
Mean Value Theorem
Flashcard
•
Mathematics
•
11th Grade - University
•
Practice Problem
•
Hard
Standards-aligned
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14 questions
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1.
FLASHCARD QUESTION
Front
What is the Mean Value Theorem?
Back
The Mean Value Theorem states that if a function is continuous on a closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one c in (a, b) such that f'(c) = (f(b) - f(a)) / (b - a).
2.
FLASHCARD QUESTION
Front
What are the conditions for the Mean Value Theorem to apply?
Back
1. The function must be continuous on the closed interval [a, b]. 2. The function must be differentiable on the open interval (a, b).
3.
FLASHCARD QUESTION
Front
What does it mean for a function to be continuous on an interval?
Back
A function is continuous on an interval if there are no breaks, jumps, or holes in the graph of the function over that interval.
4.
FLASHCARD QUESTION
Front
What does it mean for a function to be differentiable on an interval?
Back
A function is differentiable on an interval if it has a derivative at every point in that interval, meaning it has a defined slope.
5.
FLASHCARD QUESTION
Front
If f(x) = x^2 - 3x - 28, what is the average rate of change over the interval [-4, 7]?
Back
The average rate of change is (f(7) - f(-4)) / (7 - (-4)) = (f(7) - f(-4)) / 11 = (1 - 35) / 11 = -34 / 11.
Tags
CCSS.8.F.B.4
CCSS.HSF.IF.B.6
6.
FLASHCARD QUESTION
Front
How do you find the x-value where the function has the same slope as the average rate of change?
Back
Set the derivative f'(x) equal to the average rate of change calculated over the interval and solve for x.
Tags
CCSS.8.F.B.4
CCSS.HSF.IF.B.6
7.
FLASHCARD QUESTION
Front
What is the derivative of f(x) = x^2 - 3x - 28?
Back
f'(x) = 2x - 3.
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