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WorksheetsDLD Assessment 1
Total questions: 50
Worksheet time: 26mins
If the decimal number is a fraction then its binary equivalent is obtained by ________ the number continuously by 2.
Dividing
Subtracting
Multiplying
Adding
The representation of octal number (532.2)8 in decimal is ________
(346.25)10
(340.67)10
(532.864)10
(531.668)10
The decimal equivalent of the binary number (1011.011)2 is ________
(11.175)10
(9.23)10
(10.123)10
(11.375)10
An important drawback of binary system is ________
It requires large string of 1’s and small string of 0’s to represent a decimal number
It requires sparingly small string of 1’s and 0’s to represent a decimal number
It requires small string of 1’s and large string of 0’s to represent a decimal number
It requires very large string of 1’s and 0’s to represent a decimal number
The decimal equivalent of the octal number (645)8 is ______
(501)10
(451)10
(450)10
(421)10
The largest two digit hexadecimal number is ________
(FF)16
(EF)16
(FD)16
(FE)16
The octal equivalent of the decimal number (417)10 is _____
(598)8
(619)8
(640)8
(641)8
Convert the hexadecimal number (1E2)16 to decimal.
482
484
480
483
Convert (0.345)10 into an octal number.
(0.16050)8
(0.24040)8
(0.19450)8
(0.26050)8
Convert binary to octal: (110110001010)2 =?
(4532)8
(5512)8
(6745)8
(6612)8
The given hexadecimal number (1E.53)16 is equivalent to ____________
(36.246)8
(35.599)8
(34.340)8
(35.684)8
Binary subtraction of 101101 – 001011 = ?
100010
010110
110101
101100
On multiplication of (10.10) and (01.01), we get ____________
0010.101
101.0010
110.0011
011.0010
What is the addition of the binary numbers 11011011010 and 010100101?
0111001000
11101111111
10011010011
1100110110
Any signed negative binary number is recognised by its ________
Byte
Nibble
MSB
LSB
1’s complement of 1011101 is ____________
1100101
0100010
0101110
1001101
2’s complement of 11001011 is ________
01010111
11010100
11100010
00110101
On subtracting (01010)2 from (11110)2 using 1’s complement, we get ____________
10101
11010
01001
10100
On subtracting (101011)2 from (111001)2 using 2’s complement, we get ____________
1101100
0011100
11010111
11010101
1’s complement can be easily obtained by using _________
Comparator
Adder
Inverter
Subtractor
The advantage of 2’s complement system is that _________
Only one arithmetic operation is required
Two arithmetic operations are required
No arithmetic operations are required
Different Arithmetic operations are required
Binary coded decimal is a combination of __________
Four binary digits
Six binary digits
Three binary digits
Two binary digits
The decimal number 10 is represented in its BCD form as __________
00010000
01010111
10100000
00101011
Add the two BCD numbers: 1001 + 0100 = ?
10101111
00010011
01010000
00101011
Carry out BCD subtraction for (68) – (61)
011111000
00000111
01110000
100000111
When numbers, letters or words are represented by a special group of symbols, this process is called __________
Digitizing
Inverting
Encoding
Decoding
A three digit decimal number requires ________ for representation in the conventional BCD format.
6 bits
12 bits
24 bits
3 bits
How many bits would be required to encode decimal numbers 0 to 9999 in straight binary codes?
16
14
12
18
The excess-3 code for 597 is given by __________
100011001010
010110101101
010110010111
100010100111
The output of a logic gate is 1 when all the input are at logic 0
An OR or an EX-NOR
An AND or an EX-OR
A NAND or an EX-OR
A NOR or an EX-NOR
The code where all successive numbers differ from their preceding number by single bit is __________
BCD
Alphanumeric Code
Excess 3
Gray
How many AND gates are required to realize Y = CD + EF + G?
2
4
5
3
How many two-input AND and OR gates are required to realize Y = CD+EF+G?
3, 2
2, 2
2, 3
3, 3
How many truth table entries are necessary for a four-input circuit?
4
8
16
12
If we use an AND gate to inhibit(stop) a signal from passing one of the inputs must be ___________
LOW
HIGH
Floating
Inverted
The expression for Absorption law is given by _________
A + AB = A
A + AB = B
AB + AA’ = A
A + B = B + A
A(A + B) = ?
AB
1
1+AB
A
Complement of the expression A’B + CD’ is _________
(A’ + B)(C’ + D)
(A + B’)(C’ + D)
(A’ + B)(C’ + D)
(A + B’)(C + D’)
DeMorgan’s theorem states that _________
(AB)’ = A’ + B
(A + B)’ = A’B
A’ + B’ = A’B’
(AB)’ = A’ + B'
Simplify Y = AB’ + (A’ + B)C
AB’ + C
AB + AC
A’B + AC’
AB + A
According to boolean law: A + 1 = ?
1
A
0
A'
The expression Y=AB+BC+AC shows the _________ operation.
EX-OR
SOP
POS
NOR
The canonical sum of product form of the function y(A,B) = A + B is __________
AB + BB + A’A
AB + AB’ + A’B
BA + BA’ + A’B’
AB’ + A’B + A’B’
There are _____________ Minterms for 3 variables (a, b, c).
0
2
8
1
There are ______ cells in a 4-variable K-map.
12
16
18
8
The prime implicant which has at least one element that is not present in any other implicant is known as ___________
Essential Prime Implicant
Implicant
Complement
Prime Complement
In a combinational circuit, the output at any time depends only on the _______ at that time.
Voltage
Intermediate values
Input values
Clock pulses
If A and B are the inputs of a half adder, the sum is given by __________
A AND B
A OR B
A XOR B
A EX-NOR B
The difference between half adder and full adder is __________
Half adder has two inputs while full adder has four inputs
Half adder has one output while full adder has two outputs
Half adder has two inputs while full adder has three inputs
All of the Mentioned
How many AND, OR and EXOR gates are required for the configuration of full adder?
1, 2, 2
2, 1, 2
3, 1, 2
4, 0, 1
