Free Printable Algebra 2 Unit 4B Review OL

Worksheets

Algebra 2 Unit 4B Review OL

Total questions: 20

Worksheet time: 29mins

Name

Class

Date

The quadratic equation k2 - 12k = -11 has two potential solutions. Use the X-method to factor the quadratic and find these two solutions.

k = 11

k = 1

k = -11

k = -1

k = 11

k = -1

k = -11

k = 1

Solve by factoring.

4x²+ 2x = 12

3(x - 4)(x + 1)

4(x + 2)(x - 3)

2(2x - 3)(x+2)

(2x - 6)(x + 2)

Solve the following quadratic using factoring.

x²= 81

x = 9

x = 0

x = 9i

x = 9 and

x = -9

There are no solutions

Solve using the quadratic formula.

2m² – 7m – 13 = -10

m = (7 ± $\sqrt[]{70}$ ) / 4

m = (7 ± $\sqrt[]{73}$ ) / 4

m = (7 ± $\sqrt[]{80}$ ) / 4

m = (7 ± $\sqrt[]{60}$ ) / 4

Solve using the quadratic formula.

a² – 7 = -2a

a = 1 ± 4 $\sqrt[]{2}$

a = -1 ± 2 $\sqrt[]{2}$

a = -2 ± $\sqrt[]{3}$

a = 3 ± $\sqrt[]{5}$

Mackenzie claims that the equation

y = x² + 8x - 33 does not have any real solutions. Is she correct?

No, Mackenzie is not correct; the equation has real solutions.

Yes, Mackenzie is correct; the equation has no real solutions.

Find the number and type of roots of each example below. All of the following have exactly two roots EXCEPT:

f(x) = (⅕)x² + 7x - 15

f(x) = (-⅓)x² + 9x + 18

f(x) = 3x² - 8x + 3

f(x) = x² - 14x + 49

Solve the equation 5h² + 3h + 3 = 0.

h = (3 ± i $\sqrt[]{25}$ ) / 10

h = (3 ± i $\sqrt[]{51}$ ) / 10

h = (-3 ± $\sqrt[]{51}$ ) / 10

h = (-3 ± i $\sqrt[]{51}$ ) / 10

Simplify.

(-2 - 5i) - (-8 + 8i)

-6 + 3i

4 + 5i

6 - 13i

-10 - 3i

10.

Simplify.

(8 - 4i)(2 - 6i)

-8 + 32i

-8 - 56i

16 - 24i

-16 + 12i

11.

Ricardo is converting the equation

0 = x² + 8x - 33 into (x + 4)² + k by completing the square.

What is the value of k?

-25

-16

-8

-49

12.

What are the roots of the following quadratic equation?

x² + 2x = 12

x = 1 + $\sqrt[]{13}$

x = 1 - $\sqrt[]{13}$

x = -1 + $\sqrt[]{13}$

x = -1 - $\sqrt[]{13}$

x = -2, x = 6

x = -6, x = 2

13.

Solve the equation:

x² + 47 = 23

x = 2 $\sqrt[]{6}$

x = -2√ $\sqrt[]{6}$

x = 23

x = ±2i $\sqrt[]{6}$

14.

Simplify.

(5 + 4i)²

1 + 8i

9 + 40i

10 + 20i

25 + 16i

15.

Simplify the radical.

$\sqrt[]{-117}$

3i $\sqrt[]{13}$

-i $\sqrt[]{117}$

$\sqrt[]{117}$

- $\sqrt[]{117}$

16.

Factor the following quadratic. You do not need to solve it.

45x²- 80

5(3x - 4)(3x + 4)

5(9x - 8)(9x + 8)

3(15x - 4)(15x + 4)

45(x - 4)(x + 4)

17.

Solve the equation using the quadratic formula.

8n² + 4n – 16 = -n²

n = (-2 ± 2 $\sqrt[]{37}$ ) / 9

n = (1 ± 2 $\sqrt[]{37}$ ) / 5

n = (-4 ± 3 $\sqrt[]{37}$ ) / 8

n = (2 ± $\sqrt[]{37}$ ) / 9

18.

What two numbers have a product of 12 and a sum of -8?

-3 & -4

-2 & -4

-6 & 2

-6 & -2

-10 & 2

19.

Solve the equation by factoring.

x = -16

x = -2, 4

x = -4

x = -4, 2

20.

Solve
x² + x - 20 = 0

x = -5 and 4

x = 4 and 5

x = 5 and -4

x = -4 and -5

Reset

Algebra 2 Unit 4B Review OL

Total questions: 20

Worksheet time: 29mins

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