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Worksheets

Solutions and their Concentrations

Total questions: 63

Worksheet time: 32mins

Name
Class
Date
1.

Fill in the blank: One of the topics covered in Chapter 4 'Solutions and their Concentrations' is _________.

a)

Types of Solutions

b)

Electrolysis of Water

c)

Periodic Table Trends

d)

Organic Reaction Mechanisms

2.

Fill in the blank: Chapter 4 'Solutions and their Concentrations' discusses _________, which refers to the various methods used to describe how much solute is present in a solution.

a)

Different Ways of Expressing Concentration

b)

Chemical Bonding

c)

Types of Chemical Reactions

d)

Properties of Acids and Bases

3.

Fill in the blank: The process of making solutions is called _________, as mentioned in Chapter 4 'Solutions and their Concentrations'.

a)

Preparation of Solutions

b)

Evaporation

c)

Filtration

d)

Distillation

4.

Fill in the blank: Chapter 4 'Solutions and their Concentrations' includes a topic on _________, which involves the measurement and calculation of how substances behave in solutions.

a)

Activity and Activity Coefficients

b)

Molarity and Molality

c)

Osmosis and Diffusion

d)

Electrolysis and Conductivity

5.

What is a solution? A solution is a __________ mixture of two or more substances.

a)

homogeneous

b)

heterogeneous

c)

colloidal

d)

suspension

6.

Which of the following is the substance present in a smaller amount in a solution?

a)

A) Solute

b)

B) Solvent

7.

Which of the following is the substance present in a larger amount in a solution?

a)

A) Solute

b)

B) Solvent

8.

A solution may be __________ (such as air), __________ (such as an alloy), or __________ (seawater, for example).

a)

gaseous, solid, liquid

b)

liquid, solid, gaseous

c)

solid, gaseous, liquid

d)

liquid, gaseous, solid

9.

True or False: A solution is always a liquid.

a)

True

b)

False

10.

Fill in the blank: A ________ solution is a solution that contains the maximum amount of a solute in a given solvent, at a specific temperature. Q = K

a)

saturated

b)

dilute

c)

unsaturated

d)

supersaturated

11.

Fill in the blank: An ________ solution is the solution that contains less solute than it has the capacity to dissolve. Q < K

a)

unsaturated

b)

saturated

c)

supersaturated

d)

dilute

12.

A ________ solution is the solution that contains more solute than the solvent can normally dissolve. Q > K

a)

supersaturated

b)

saturated

c)

dilute

d)

unsaturated

13.

Based on Table 4.1 Types of Solutions, fill in the blank: When both the solute and solvent are gases, the state of the resulting solution is _____. Example: Air.

a)

Gas

b)

Liquid

c)

Solid

d)

Aqueous

14.

Based on Table 4.1 Types of Solutions, fill in the blank: When the solute is a gas and the solvent is a liquid, the state of the resulting solution is _____. Example: Soda water (CO₂ in H₂O).

a)

Liquid

b)

Solid

c)

Gas

d)

Aqueous

15.

Based on Table 4.1 Types of Solutions, fill in the blank: When the solute is a gas and the solvent is a solid, the state of the resulting solution is _____. Example: H₂ gas in palladium.

a)

Solid

b)

Liquid

c)

Gas

d)

Aqueous

16.

Based on Table 4.1 Types of Solutions, fill in the blank: When both the solute and solvent are liquids, the state of the resulting solution is _____. Example: Ethanol in water.

a)

Liquid

b)

Solid

c)

Gas

d)

Plasma

17.

Based on Table 4.1 Types of Solutions, fill in the blank: When the solute is a solid and the solvent is a liquid, the state of the resulting solution is _____. Example: NaCl in water.

a)

Liquid

b)

Solid

c)

Gas

d)

Plasma

18.

Based on Table 4.1 Types of Solutions, fill in the blank: When both the solute and solvent are solids, the state of the resulting solution is _____. Example: Brass (Cu/Zn), solder (Sn/Pb).

a)

Solid

b)

Liquid

c)

Gas

d)

Aqueous

19.

Which of the following is NOT a type of interaction involved in the formation of solutions?

a)

solvent-solvent interaction

b)

solute-solute interaction

c)

solvent-solute interaction

d)

solute-gas interaction

20.

If the solvent-solute attraction is stronger than the solvent-solvent attraction and solute-solute attraction, the solution process is:

a)

unfavorable

b)

favorable

c)

neutral

d)

impossible

21.

If the solute-solvent interaction is weaker than the solvent-solvent and solute-solute interactions, the solution process is:

a)

exothermic

b)

endothermic

c)

neutral

d)

impossible

22.

If the solution process is exothermic, Hsoln is ____ (greater than/less than/equal to) 0.

a)

less than

b)

greater than

c)

equal to

d)

not defined

23.

Step 1 is the separation of solvent molecules. Is this process endothermic or exothermic?

a)

Endothermic

b)

Exothermic

24.

Step 2 entails the separation of solute molecules. Is this process endothermic or exothermic?

a)

Endothermic

b)

Exothermic

25.

Steps 1 & 2 require energy input to break attractive intermolecular forces; therefore, they are _________.

a)

endothermic

b)

exothermic

c)

neutral

d)

spontaneous

26.

In step 3, the solvent and solute molecules mix. This step may be:

a)

Exothermic

b)

Endothermic

c)

Both exothermic or endothermic

27.

The heat of solution (Hsoln) is given by the equation: Hsoln = H1 + H2 + H3. Fill in the blanks for what H1, H2, and H3 represent.

a)

H1 = Separation of solvent molecules H2 = Separation of solute molecules H3 = Mixing of solvent and solute molecules

b)

H1 = Mixing of solvent and solute molecules H2 = Separation of solvent molecules H3 = Separation of solute molecules

c)

H1 = Separation of solute molecules H2 = Mixing of solvent and solute molecules H3 = Separation of solvent molecules

d)

H1 = Separation of solvent molecules H2 = Mixing of solvent and solute molecules H3 = Separation of solute molecules

28.

Fill in the blank: The amount of solute present in a given amount of solvent, or a given amount of solution, is called the ________ of a solution.

a)

concentration

b)

temperature

c)

density

d)

volume

29.

Which of the following is expressed as mol/L?

a)

Molarity

b)

Normality

c)

Molality

d)

Mole fraction

30.

Which of the following is expressed as eq/L?

a)

Molarity

b)

Normality

c)

Molality

d)

Percent by mass

31.

Which of the following is expressed as mol/Kg?

a)

Molarity

b)

Normality

c)

Molality

d)

Percent by volume

32.

Fill in the blank: The ratio of the number of moles of a component to the total number of moles in the solution is called ________.

a)

mole fraction

b)

molarity

c)

normality

d)

molality

33.

Fill in the blank: The concentration of a solution can be expressed as percent by ________ or percent by ________.

a)

mass; volume

b)

weight; density

c)

temperature; pressure

d)

length; area

34.

Calculate the molar concentration of ethanol in an aqueous solution that contains 2.30 g of C₂H₅OH (46.07 g/mol) in 3.50 L of solution. What is the molar concentration of ethanol?

a)

0.0143 M

b)

0.0660 M

c)

0.00143 M

d)

0.143 M

35.

Given: 2.30 g of C2H5OH and the molar mass of C2H5OH is 46.07 g/mol. Calculate the number of moles of C2H5OH.

a)

0.04992 mol C2H5OH

b)

0.500 mol C2H5OH

c)

0.0200 mol C2H5OH

d)

0.100 mol C2H5OH

36.

What is the molar concentration of C2H5OH if 2.30 g is dissolved in 3.50 L of solution?

a)

0.0143 M

b)

0.0234 M

c)

0.0078 M

d)

0.0356 M

37.

Which formula is used to calculate the molar concentration (M) of a solution?

a)

M = mass/volume

b)

M = moles/volume

c)

M = volume/moles

d)

M = moles × volume

38.

The molality, m, of a solute in solution is the number of moles of solute per ________ of solvent.

a)

kilogram

b)

liter

c)

gram

d)

milliliter

39.

What is the molality of a solution that contains 54.6 g of CH3OH in 108 g of water?

a)

5.00 mol/kg

b)

1.57 mol/kg

c)

3.00 mol/kg

d)

0.50 mol/kg

40.

How many grams of H2O must be used to dissolve 50.0 grams of sucrose to prepare a 1.25 m solution of sucrose, C12H22O11?

a)

27.4 grams

b)

94.1 grams

c)

50.0 grams

d)

32.0 grams

41.

Exercise: Calculate the molality of a solution that contains 56.5 g of benzoic acid, C6H5COOH, in 350 mL of ethanol, C2H5OH. The density of ethanol is 0.789 g/mL. Fill in the blank with the correct molality value.

a)

1.7 m C6H5COOH in C2H5OH

b)

0.5 m C6H5COOH in C2H5OH

c)

2.3 m C6H5COOH in C2H5OH

d)

3.0 m C6H5COOH in C2H5OH

42.

What are the mole fractions of CH3OH and H2O in the solution containing 54.6 grams of CH3OH and 108 grams of H2O?

a)

CH3OH: 0.25, H2O: 0.75

b)

CH3OH: 0.33, H2O: 0.67

c)

CH3OH: 0.50, H2O: 0.50

d)

CH3OH: 0.20, H2O: 0.80

43.

What are the mole fractions of ethanol, C₂H₅OH, and water in a solution prepared by mixing 55.0 g of ethanol with 45.0 g of water?

a)

Mole fraction of ethanol (X_C₂H₅OH) = 0.322, Mole fraction of water (X_H₂O) = 0.678

b)

Mole fraction of ethanol (X_C₂H₅OH) = 0.450, Mole fraction of water (X_H₂O) = 0.550

c)

Mole fraction of ethanol (X_C₂H₅OH) = 0.500, Mole fraction of water (X_H₂O) = 0.500

d)

Mole fraction of ethanol (X_C₂H₅OH) = 0.678, Mole fraction of water (X_H₂O) = 0.322

44.

What is the formula for percent by mass of solute?

a)

(mass of solute / mass of solute + mass of solvent) × 100%

b)

(mass of solute / mass of soln) × 100%

c)

(mass of solvent / mass of solute) × 100%

d)

(mass of solute / mass of solvent) × 100%

45.

Fill in the blank: The percent by mass is a ______ number because it is a ratio of two similar quantities.

a)

unitless

b)

whole

c)

fractional

d)

decimal

46.

Percent by mass is also called percent by weight or the ______ percent.

a)

weight

b)

volume

c)

density

d)

mole

47.

A solution is prepared by mixing 1.00 g ethanol with 100.0 g water to give a final volume of 101 mL. Calculate the molarity of ethanol in this solution. (Show your answer in M)

a)

0.215 M

b)

0.105 M

c)

0.325 M

d)

0.500 M

48.

A solution is prepared by mixing 1.00 g ethanol with 100.0 g water to give a final volume of 101 mL. Calculate the mass percent of ethanol in this solution.

a)

0.99%

b)

1.00%

c)

1.10%

d)

0.90%

49.

A solution is prepared by mixing 1.00 g ethanol with 100.0 g water to give a final volume of 101 mL. What is the mole fraction of ethanol in this solution?

a)

0.0043

b)

0.0217

c)

0.0108

d)

0.0017

50.

A solution is prepared by mixing 1.00 g ethanol with 100.0 g water to give a final volume of 101 mL. Calculate the molality of ethanol in this solution.

a)

0.217 mol/kg

b)

0.010 mol/kg

c)

0.100 mol/kg

d)

0.500 mol/kg

51.

What is the formula for calculating the mass percent of C2H5OH in a solution?

a)

(mass of C2H5OH / mass of solution) × 100%

b)

(mass of solution / mass of C2H5OH) × 100%

c)

(mass of C2H5OH / volume of solution) × 100%

d)

(volume of C2H5OH / mass of solution) × 100%

52.

Calculate the mass percent of C2H5OH if 1.00 g C2H5OH is dissolved in 100.0 g H2O. Show your answer as a percentage.

a)

0.990% C2H5OH

b)

1.00% C2H5OH

c)

0.900% C2H5OH

d)

0.500% C2H5OH

53.

What is the formula for calculating the mole fraction of C2H5OH in a solution?

a)

nC2H5OH / (nC2H5OH + nH2O)

b)

nH2O / (nC2H5OH + nH2O)

c)

nC2H5OH / nH2O

d)

nH2O / nC2H5OH

54.

If 100.0 g H2O is used, how many moles of H2O are present?

a)

5.56 mol

b)

1.80 mol

c)

0.56 mol

d)

10.0 mol

55.

Calculate the mole fraction of C2H5OH if 2.17×10−2molC2H5OH2.17 \times 10^{-2} mol C2H5OH is mixed with 5.56molH2O5.56 mol H2O .

a)

0.00389

b)

0.0123

c)

0.278

d)

0.00456

56.

A solution of phosphoric acid was made by dissolving 10.0 g H₃PO₄ in 100.0 mL water. The resulting volume was 104 mL. Calculate the density of the solution. Assume water has a density of 1.00 g/cm³. (Give your answer in g/mL)

a)

1.06 g/mL

b)

0.96 g/mL

c)

1.10 g/mL

d)

1.00 g/mL

57.

A solution of phosphoric acid was made by dissolving 10.0 g H₃PO₄ in 100.0 mL water. The resulting volume was 104 mL. Calculate the mole fraction of H₃PO₄ in the solution. Assume water has a density of 1.00 g/cm³.

a)

0.018

b)

0.12

c)

0.0018

d)

0.0025

58.

A solution of phosphoric acid was made by dissolving 10.0 g H₃PO₄ in 100.0 mL water. The resulting volume was 104 mL. Calculate the molarity of H₃PO₄ in the solution. Assume water has a density of 1.00 g/cm³.

a)

0.98 M

b)

0.75 M

c)

1.20 M

d)

0.50 M

59.

A solution of phosphoric acid was made by dissolving 10.0 g H₃PO₄ in 100.0 mL water. The resulting volume was 104 mL. Calculate the molality of H₃PO₄ in the solution. Assume water has a density of 1.00 g/cm³.

a)

1.02 m

b)

0.96 m

c)

1.25 m

d)

0.85 m

60.

Normality (N) = ________

a)

Number of equivalents of solute per liter of solution

b)

Number of moles of solute per liter of solution

c)

Number of grams of solute per liter of solution

d)

Number of atoms of solute per liter of solution

61.

Normality (N) is defined as the number of equivalents of solute per liter of solution. Fill in the blank: N x V = ________

a)

Number of equivalents of solute

b)

Number of moles of solute

c)

Volume of solution in liters

d)

Molarity of solution

62.

Normality (N) is defined as the number of equivalents of solute per liter of solution. Example 1: A solution of sulfuric acid contains 86 g of H₂SO₄ per liter of solution. Calculate the normality of this solution.

a)

1.76 N

b)

0.88 N

c)

2.00 N

d)

0.50 N

63.

Calculate the normality of the solution.

a)

1.76 N

b)

0.88 N

c)

2.50 N

d)

0.50 N