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eoc

Total questions: 12

Worksheet time: 3hrs 0mins

Name
Class
Date
1.

In the figure XV is the missives of trapezoid RSTU if RSU=30 and XV=44 what is TU?

a)

A.32

b)

B.58

c)

C.74

d)

D.11

2.

Quadrilateral LMNO has vertices at L(8, 4), M(4, 10), N(-4, 6), and O(0, 0).

Is LMNO a square? Justify your answer.

a)

GYes, all sides are congruent, and LM and MN are perpendicular.

b)

GYes, all sides are congruent, and LM and NO are parallel.

c)

No, LM and NO are not parallel.

d)

No, LM and NO are not Congurent

3.

You and X are midpoints of the legs VZ and WY of. Trapezoid VWYZ. What is S?

a)

1

b)

6

c)

7

d)

11

4.

Surface area is…..?

a)

15386

b)

14678

c)

15387

d)

15368

5.

Which of the following is a counterexample for this conditional statement?

T

If a rectangle has a perimeter of 20, then its area is 24.

a)

人

a rectangle with sides measuring 10 and 2

b)

a rectangle with sides measuring 5 and 6

c)

a rectangle with sides measuring 4 and 6

d)

a rectangle with sides measuring 8 and 2

6.

These figures are congruent. What is mLP?

a)

77

b)

95

c)

53

d)

76

7.

What is the surface area of this rectangular pyramid?

a)

732

b)

765

c)

63456

d)

731

8.

What is the shape doing

a)

1

b)

2

c)

3

d)

4

9.

What is the scale factor

a)

1/4

b)

6

c)

4

d)

1/6

10.

What is the translation

a)

(X+4,y+3)

b)

(X+4,y+2)

c)

(X+3,y+4)

d)

(X-3,y-4)

11.

Is EFGH congruent to PQRS? Justify your answer.

a)

Yes, because a rotation 180° around H followed by a reflection across the line

y = x maps EFGH onto PQRS.

b)

Yes, because a rotation 90° clockwise around the origin followed by a translation left 1 unit and down 10 units maps EFGH onto PQRS.

c)

No, because LH and LS do not have the same measure.

d)

No, because EF and PQ do not have the same length.

12.

Quadrilateral CDEF is an isosceles trapezoid and m LF = t + 46º. What is the value of t?

a)

46

b)

91

c)

90

d)

It’s the same