If N = 5, which corresponds to pentane, what is the molecular formula of pentane?

Balance the following combustion reaction:

C₆H₁₄+O₂→CO₂+H₂O

Calculate the molar mass of hexane (C₆H₁₄)

Molar mass:

• Carbon (C) = 12.01 g/mol

• Hydrogen (H) = 1.008 g/mol

Convert 100 g of hexane (C₆H₁₄) to moles.
(Molar mass of hexane = 86.17 g/mol)

Using the balanced equation you balanced before:

2 C₆H₁₄ + 19 O₂ → 12 CO₂ + 14 H₂O

How many moles of oxygen (O₂) are required to burn 1.16 moles of hexane (C₆H₁₄)?

Convert 11.03 moles of oxygen (O₂) to grams. The molar mass of O₂ is 32.00 g/mol.

Using the previously calculated 11.03 moles of O₂, how many liters of oxygen gas (O₂) is required to burn 100g of hexane (C₆H₁₄) at standard temperature and pressure (STP)?
(1 mole of gas = 22.4 L at STP)

 If the volume of oxygen (O₂) required to burn 100g of hexane is 247.0 L, and assuming air is 21% oxygen and , how many liters of air are needed?

Knowing that 100g of hexane (C₆H₁₄) represents 1.16 moles of hexane, how many moles of CO₂ are produced by burning 1.16 moles of hexane?

Convert 7 moles of CO₂ to volume at STP (0°C, 1 atm, 1 mole of gas = 22.4 L)