WorksheetsGnav 501-550
Total questions: 50
Worksheet time: 25mins
Given: TAS: 150 kts Actual HDG: 270° Wind: 245/12 kts What is the wind correction angle?
4° to the left.
4° to the right.
2° to the right.
2° to the left.
The equivalent of 70 m/sec is approximately:
136 kts
145 kts
210 kts
35 kts
Given: True Heading: 180° TAS: 500 kts W/V: 225°/100 kts Calculate the GS.
600 kts
450 kts
535 kts
435 kts
Your pressure altitude is FL55, the QNH is 998, and the OAT is +30°C. What is density altitude?
6 980 feet.
7 750 feet.
8 620 feet.
10 020 feet.
An aircraft is flying at FL180 and the outside air temperature is -30°C. If the CAS is 150 kts, what is the TAS?
195 kts
115 kts
180 kts
145 kts
An aircraft is following a true track of 048° at a constant TAS of 210 kts. The wind velocity is 350°/30 kts. The GS and drift angle are:
200 kts, 3.5° right
192 kts, 7° left
192 kts, 7° right
225 kts, 7° left
The distance between A and B is 90 NM. At a distance of 75 NM from A the aircraft Is 4 NM right of course. The track angle error (TKE) is:
3°R
19°R
6°R
22°R
An aircraft at FL140, IAS 210 kts, OAT -5°C and wind component minus 35 kts, is required to reduce speed in order to cross a reporting point 5 min later than planned. Assuming that flight conditions do not change, when 150 NM from the reporting point the IAS should be reduced by:
25 kts
20 kts
30 kts
15 kts
An aircraft is descending from FL270 to FL100 following MT 054° and maintaining CAS 250 kts. Given are variation 13°E, temperatures ISA-10°C, W/V 020/60. What is your GS?
277 kts
265 kts
325 kts
298 kts
You are required to descend from FL230 to FL50 over a distance of 32 NM in 7 minutes. What is the required TAS when you expect a Wind Component (WC) of -25 kts during the descent?
317 kts
329 kts
308 kts
300 kts
True track from A to B is 167°, and the distance is 140 NM. Variation is 12°W at A and 14°W at B. Your flight-plan WCA 8°L. When the remaining distance to B is 35 NM you find that your position is 5 NM right of the flight plan track. Since over A you have steered as flight planned. What change of heading is required at this time to bring you directly to B?
3° left.
8° left.
11° left.
14° left.
An aircraft is departing from an airport which has an elevation of 2000 ft and the QNH is 1003 hPa. The TAS Is 100 kts, the head wind component is 20 kts and the rate of climb is 1 000 ft/min. Top of climb is FL100. At what distance from the airport will this be achieved?
10.3 NM
11.1 NM
15.4 NM
13.3 NM
An aircraft is departing from an airport which has an elevation of 2000 ft and the QNH is 1003 hPa. The TAS is 100 kts, the head wind component is 20 kts and the rate of climb is 1000 ft/min. Top of climb is FL050. At what distance from the airport will this be achieved?
4.0 NM
3.6 NM
44 NM
54 NM
You are departing from an airport which has an elevation of 2000 ft. The QNH is 1013 hPa. 10 NM away there is a waypoint you are required to pass at an altitude of 7 500 ft. Given a groundspeed of 100 kts, what is the minimum rate of climb?
1 080 ft/min
750 ft/min
590 ft/mins
920 ft/min
An aircraft at FL350 is required to commence descent when 85 NM from a VOR and to cross the VOR at FL80. The mean GS for the descent is 340 kts. What is the minimum rate of descent required?
1 900 ft/min.
1 800 ft/min.
1 600 ft/min.
1 700 ft/min.
You are on ILS 3° glideslope which passes over the runway threshold at 50 feet. Your DME range is 25 NM from the threshold. What is your height above the runway threshold elevation? (Use the 1 in 60 rule and 6000 ft = 1 NM)
8 010 feet.
7 450 feet.
6 450 feet.
7 550 feet.
You are departing from an airport which has an elevation of 1 500 ft. The QNH is 1003 hPa. 15 NM away there is a waypoint you are required to pass at an altitude of 7 500 ft. Given a groundspeed of 120 kts, what is the minimum rate of climb?
800 ft/min
730 ft/min
870 ft/min
530 ft/min
Given: TAS: 197 kts True course: 240° W/V: 180/30 kts Descent is initiated at FL220 and completed at FL40. Distance to be covered during descent is 39 NM. What is the approximate rate of descent?
800 ft/min
1 400 ft/min
950ft/min
1 500 ft/min
Distance from A to B is 120 NM. After 30 NM aircraft is 3 NM to the left of course. What heading alteration should be made in order to arrive at point B?
8° left.
6° right.
4° right.
8° right.
An aircraft follows a coastline during a particular time. This coastline is:
a speedline.
a line of position.
a VFR line.
an unknown line of position.
Due to pressurization problems you request to descent from FL120 down to FL50, with 1 000 ft/min only, and maintaining a CAS of 200 kts. What descent profile will you follow at no wind conditions and standard temperature?
2°
2,5°
3°
1.5°
The distance between A and B is 90 NM. At a distance of 15 NM from A the aircraft is 4 NM right of course. To reach destination B, the correction angle on the heading should be:
16°
3°
21°
19°
You are required to descend from FL230 to FL50 over a distance of 32 NM in 7 minutes. What is the required rate of descent when you expect WC -25 during the descent?
2 157 ft/min.
2 230 ft/min.
2 458 ft/min.
2 570 ft/min.
An island appears 30° to the left of the centre line on an airborne weather radar display. What is the true bearing of the aircraft from the island if at the time of observation the aircraft was on a magnetic heading (MH) of 020° with the magnetic variation (VAR) 25°W?
145°
195°
205°
325°
Assuming zero wind, what distance will be covered by an aircraft descending 15 000 ft with a TAS of 320 kts and maintaining a rate of descent of 3 000 ft/min?
26.7 NM
19.2 NM
38.4 NM
160 NM
An aircraft at FL120, IAS 200 kts, OAT -5° and wind component +30 kts, is required to reduce speed in order to cross a reporting point 5 min later than planned. Assuming flight conditions do not change, when 100 NM from the reporting point lAS should be reduced to:
169 kts
165 kts
159 kts
174 kts
The distance between two waypoints is 200 NM. To calculate compass heading, the pilot used 2°E magnetic variation instead of 2°W. Assuming that the forecast W/V applied, what will the off track distance be at the second waypoint?
0 NM
7 NM
14 NM
21 NM
Given: An aircraft is flying a track of 255°(M). At 2254 UTC, it crosses radial 360° from a VOR station. At 2300 UTC, it crosses radial 330° from the same station. At 2300 UTC, the distance between the aircraft and the station is:
the same as it was at 2254 UTC.
greater than it was at 2254 UTC.
randomly different than it was at 2254 UTC.
less than it was at 2254 UTC.
An aircraft at FL390 is required to descend to cross a DME facility at FL70. Maximum rate of descent is 2500 ft/min, mean GS during descent is 248 kts. What is the minimum range from the DME at which descent should commence?
53 NM
58 NM
63 NM
68 NM
An aircraft is flying from A to B a distance of 50 NM. The True course in the flight log is 090°, the forecast wind is 225° (T) /15 kts and the TAS is 120 kts. After 15 minutes of flying with the planned TAS and TH the aircraft is 3 NM South of the intended track and 2.5 NM ahead of the dead reckoning position. To reach destination B from this position, the correction angle on the heading should be:
5°
10°
12°
17°
A ground feature was observed on a relative bearing of 315° and 3 min later on a relative bearing of 270°. The W/V is calm; aircraft GS 180 kts. What is the minimum distance between the aircraft and the ground feature?
3 NM
12 NM
9 NM
6 NM
The True course in the flight log is 270°, the forecast wind Is 045° m / 15kts and the TAS is 120 kts. After 15 minutes of flying with the planned TAS and TH the aircraft is 3 NM South of the intended track and 2.5 NM ahead of the dead reckoning position. The track angle error (TKE) Is:
5°L
2°L
3°R
6°R
An island appears 30° to the right of the centre line on an airborne weather radar display. What is the true bearing of the aircraft from the island if at the time of observation the aircraft was on a magnetic heading (MH) of 355° with the magnetic variation (VAR) 15°E?
160°
130°
220°
190°
An aircraft is planned to fly from position A to position B, distance 320 NM, at an average GS of 180 kts. It departs A at 12:00 UTC. After flying 70 NM along track from A, the aircraft is 3 min ahead of planned time. Using the actual GS experienced, what is the revised ETA at B?
1401 UTC
1333 UTC
1347 UTC
1340 UTC
An island is observed to be 30° to the right of the nose of the aircraft. The aircraft heading is 290° (M), variation 10°E. The bearing from the aircraft to the island is:
330° (T)
270° (T)
250° (T)
310° (T)
An aircraft obtains a relative bearing of 315° from an NDB at 08:30. At 08:40 the relative bearing from the same position is 270°. Assuming no drift and a GS of 240 kts, what is the approximate range from the NDB at 08:40?
50 NM
40 NM
60 NM
30 NM
A pilot receives the following signals from a VOR DME station: Radial: 180° +/- 1° Distance: 200 NM What is the approximate error?
±3.5 NM
±1NM
±2NM
±7NM
An aircraft at FL370 is required to commence descent when 100 NM from a DME facility and to cross the station at FL120. If the mean GS during the descent is 396 kts, the minimum rate of descent required is approximately:
1 650 ft/min.
2 400 ft/min.
1 000 ft/min.
1 550 ft/min.
To establish a track plot you need:
the last position, air position and DR position.
the last position and the DR position.
at least two pinpoints or fixes.
the air position and a pinpoint or fix.
An aircraft at FL330 is required to commence descent when 65 NM from a VOR and to cross the VOR at FL100. The mean GS during the descent is 330 kts. What is the minimum rate of descent required?
1 950 ft/min.
1 650 ft/min.
1 750 ft/min.
1 850 ft/min.
An island appears 60° to the left of the centre line on an airborne weather radar display. What is the true bearing of the aircraft from the island if at the time of observation the aircraft was on a magnetic heading (MH) of 276° with the magnetic variation (VAR) 10°E?
046°
086°
226°
026°
An aircraft at FL350 is required to descend to cross a DME facility at FL80. Maximum rate of descent is 1 800 ft/min and mean GS for descent is 276 kts. The minimum range from the DME at which descent should start is:
79 NM
69 NM
49 NM
59 NM
Given: Distance A to B: 475 NM Planned GS: 315 kt AID: 1000 UTC 1040 UTC - fix obtained 190 NM along track. What GS must be maintained from the fix in order to achieve planned ETA at B?
300 kt
340 kt
360 kt.
320 kt.
An aircraft is planned to fly from position A to position B, distance 480 NM at an average GS of 240 kts. It departs A at 10:00 UTC. After flying 150 NM along track from A, the aircraft is 2 min behind planned time. Using the actual GS experienced, what is the revised ETA at B?
1203
1206
1153
1157
The relative bearing to a beacon is 270°R. Three minutes later, at a ground speed of 180 knots, it has changed to 225°R. What was the distance of the closest point of approach of the aircraft to the beacon?
45 NM
18 NM
9 NM
3 NM
Transferring position lines can be done with:
radials and QDM/QDR only.
QDM/QDR and QTE only.
radials and DME only.
radials, DME, QDM/QDR
What is the average TAS climbing from 2000 ft up to FL120 at standard temperatures, given a CAS 185 kts and QNH 1013?
188 kts
197 kts
210 kts
221 kts
An island is observed by weather radar to be 15° to the left. The aircraft heading is 120°(M) and the magnetic variation 17°W. What is the true bearing of the aircraft from the island?
122° (T)
302°(T)
088° (T)
268° (T)
An island appears 45° to the right of the centre line on an airborne weather radar display. What is the true bearing of the aircraft from the island if at the time of observation the aircraft was on a magnetic heading (MH) of 215° with the magnetic variation (VAR) 21°W?
101°
059°
239°
329°
Transferring position lines (LOP): An aircraft should follow a true course 120°, given TAS 100 kts and W/V 360/50. It obtains position lines at 14:00, 14:03, 14:06 hours.
1 LOP is transferred by 8.0 NM, 1 LOP by 4.0 NM, the third one is not transferred.
1 LOP is transferred by 10.0 NM, 1 LOP by 5.0 NM, the third one is not transferred.
1 LOP is transferred by 12.5 NM, 1 LOP by 6.25 NM, the third one is not transferred.
1 LOP is transferred by 11.6 NM, 1 LOP by 5.8 NM, the third one is not transferred.
