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WorksheetsReal-World Applications: Dimensions of Boxes and Cylinders
Total questions: 150
Worksheet time: 4hrs 8mins
A rectangular box has length twice the width. The height is 2 inches greater than the width. The volume is 192 cubic inches. Find the dimensions (length × width × height) in inches.
A rectangular box has length, width, and height that are consecutive whole numbers. The volume is 120 cubic inches. Which set gives the correct dimensions in inches?
3, 4, 10
4, 5, 6
5, 6, 4
6, 5, 4
A rectangular box has length one inch more than the width, which is one inch more than the height. The volume is 86.625 cubic inches. What is the height in inches?
3.5
3.75
4
4.25
A rectangular box has length three times the height, and the height is one inch less than the width. The volume is 108 cubic inches. Find the width in inches.
3
4
5
6
A rectangular box has length 3 inches more than the width. The width is 2 inches more than the height. The volume is 120 cubic inches. Determine the dimensions in inches.
A right circular cylinder has radius 3 inches more than the height. The volume is 16π cubic inches. What is the height? Use V=πr2h .
1 inch
2 inches
3 inches
4 inches
A right circular cylinder has height one less than one half the radius. The volume is 72π cubic meters. Find the radius in meters. Use V=πr2h .
A right circular cylinder’s radius and height differ by one meter; the radius is larger. The volume is 48π cubic meters. Which ordered pair (r, h) in meters satisfies V = πr2h ?
(3, 2)
(4, 3)
(5, 4)
(6, 5)
A right circular cylinder’s radius and height differ by two meters, with the height greater than the radius. The volume is 28.125π cubic meters. Find the height in meters. Use V=πr2h .
3
3.75
4.5
5
A right circular cylinder has radius 1/3 meter greater than the height, and volume 98/9 π cubic meters. Find the dimensions.
Average cost function for producing x items is f(x) = (15,000x−0.1x2+1000)/x . Which expression simplifies f(x) correctly for x > 0?
f(x) = 15,000 − 0.1x + 1000x
f(x) = 15,000 − 0.1x + 1000/x
f(x)=15,000x−0.1x2+1000
f(x) = (15,000 − 0.1x)/x + 1000
Explain why the function f(x)=x15,000x−0.1x2+1000 is a rational function and identify one practical context mentioned for such functions.
Which statement best defines a rational function in this section’s context?
A function with only non-negative integer exponents
A function that has variables in the denominator
A function composed of only linear terms
A function whose graph is always a straight line
The average cost function for producing x items is given by f(x) = (15,000x−0.1x2+1000)/x . What is a direct implication of the variable x being in the denominator?
The function is a polynomial and defined for all real numbers
The function is rational and is undefined at x = 0
The function has no asymptotic behavior
The function’s output cannot change sign
Consider the reciprocal function f(x) = 1/x. Based on the description provided, which statement about its local behavior near x = 0 is correct?
As x approaches 0 from the left, f(x) approaches positive infinity
As x approaches 0 from the right, f(x) approaches negative infinity
As x approaches 0 from the left, f(x) approaches negative infinity
As x approaches 0 from either side, f(x) remains finite
Arrow notation summarizes limits and asymptotic behavior. Match the symbol to its meaning: x→a+ , x→a− , f(x)→∞ , f(x)→a .
Approaches a from the left; approaches a from the right; output approaches infinity; output approaches a
Approaches a from the right; approaches a from the left; output approaches a; output approaches infinity
Approaches infinity; approaches negative infinity; output approaches a; output approaches infinity
Approaches a from the left; approaches infinity; output approaches a; output approaches negative infinity
Using arrow notation and the given observations, which statement about f(x) = 1/x is correct?
x → 0^+ implies f(x)→−∞
x → 0^− implies f(x)→+∞
x → ∞ implies f(x) → 0
x → −∞ implies f(x) → +∞
BLANK: Write the arrow notation that describes the right-hand end behavior of f(x) = 1/x.
(a)
OPEN: Explain why x = 0 is not in the domain of f(x) = 1/x using the section’s reasoning, and describe what happens to f(x) as x approaches 0 from the left.
Consider the reciprocal function f(x) = 1/x. Using the local behavior near x = 0 shown, which statement correctly describes the function values as x approaches 0 from the left?
f(x) approaches 0 from below
f(x) approaches 0 from above
f(x) decreases without bound to −∞
f(x) increases without bound to +∞
For f(x) = 1/x, what happens to f(x) as x approaches 0 from the right? Use the observed values 0.1, 0.01, 0.001, 0.0001.
f(x) approaches 0
f(x) approaches −∞
f(x) approaches +∞
f(x) oscillates between positive and negative values
Which statement best describes the end behavior of f(x) = 1/x as x → ±∞, based on the plotted graph?
As x → ±∞, f(x) → 0
As x → ±∞, f(x) → ±∞
As x → ±∞, f(x) → 1
As x → ±∞, f(x) oscillates without approaching a value
A vertical asymptote of a graph is defined as a vertical line x = a where the graph tends toward positive or negative infinity as x approaches a from either side. Which notation captures this behavior?
As x → a, f(x) → 0
As x → a, f(x) → L
As x → a−, f(x) → ±∞ or x → a+, f(x) → ±∞
As x → ±∞, f(x) → L
Explain why y = 0 is a horizontal asymptote for f(x) = 1/x. Support your explanation with arrow notation and the graph’s end behavior.
Using the arrow notation for f(x) = 1/x, select the correct pair describing behavior near x = 0 and for large |x|.
As x → 0±, f(x) → 0; as x → ±∞, f(x) → ±∞
As x → 0±, f(x) → ±∞; as x → ±∞, f(x) → 0
As x → 0±, f(x) → 1; as x → ±∞, f(x) → 1
As x → 0±, f(x) oscillates; as x → ±∞, f(x) oscillates
Define a horizontal asymptote using the formal description provided and choose the expression that correctly uses arrow notation for a function with horizontal asymptote y = b.
A horizontal asymptote is a vertical line x = b where f(x) → b as x → ±∞
A horizontal asymptote is a horizontal line y = b where f(x) → b as x → ±∞
A horizontal asymptote is a slanted line y = mx + b approached as x → 0±
A horizontal asymptote is any line the graph never crosses
The graph in Figure 6 shows a vertical dashed line at x = 2 and a horizontal dashed line at y = 4. Use arrow notation to state the local behavior near the vertical asymptote.
As x → 2−, f(x) → −∞ and as x → 2+, f(x) → ∞
As x → 2−, f(x) → ∞ and as x → 2+, f(x) → −∞
As x → 2−, f(x) → 4 and as x → 2+, f(x) → 4
As x → 2, f(x) → 0
For the function graphed in Figure 6, identify the horizontal asymptote and write the end behavior using arrow notation.
Horizontal asymptote y = 4; As x → ±∞, f(x) → 4
Horizontal asymptote y = 2; As x → ±∞, f(x) → 2
Horizontal asymptote x = 4; As x → ±∞, f(x) → 0
No horizontal asymptote; As x → ±∞, f(x) → ±∞
A reciprocal function is shifted left 2 units and up 3 units, producing f(x) = 1/(x+2) + 3. Identify its vertical asymptote.
(a)
For the function f(x) = 1/(x+2) + 3, choose the correct end behavior statement.
As x → ±∞, f(x) → 0
As x → ±∞, f(x) → 3
As x → ±∞, f(x) → −∞
As x → ±∞, f(x) → ∞
The transformed rational function in Example 2 can be written equivalently as f(x) = (3x + 7)/(x + 2). Which statement about its asymptotes matches the analysis?
Vertical asymptote at x = 2 and horizontal asymptote at y = −3
Vertical asymptote at x = −2 and horizontal asymptote at y = 3
Vertical asymptote at x = −7/3 and horizontal asymptote at y = 0
No vertical asymptote and horizontal asymptote at y = 7/3
A rational function is defined as a function that can be written as the quotient of two polynomials. Select the option that best matches this definition.
A function expressed as the sum of two polynomials
A function expressed as the product of two polynomials
A function expressed as the quotient of two polynomials
A function expressed as the composition of two polynomials
Recall the definition: A rational function is any function that can be written as the quotient of two polynomials P(x) and Q(x) with Q(x) ≠ 0. Which expression represents a rational function?
f(x)=3x
f(x)=(x3+4)(2x2−5x+1)
f(x) = √(x + 7)
f(x) = |x| + 1
A tank initially contains 100 gallons of water and 5 pounds of sugar. Beginning at t = 0 minutes, water flows in at 10 gallons per minute and sugar is added at 1 pound per minute. The concentration in pounds of sugar per gallon is modeled by C(t) = (5 + t)/(100 + 10t). Compute the concentration after 12 minutes and decide whether it is greater than at the beginning. Show your reasoning.
Given the concentration model C(t) = (5 + t)/(100 + 10t), identify the horizontal asymptote of C(t) and interpret it in context.
y = 0, meaning the concentration approaches zero as time increases
y = 0.1, meaning the ratio of pounds of sugar to gallons of water approaches 0.1 in the long term
y = 1, meaning the concentration approaches one pound per gallon as time increases
y = 10, meaning the concentration approaches 10 pounds per gallon as time increases
Recall the rule for determining the domain of a rational function. Which statement correctly describes the domain?
All real numbers with no exceptions
All real numbers except those that make the denominator equal zero
Only positive real numbers
All real numbers except those that make the numerator equal zero
Use the step-by-step method to find the domain of f(x) = (x+3)/(x2−9) . First, set the denominator equal to zero and solve. Then state the domain based on these values.
Consider the graph of the rational function f(x) = (x+3)/(x2−9) . Based on the domain analysis, which feature appears at x = 3?
A vertical asymptote
A horizontal asymptote
A removable discontinuity (hole)
A local maximum
Given k(x) = (5+x2)/(2−x−x2) , factor the denominator and determine the x-values of the vertical asymptotes.
(a)
Consider the simplified form of k(x) = (5+x2)/(2−x−x2) after factoring the denominator as (2+x)(1−x) . Explain why x=−2 and x=1 are vertical asymptotes rather than removable discontinuities.
For f(x) = x2−1 over x2−2x−3 , write f(x) in fully factored form and identify the location of the removable discontinuity and the vertical asymptote.
A removable discontinuity of a rational function occurs at x = a if a is a zero for which kind of factor relationship between numerator and denominator?
A factor in the denominator that is not a factor in the numerator
A factor common to both numerator and denominator
A factor only in the numerator
Any factor with multiplicity greater than or equal to one in the numerator
Given k(x) = (x−2)/(x2−4) , determine the x-values of any removable discontinuities and vertical asymptotes by factoring.
Graph-based interpretation: A plotted rational function shows a dashed vertical line at x = −2 and another at x = 1, with the curve approaching these lines. What conclusion can you draw about the function’s behavior at x = −2 and x = 1?
The function has removable discontinuities at x = −2 and x = 1
The function is continuous at x = −2 and x = 1
The function has vertical asymptotes at x = −2 and x = 1
The function has horizontal asymptotes at x = −2 and x = 1
Recall the rule: When the degree of the denominator is greater than the degree of the numerator for a rational function f(x)=p(x)/q(x), what is the horizontal asymptote?
y = 0
y equals the ratio of leading coefficients
No horizontal asymptote; slant asymptote exists
y = 1
A rational function has numerator degree one larger than the denominator degree. Which end-behavior feature occurs?
Horizontal asymptote at y = 0
Horizontal asymptote at the ratio of leading coefficients
No horizontal asymptote; a slant asymptote determined by polynomial long division
Vertical asymptote at y = 0
State the rule for a horizontal asymptote when the degrees of numerator and denominator are equal for f(x)=p(x)/q(x) with nonzero leading coefficients a_n and b_n.
(a)
Given f(x) = x2+4x−54x+2 , determine its horizontal asymptote based on degree comparison and end behavior.
y = 0
y = 1
y = 4
No horizontal asymptote
For f(x) = (3x2−2x+1)/(x−1) , identify the slant asymptote by performing polynomial division and interpreting end behavior.
y = 3x + 1
y = 3x − 1
y = x + 3
No slant asymptote; horizontal at y = 0
Explain why f(x)=x−13x2−2x+1 has no horizontal asymptote. Provide the degree-based reasoning.
For f(x) = x2+4x−53x2+2 , determine the horizontal asymptote using the ratio of leading coefficients.
y = 3
y = 0
y = 1/3
No horizontal asymptote
A rational function’s graph may cross a horizontal asymptote but will never cross which type of asymptote?
Vertical asymptote
Slant asymptote
Horizontal asymptote
Oblique asymptote
Consider g(x) = (6x3−10x)/(2x3+5x2) . Identify its horizontal asymptote using leading coefficients.
y = 3
y = 0
y = 6/2 = 3
y = (leading coefficient ratio) = 6/2 = 3
For h(x) = (x2−4x+1)/(x+2) , find the slant asymptote by division. Use the given quotient and remainder information.
y = x − 6
y = x + 6
y = x − 2
y = x + 2
Determine the horizontal asymptote of k(x)=x3−8x2+4x by comparing degrees.
y = 0
y = 1
y = 4
No horizontal asymptote
Open response: Describe how to use polynomial long division to find a slant asymptote for a rational function whose numerator degree exceeds the denominator degree by one, and illustrate with the example x−13x2−2x+1 .
Recall the rule for horizontal asymptotes of a rational function when the degrees of the numerator and denominator are equal. Which statement correctly identifies the horizontal asymptote for C(t) = (5 + t) / (100 + 10t)?
y = 0 because the denominator’s degree exceeds the numerator’s degree
y = 1/10 because the ratio of the leading coefficients is 1 to 10
y = 10 because the leading coefficient in the denominator is larger
No horizontal asymptote because the function is linear
Application: In the context of the sugar concentration model C(t) = (5 + t) / (100 + 10t), interpret the horizontal asymptote value in plain terms about long-term behavior.
Analyze the end behavior of f(x) = ((x − 2)(x + 3)) / ((x − 1)(x + 2)(x − 5)). Which statement best describes its horizontal asymptote and why?
y = 1 because the degrees are equal and the ratio of leading coefficients is 1
y = 0 because the denominator’s degree (3) exceeds the numerator’s degree (2)
y = 0 because the function has three vertical asymptotes
No horizontal asymptote because the function is undefined at x = 1, −2, and 5
A rational function will have a y-intercept when which condition is met? Choose the best statement.
The numerator equals zero for some x-value
The input is zero and the function is defined at zero
The denominator equals zero at x = 0
The function has a vertical asymptote at x = 0
Which inputs can produce x-intercepts for a rational function?
Inputs that make the denominator zero
Inputs that make the numerator zero while the function is defined
Inputs that make both numerator and denominator zero
Any inputs that make the function undefined
Consider f(x) = (x−2)(x+3) / [(x−1)(x+2)(x−5)]. Compute the y-intercept.
(a)
For f(x) = (x−2)(x+3) / [(x−1)(x+2)(x−5)], find the x-intercepts.
(a)
In the graph of a rational function, vertical asymptotes correspond to which features of the function?
Zeros of the numerator
Factors of the denominator
Horizontal asymptotes
Points where f(0) ≠ 0
A reciprocal squared function is shifted right 3 units and down 4 units. Write this as a rational function using the toolkit form x21 and then state its vertical and horizontal asymptotes.
When a factor in the denominator has odd degree, how does the graph behave near the corresponding vertical asymptote?
On both sides the graph heads to positive infinity
On both sides the graph heads to negative infinity
On one side the graph heads towards positive infinity and on the other side towards negative infinity
The graph crosses the asymptote
Consider the parent rational function y = 1/x. Describe the end behavior near the vertical asymptote x = 0 and the horizontal asymptote y = 0. Choose the statement that best matches the graph: As x approaches 0 from the right and from the left, and as x → ±∞.
As x → 0+, y → +∞; as x → 0−, y → −∞; as x → ±∞, y → 0.
As x → 0+, y → −∞; as x → 0−, y → +∞; as x → ±∞, y → 0.
As x → 0±, y → 0; as x → ±∞, y → ±∞.
As x → 0±, y → ±∞ with the same sign on both sides; as x → ±∞, y → 1.
A rational function has a denominator factor with even multiplicity producing a vertical asymptote. Which statement best describes the distinguishing characteristic of the graph's behavior near that asymptote?
The graph heads toward the same infinity (both positive or both negative) on both sides of the asymptote.
The graph crosses the asymptote at a single point.
The graph heads to opposite infinities on each side of the asymptote.
The graph must have an x-intercept at the asymptote.
Given the rational function f(x) = ((x+1)2(x−3))/((x+3)2(x−2)) , identify the vertical asymptotes and describe the local behavior on each side based on multiplicity.
For f(x) = ((x+1)2(x−3))/((x+3)2(x−2)) , which point is an x-intercept where the graph bounces (touches and turns) rather than crosses?
x = −1
x = 0
x = 2
x = 3
Using the graph of f(x) = (x+3)2(x−2)(x+1)2(x−3) , identify the horizontal asymptote and explain why it occurs.
According to the 'Given a rational function, sketch a graph' procedure, which step should be performed first?
Evaluate the function at 0 to find the y-intercept.
Factor the numerator and denominator.
Find multiplicities of x-intercepts.
Determine vertical asymptotes by setting denominator factors not common to the numerator equal to 0.
For g(x) = (x+1)2(x−2)(x+2)(x−3) , which x-values are vertical asymptotes, and what does multiplicity tell you about behavior there?
For g(x) = (x+1)2(x−2)(x+2)(x−3) , which statement about intercepts is correct?
y-intercept is (0, 3); x-intercepts at x = −2 and x = 3, each with linear (multiplicity 1) behavior.
y-intercept is (0, −3); x-intercepts at x = −1 and x = 2, each with bouncing behavior.
y-intercept is (3, 0); x-intercept only at x = 3 with bouncing behavior.
No x-intercepts because the numerator degree is less than the denominator degree.
A rational function has x-intercepts at x = x1, x2, …, xn, vertical asymptotes at x = v1, v2, …, vm, and no horizontal asymptote other than y = 0. Which general form correctly expresses f(x) using factors from intercepts and asymptotes?
f(x) = a(x − x1)(x − x2)…(x − xn)(x − v1)(x − v2)…(x − vm)
f(x) = a(x − x1)p1(x − x2)p2…(x − xn)pn/(x − v1)q1(x − v2)q2…(x − vm)qm
f(x) = a/(x − x1)p1(x − x2)p2…(x − xn)pn(x − v1)q1(x − v2)q2…(x − vm)qm
f(x) = a(x − v1)q1(x − v2)q2…(x − vm)qm/(x − x1)p1(x − x2)p2…(x − xn)pn
From the graph of a rational function, the curve crosses the x-axis at x = 3 and just touches and turns at x = −2. What multiplicities do these behaviors suggest for the corresponding factors in the numerator?
Linear factors with powers 1 at both x = −2 and x = 3
A squared factor at x = −2 and a linear factor at x = 3
Cubic factors at both x = −2 and x = 3
A linear factor at x = −2 and a squared factor at x = 3
Suppose a graph shows vertical asymptotes at x = −1 and x = 2. Near x = −1, the branches go to opposite infinities on either side. Near x = 2, both sides head to negative infinity. Which choice best matches the simplest denominator consistent with this behavior?
(x + 1)(x − 2)
(x + 1)2(x − 2)
(x + 1)(x − 2)2
(x + 1)2(x − 2)2
Given a rational function with x-intercepts at x = −2 and x = 3, and vertical asymptotes at x = −1 and x = 2 where the behavior matches 1/x at x = −1 and 1/x2 at x = 2, write a simplest-form model for f(x) up to a stretch factor a.
(a)
A graph of a rational function has an x-intercept at x = 1 where the curve crosses the axis, and vertical asymptotes at x = −1 and x = 2. Which statement is correct about the factors and their multiplicities?
Numerator has factor (x − 1)2; denominator has factors (x + 1) and (x − 2)
Numerator has factor (x − 1); denominator has factors (x + 1) and (x − 2)2
Numerator has factors (x + 1) and (x − 2); denominator has factor (x − 1)
Numerator has factor (x − 1)2; denominator has factors (x + 1)2 and (x − 2)2
Using the “HOW TO” guidance for writing a rational function from a graph, which step is used to determine the stretch factor a?
Analyze behavior at each vertical asymptote to decide powers
Use any clear point on the graph different from x-intercepts and asymptotes
Count the number of turning points to infer degree
Compare end behavior to identify the horizontal asymptote
Consider f(x) = a (x + 2)(x − 3)/[(x + 1)(x − 2)2]. If the graph passes through the y-intercept (0, −2), what is the value of a?
a = −2
a = 1
a = 4
a = 2/3
Explain how to determine whether the factor corresponding to a vertical asymptote should have even or odd multiplicity, using observed behavior near the asymptote.
Define a rational function and distinguish it from a polynomial function in terms of algebraic form.
What is a fundamental difference between typical graphs of polynomial functions and rational functions regarding continuity and asymptotic behavior?
Polynomial graphs are always continuous with no asymptotes, while rational graphs can have discontinuities and asymptotes.
Polynomial graphs have vertical asymptotes, while rational graphs never have vertical asymptotes.
Rational graphs are always continuous with no holes, while polynomial graphs often have holes.
Polynomial graphs always have horizontal asymptotes; rational graphs never do.
If the graph of a rational function has a removable discontinuity at x=a, what must be true of the functional rule at x=a?
The function is undefined at x=a because the factor (x−a) cancels.
The function tends to ±∞ as x→a.
The function’s numerator is zero at x=a but the denominator is nonzero.
The function changes concavity at x=a.
Can a graph of a rational function have no vertical asymptote? If so, how?
Can a rational function have no x-intercepts? If so, how?
Find the domain of f(x)= x+2x−1 . State excluded x-values.
All real x except x=−2
All real x except x=1
All real x
All real x except x=2
Find the domain of f(x)= x2−1x+1 .
All real x except x=±1
All real x except x=0
All real x
All real x except x=±2
Find the domain of f(x)= x2−2x−8x2+4 .
All real x except x=−2 and x=4
All real x except x=2 and x=−4
All real x except x=−4 and x=2
All real x
Find the domain of f(x)= x5−5x4+4x2+4x−3 .
For f(x)= x−14 , determine the domain, vertical asymptote(s), and horizontal asymptote (if any).
For f(x)= 5x+22 , determine the domain, vertical asymptote(s), and horizontal asymptote (if any).
For f(x)= x2−9x , determine the domain, vertical asymptote(s), and horizontal asymptote (if any).
For f(x)= x2+5x−36x , determine the domain, vertical asymptote(s), and horizontal asymptote (if any).
For f(x)= x3−273+x , determine the domain, vertical asymptote(s), and horizontal asymptote (if any).
For f(x)= x3−16x3x−4 , determine the domain, vertical asymptote(s), and horizontal asymptote (if any).
For f(x)= x3+9x2+14xx2−1 , determine the domain, vertical asymptote(s), and horizontal asymptote (if any).
For f(x)= x2−25x+5 , determine the domain, vertical asymptote(s), and horizontal asymptote (if any).
For f(x)= x−6x−4 , determine the domain, vertical asymptote(s), and horizontal/hole behavior.
For f(x)= 3x−14−2x , determine the domain, vertical asymptote(s), and horizontal asymptote (if any).
Determine the x- and y-intercepts of f(x)=−x2−xx .
For f(x) = (x2+8x+7)/(x2+11x+30) , find the x-intercepts and y-intercept.
Find the x- and y-intercepts of f(x) = x2+10x+24x2+x+6 .
Identify the local behavior near any vertical asymptotes and the end behavior of f(x) = x/(2x+1).
Describe local behavior near the vertical asymptote and the end behavior for f(x) = 2x/(x−6).
Analyze f(x) = −2x/(x−6): state the vertical asymptote, local behavior near it, and the end behavior.
For f(x) = (x2−4x+3)/(x2−4x−5) , describe the local behavior near each vertical asymptote and the end behavior.
Describe the local behavior near the vertical asymptotes and end behavior of f(x) = 6x2+13x−52x2−32 .
Find the slant asymptote of f(x) = 2x+124x2+6x .
Determine the slant asymptote for f(x) = (4x2−2x−10)/(2x−4) .
Find the slant asymptote of f(x) = (81x2−18)/(3x−2) .
Compute the slant asymptote of f(x) = (6x3−5x)/(3x2+4) .
A reciprocal function is shifted up two units. State its new horizontal asymptote and describe how the graph changes.
The reciprocal function is shifted down one unit and left three units. Identify the vertical and horizontal asymptotes of the transformed function.
The reciprocal squared function y=1/x^2 is shifted to the right 2 units. State the vertical and horizontal asymptotes of the transformed function.
The reciprocal squared function y=1/x^2 is shifted down 2 units and right 1 unit. What are the vertical and horizontal asymptotes?
For p(x) = (2x−3)/(x+4), find the horizontal intercept(s), vertical intercept, vertical asymptote, and horizontal asymptote.
For q(x) = (x−5)/(3x−1), determine the horizontal intercept(s), vertical intercept, vertical asymptote, and horizontal asymptote.
For r(x) = 5/(x+1)2 , state the vertical intercept, vertical asymptote, and whether the graph is above or below the x-axis.
For f(x) = (3x2−14x−5)/(3x2+8x−16) , find the horizontal intercepts, the vertical intercept, the vertical asymptotes, and any horizontal or slant asymptote.
For g(x) = (2x2+7x−15)/(3x2−14x+15) , determine all intercepts, vertical asymptotes, and the end behavior.
For a(x) = (x3+2x−3)/(x2−1) , identify the vertical asymptotes and the end behavior (including any slant asymptote).
For b(x) = (x2−x−6)/x2 , state the intercepts, vertical asymptotes, and end behavior.
For h(x) = (2x2+x−1)/(x−4) , find the slant asymptote and any vertical asymptote(s).
For k(x) = (2x2−3x−20)/(x−3) , identify the slant asymptote and the vertical asymptote.
For w(x) = ((x−1)(x+3)(x−5))/((x+2)(x−4)), determine the horizontal intercepts, vertical intercept, and vertical asymptotes.
Write an equation for a rational function with vertical asymptotes at x = 5 and x = −5, x-intercepts at (2, 0) and (−1, 0), and y-intercept at (0, 4). Choose the simplest function with integer coefficients.
A rational function has vertical asymptotes at x = −4 and x = −1, x-intercepts at (1, 0) and (5, 0), and y-intercept at (0, 7). Which of the following is a correct equation?
f(x) = 7(x − 1)(x − 5) / [(x + 4)(x + 1)]
f(x) = 7(x + 1)(x + 4) / [(x − 1)(x − 5)]
f(x) = (x − 1)(x − 5) / [(x + 4)(x + 1)]
f(x)=7(x−1)(x−5)/(x2+5x+4)
Write an equation for a rational function with vertical asymptotes at x = −4 and x = −5, x-intercepts at (4, 0) and (−6, 0), and a horizontal asymptote at y = 7. Provide the simplest form with integer coefficients.
Find a rational function with vertical asymptotes at x = −3 and x = 6, x-intercepts at (−2, 0) and (1, 0), and a horizontal asymptote at y = −2. Choose the simplest form with integer coefficients.
Construct a rational function with a vertical asymptote at x = −1, a double zero at x = 2, and y-intercept at (0, 2).
Create a rational function with a vertical asymptote at x = 3, a double zero at x = 1, and y-intercept at (0, 4).
Use the given graph to write an equation for the function. The graph shows vertical asymptotes at x = −2 and x = 2, x-intercepts at x = −3 and x = 1, and y-intercept at y = −1. Provide a simplest rational function with integer coefficients.
From the graph, identify the vertical asymptotes. The graph displays dashed lines at x = −2 and x = 4 with curves approaching these lines.
x = −2 and x = 4
x = −3 and x = 2
x = −4 and x = 2
x = 2 and x = 4
Given a rational function graph with vertical asymptotes at x = −3 and x = 3, the curve crosses the y-axis at y = −2 and has x-intercepts at x = 0 and x = 2. Write a simplest equation with integer coefficients that fits the graph.
A graph shows vertical asymptotes at x = −3 and x = 5. The y-intercept is y = 0. Which equation below is consistent with these features and also has an x-intercept at x = 2?
f(x) = x(x − 2) / [(x + 3)(x − 5)]
f(x) = (x + 2) / [(x + 3)(x − 5)]
f(x)=x2−2x
f(x) = (x − 2) / (x + 3)
Graph shown has a vertical asymptote marked with an orange dashed line at x = 2. The curve approaches +∞ on the right of the asymptote and −∞ on the left, and passes through the origin, increasing and flattening for large x. Based on this visual, which statement best describes the end behavior as x → ∞?
f(x) → 0 from above
f(x) → 0 from below
f(x) → +∞ without bound
f(x) approaches a positive horizontal asymptote
In the graph with an orange dashed vertical line at x = −2, the function is decreasing across the right half-plane and approaches 0 as x increases. As x approaches −2 from the right, the function tends to +∞. What is the sign of f(x) immediately to the left of the vertical asymptote x = −2?
Positive and large in magnitude
Negative and large in magnitude
Approximately zero
Oscillates between positive and negative
Consider the graph where the orange dashed vertical asymptote is at x = −3. The left branch is in Quadrant II approaching +∞ near the asymptote, and the right branch is in Quadrant IV approaching −∞ near the asymptote and tending to 0 for large positive x. Which interval contains x-values where f(x) > 0?
x > −3
x < −3
All real x
No real x
The displayed graph shows two vertical asymptotes (orange dashed) at x = 3 and x = 5. The curve has peaks near each asymptote and approaches 0 between and outside them. Which statement is most consistent with this behavior?
The function has a single linear denominator producing one vertical asymptote.
The denominator has factors (x − 3)(x − 5) giving two vertical asymptotes.
The function is polynomial with degree 2 and no asymptotes.
The function has a horizontal asymptote y = 5.
For f(x) = 1/(x − 2), make a small numeric table to analyze behavior near the vertical asymptote and horizontal asymptote. Which row correctly shows values near x = 2?
x = 1.9 → f(x) ≈ −10; x = 2.1 → f(x) ≈ +10
x = 1.9 → f(x) ≈ +10; x = 2.1 → f(x) ≈ −10
x = 1.9 → f(x) ≈ −1; x = 2.1 → f(x) ≈ +1
x = 1.9 → f(x) ≈ +1; x = 2.1 → f(x) ≈ −1
Given f(x) = x/(x − 3), identify the vertical and horizontal asymptotes.
For f(x) = 2x/(x + 4), which statement about the sign of f(x) is true?
f(x) is positive for all real x.
f(x) changes sign at x = −4 and at x = 0.
f(x) changes sign only at x = −4.
f(x) is negative for x > 0.
Consider f(x) = 2/(x + 1). Using a graphing calculator, solve f(x) > 0. Which solution set is correct?
x > −1
x < −1
x ≠ −1
All real x
Let f(x) = 4/(2x − 3). Using the graph, for which x is f(x) > 0?
x > 3/2
x < 3/2
All real x
No solution
For f(x) = 2/[(x − 1)(x + 2)], determine the intervals where f(x) > 0 using a sign chart or graph.
Identify the removable discontinuity of f(x) = (x2−4)/(x2−2) . State the x-value where the hole occurs.
(a)
For the function f(x) = (x3+1)/(x+1) , what is the x-value of the removable discontinuity (hole)?
x = −1
x = 1
x = 0
x = −3
For the function f(x) = (x2+x−6)/(x−2) , which value of x creates a removable discontinuity?
x = −3
x = 3
x = 2
x = −2
