$$f'\left(x\right)=\ln x$$

$$f'\left(x\right)=-\frac{1}{x^2}$$

$$f'\left(x\right)=0$$

$$f'\left(x\right)=-2x$$

$$f'\left(x\right)=5+\frac{1}{x}$$

$$f'\left(x\right)=5+\frac{1}{\sqrt{x}}$$

$$f'\left(x\right)=\frac{1}{\sqrt{x}}$$

$$f'\left(x\right)=5+\frac{1}{2\sqrt{x\ }}$$

$$f'\left(x\right)=\frac{1}{2\text{lnx}\ }-\frac{1}{3\ln x}$$

$$f'\left(x\right)=\frac{1}{\ln2\ }-\frac{1}{\ln3}$$

$$f'\left(x\right)=\frac{1}{x\ln2}-\frac{1}{x\ln3}$$

$$f'\left(x\right)=\frac{2}{x}$$

$$2^x\ln2+3^x\ln3-1$$

$$x\ln2+x\ln3-1$$

$$x\cdot\ 2^{x-1}+x\cdot\ 3^{x-1}-1$$

$$f'\left(x\right)=2^x+3^x$$

$$2\cos x-3\sin x$$

$$2\cos x+3\sin x$$

$$2\sin x-3\cos x$$

$$-2\cos x+3\sin x$$

$$2x+16$$

$$x+8$$

$$2x+8$$

$$x+4$$

$$f'(x)=\frac{1}{\left(x-3\right)^{2\ }}$$

$$f'\left(x\right)=\frac{5}{x-3}$$

1

$$f'\left(x\right)=\frac{-5}{\left(x-3\right)^2}$$

$$e^x\left(2-x\right)$$

$$e^x\left(x-2\right)$$

$$e^x\left(x-4\right)$$

$$e^x\left(4-x\right)$$

DAA

NUU