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WorksheetsExploring P Block Elements, Group 15,16
Total questions: 35
Worksheet time: 22mins
What is the significance of the P block in the periodic table?
The P block is primarily made up of radioactive elements.
The P block is significant for its diverse elements that are essential for life, chemical bonding, and various industrial applications.
The P block contains only metals that are not used in industry.
The P block is significant for its role in nuclear reactions.
Which P block element is essential for life?
Phosphorus
Arsenic
Boron
Silicon
What is the trend in electronegativity across the P block?
Electronegativity increases down the P block.
Electronegativity increases across the P block from left to right.
Electronegativity decreases across the P block from left to right.
Electronegativity remains constant across the P block.
What are the common uses of phosphorus, a P block element?
Phosphorus is primarily used in electronics manufacturing.
Common uses of phosphorus include fertilizers, food additives, safety matches, and chemical manufacturing.
Phosphorus is a key ingredient in cosmetics.
Phosphorus is mainly used for water purification.
Explain the concept of hybridization in P block elements.
Hybridization in P block elements is the mixing of atomic orbitals to create new hybrid orbitals for bonding.
Hybridization in P block elements involves the loss of electrons during bonding.
P block elements do not undergo hybridization in their bonding processes.
Hybridization is only applicable to S block elements and not to P block elements.
How do P block elements differ from S block elements?
P block elements differ from S block elements in their electron configuration and chemical properties.
P block elements have more protons than S block elements.
S block elements are always metals, while P block elements are always non-metals.
P block elements are found only in the first two periods of the periodic table.
An element ‘A’ belongs to the third period and group 16 of the Periodic Table. Find out the valency of A.
(a) Valency = 6
(b) Valency = 2
(c) Valency = 1
(d) Valency = 3
Choose the correct statements about the hydrides of group 15 elements.
A. The stability of the hydrides decreases in the order NH, PH > AsH > SbH > Він
B. The reducing ability of the hydrides increases in the order NH, PH₁ < AsH₁ < SbH < BiH,
C. Among the hydrides, NH, is strong reducing agent while BiH, is mild reducing agent.
D. The basicity of the hydrides increases in the order NH, PH, <ASH, <SbH, < BiH,
Choose the most appropriate from the option given below:
B and C only
C and D only
A and B only
A and D only
The most stable trihalide of nitrogen is
NF3
NCl3
NBr3
NI3
PCl5 is well known but NCl5 is not.because,
Nitrogen is less reactive than phosphorus
Nitrogen doesn't have d-orbital in its valance shell
Catenation tendency is weaker in Nitrogen than phosphorus
Size of phosphorus is larger than Nitrogen
A group 15 element, which is a metal and forms a hydride with strongest reducing power among group 15 hydrides. The element is
Sb
P
As
Bi
Which of the following is not a pseudohalogen?
(CN)2
(OCN)2
(SCN)2
(NO2)2
The oxidation states of sulphur in Caro's acid and Marshall's acid are respectively
+5 and +6
+4 and +6
+6 and +6
+5 and +5
The shapes of SO2 and SO3 are respectively
Linear and Trigonal planar
Angular and Trigonal planar
Linear and T shape
Angular and T shape
The Oxidation states of central sulphur atom and terminal sulphur atom in Thiosulphuric acid are respectively
+4 and +2
+6 and +2
+5 and -2
+6 and -2
No. of σ bonds and π bond in H2SO4 are respectively
6 and 4
6 and 2
4 and 6
2 and 6
On addition of conc. H2SO4 to a chloride salt, colourless fumes are evolved
but in case of iodide salt, violet fumes come out. This is because
(i) H2SO4 reduces HI to I2
(ii) HI is of violet colour
(iii) HI gets oxidised to I2
(iv) HI changes to HIO3
In qualitative analysis when H2S is passed through an aqueous solution of
salt acidified with dil. HCl, a black precipitate is obtained. On boiling the
precipitate with dil. HNO3, it forms a solution of blue colour. Addition of excess
of aqueous solution of ammonia to this solution gives _________.
(i) deep blue precipitate of Cu (OH)2
(ii) deep blue solution of [Cu (NH3)4]2+
(iii) deep blue solution of Cu(NO3)2
(iv) deep blue solution of Cu(OH)2.Cu(NO3)2
On heating lead nitrate forms oxides of nitrogen and lead. The oxides formed are ______.
(i) N2O, PbO
(ii) NO2, PbO
(iii) NO, PbO
(iv) NO, PbO2
Which of the following statements is wrong?
(i) Single N–N bond is stronger than the single P–P bond.
ii) PH3 can act as a ligand in the formation of coordination compound with transition elements.
(iii) NO2 is paramagnetic in nature.
(iv) Covalency of nitrogen in N2O5 is four.
Which of the following are peroxoacids of sulphur?
(i) H2SO5 and H2S2O8
(ii) H2SO5 and H2S2O7
(iii) H2S2O7 and H2S2O8
(iv) H2S2O6 and H2S2O7
Which of the following elements can be involved in pπ–dπ bonding?
Carbon
Nitrogen
Phosphorus
Boron
2NH3 + NaOCl
N2H4 + NaCl + 2H2O
N2H6 + NaCl + H2O
N2H4 + NaCl + H2O
N2H6 + NaCl + 2H2O
In group 15 elements as we move down the group
Non metallic character increase
Metallic character increase
Both
None the above
Maximum covalency of nitrogen is
6
8
9
4
Sulphur in the vapour state is diamagnetic.
True
False
Ammonia is a Lewis base and act as complexing agent.
It accepts electron pair
It is neither electron pair donar or acceptor
It act as electron pair donar.
It exhibit covalency more than five
Nitrogen cannot exhibit co valancy more than four due to
Presence of vacant d orbitals
Due to large size
Due to absence of vacant d orbitals
Due to inert nature
Nitric oxide is para magnetic
(a)
Among the hydrides of 15th group , which is strong reducing agent?
Ammonia
Phosphine
Arsine
Bismuthine
Ammonia is liquid phosphene gas . Why?
Due to more molar mass ammonia has maximum vanderwall force of attraction
Due to more molar mass , ammonia has less vander wall force of attraction
Due to presence of inter molecular hydrogen bonding in ammonia
Due to absence of hydrogen bonding in ammonia
Assertion : N2 is less reactive than P4.
Reason : Nitrogen has more electron gain enthalpy than phosphorus
Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion.
Assertion is correct, but reason is wrong statement.
Assertion is wrong but reason is correct statement.
Both assertion and reason are wrong statement
SF6 is known but SCl6 is not________
Due to small size of fluorine six F – ion can be accomodated around sulphur whereas chloride ion is comparatively larger in size, therefore, there will be interionic repulsion
Due to absence of vacant d orbital
Chlorine have more electron gain enthalpy than
none of these
A brown ring is formed in the ring test for NO3– ion. It is due to the formation of
[Fe(H2O)5 (NO)]2+
FeSO4.NO2
[Fe(H2O)4(NO)2]2+
FeSO4.HNO3
Nitrogen is chemically inert. Why?
Due to presence of double bond require more energy to break
Due to presence of triple bond require more energy to break
Triple bond requires less energy to break
None of the above
