E: statically indeterminate
U = E: statically determinate
Degree of statical indeterminacy (DSI) = U - E
All are correct conditions in Trusses EXCEPT
U < E: unstable
unknowns (U) = r + m
U > E: statically determinate
Degree of statical indeterminacy (DSI) = U - E
All are correct conditions in Frames EXCEPT
equilibrium equations (E) = 3j + c
unknowns (U) = 3r + m
U < E: unstable
U = E: statically determinate
Given this image, the member is STABLE since the three reactions are concurrent at B
FALSE
TRUE
Given this figure, the beam is UNSTABLE since the three reactions are all parallel.
TRUE
FALSE
A beam 12m. long is simply supported at the left end at a point 9m. from the left end. The beam carries a downward vertical load of 5 kN at the right end. Determine the deflection in millimeters at the free end. E=200 GPa, I= 50x106 mm4
20
12
15
18
A 10m. long simple beam carries a symmetrical load that varies uniformly from zero at the left support to 12 kN/m/at the midspan. Determine the midspan deflection.
450/EI
500/EI
550/EI
600/EI
A propped beam having a span of 6m. carries a uniformly distributed load of 600 kN/m over a length of 2m. from the restrained end. Which of the following most nearly gives the moment in kN-m. at the fixed end.
-780
-890
-620
-830
A fixed-ended beam 4m. long carries a uniformly distributed load of 2 kN/m. over the middle 2 m. Which of the following most nearly gives the end moments in Newton meters.
-1256
-4563
-1833
-2560
A beam 10m. long is fully restrained at both ends. The beam carries a load that varies uniformly from zero at the left end to 10 kN/m at the right end. Which of the following most nearly gives the location of the maximum deflection from the left support in meters.
5.247
4.342
3.875
4.875
1.) For a continuous beam, what should be appropriate structural measures to avoid unnecessary increase in internal stresses based on slope deflection method?
a.) settlement of supports should be within tolerable limit.
b.) Member sizes should be increase.
c.) Change support A with hinge support.
d.) Remove middle support
2.) For the given span CD of the beam using slope deflection method, which is true among the statements about the contribution of loadings to end moment MCD. rotation C = 0.01.
a.) application of the two concentrated loads (50 KN & 100 KN) results to higher MBC.
b.) settlement of 40 cm at support C and a load of 100 KN at the center of span BC results to higher MBC..
c.) no much difference on the MBC regardless of the two set of loadings.
d.) MBC should be less affected by settlement than changes in the external loadings.
3.) For the given span BC of the beam using slope deflection method, what is the correct slope deflection equation of end moment MBC. rotation C = 0.01.
a.) MBC = 0.004EI +267
b.) MBC =- 0.004EI +267
c.) MBC =- 0.01EI +225
d.) MBC = 0.01EI +225
Problem 4-7. Analyze the continuous beam using slope deflection method. EI = constant. Find the fixed moment MBC.
a) 4 KN-m
b.) 5 kN-m
c.) 6 KN-m
d.)7 KN-m
Problem 4-7. Analyze the continuous beam using slope deflection method. EI = constant.
5.) Find the slope deflection equation of member end CB.
a.) MCB =0.40 EI θCB – 5
b.) MCB =0.25 EI θCB + 5
c.) MCB =0.23 EI θCB - 5
d.) MCB =0.38 EI θCB + 5
Problem 4-7. Analyze the continuous beam using slope deflection method. EI = constant. 6.) What is EI θA?
a.)2.1
b.)2.7
c.)1.9
d.)1.5
Problem 4-7. Analyze the continuous beam using slope deflection method. EI = constant. 7.) What is the end moment BC?
a.) MBC =-5.4 KN-m
b.) MCB =-6.2 KN-m
c.) MCB =-3.9 kN-m
d.) MCB =-4.3 kN-m
Problem 8-10. Analyze the given frame using slope deflection method. 8.) What is the type of frame and sidesway degrees of freedom?
a.) sway frame; ss = 1
b.) non sway frame; ss = -1
c.) non sway frame; ss = 0
d.) sway frame; ss =2
Problem 8-10. Analyze the given frame using slope deflection method. 9.) What is rotation θB ?
a.) θB = 2.3/EI
b.) ΘB = 7.2/EI
c.) θB = 5.6/EI
d.) θB = 4.5/EI
Problem 8-10. Analyze the given frame using slope deflection method. 10.)Find moment at the fixed support A?
a.) MAB = -3.5 kN-m
b.) MAB = -1.5 kN-m
c.) MAB = -2.7 kN-m
d.) MAB = -1.0 kN-m
11.)What is the physical meaning of distribution factors in moment distribution method?
a.) It means that the external stress on a joint is distributed according to joint restraints.
b.) It means that the external stress on a joint is distributed according to sizes and type of material.
c.) It means that the external stress on a joint is distributed according to magnitude of fixed end moments produced.
d.) It means that the external stress on a joint is distributed according to the rigidity or flexibility of members.
Problem 12-16. Solve the problem on the continuous beam using moment distribution method. 12.) Find the distribution factor for member BC.
a.)DFBC = 0.5
b.) DFBC = 0.6
c.) DFBC = 0.3
d.) DFBC = 0.4
Problem 12-16. Solve the problem on the continuous beam using moment distribution method. 13.) Find the End moment MAB?
a.) MAB = 108.4 kN-m
b.) MAB = 98.1 kN-m
c.) MAB = 86.4 kN-m
d.) MAB = 58.2 kN-m
Problem 12-16. Solve the problem on the continuous beam using moment distribution method. 14.) Find the End moment MBC?
a.) MAB = 34.1 kN-m
b.) MAB = 83.4 kN-m
c.) MAB = 68.1 kN-m
d.) MAB = 75.8 kN-m
Problem 12-16. Solve the problem on the continuous beam using moment distribution method. 15.) What is the maximum shear stress (KN) in the beam based on the shear diagram?
a.) V = 28 KN
b.) V = 36 KN
c.)V = 43 KN
d.) V = 51 KN
Problem 12-16. Solve the problem on the continuous beam using moment distribution method. 16.) What is the maximum positive moment in the beam based on the moment diagram?
a.) M = 58.2 KN-m
b.) M = 34.8 KN-m
c.) M = 89 KN-m
d.) M = 104.1 KN-m
Problem 17-20. Using moment distribution analyze the given frame. E = 29,000 kips per square inch. Assume joint B is rigid, C is pinned and A is fixed. 17.) What is stiffness KBC?
a.) KBC = 0.45
b.) KBC = 0.60
c.) KBC = 0.75
d.) KBC = 0.35
Problem 17-21. Using moment distribution analyze the given frame. E = 29,000 kips per square inch. Assume joint B is rigid, C is pinned and A is fixed. 18.) Find the End moment MAB?
a.) MAB = - 3.6 k-ft
b.) MAB = - 7.8 k-ft
c.) MAB = - 2.3 k-ft
d.) MAB = - 4.1 k-ft
Problem 17-21. Using moment distribution analyze the given frame. E = 29,000 kips per square inch. Assume joint B is rigid, C is pinned and A is fixed. 19.) Find the End moment MBA?
a.) MBA = 32.6 k-ft
b.) MBA = 54.1 k-ft
c.) MBA = 10.9 k-ft
d.) MBA = 19.4 k-ft
Problem 17-21. Using moment distribution analyze the given frame. E = 29,000 kips per square inch. Assume joint B is rigid, C is pinned and A is fixed. 20.)What is the axial load in member BC?
a.) FBC = 3.1 kips
b.) FBC = 4.7 kips
c.) FBC = 2.8 kips
d.) FBC = 5.9 kips
