Set up the quadratic formula to solve: $$x^2 + 2x - 5 = 0$$

$$x = \frac{-2 \pm \sqrt{(2)^2 - 4(1)(-5)}}{2(1)}$$

Set up the quadratic formula to solve: $$2x^2 - 3x - 5 = 0$$

$$x = \frac{3 \pm \sqrt{(-3)^2 - 4(2)(-5)}}{2(2)}$$

How do you find the vertex of a parabola given by a quadratic equation?

The vertex can be found using the formula $$x = -\frac{b}{2a}$$ and substituting back to find the y-coordinate.

What is the axis of symmetry for a quadratic function?

The axis of symmetry is the vertical line $$x = -\frac{b}{2a}$$ .

What is the standard form of a quadratic equation?

The standard form is $$ax^2 + bx + c = 0$$ .

How do you convert a quadratic equation from standard form to vertex form?

Complete the square to rewrite the equation in the form $$y = a(x - h)^2 + k$$ .

What is the significance of the leading coefficient in a quadratic equation?

The leading coefficient $$a$$ determines the direction of the parabola: if $$a > 0$$ , it opens upwards; if $$a

What are the roots of a quadratic equation?

The roots are the values of $$x$$ that make the equation equal to zero, found using the quadratic formula.

What is the vertex of the parabola given by the equation $$y = 2x^2 - 8x + 3$$ ?

The vertex can be found at $$x = -\frac{-8}{2(2)} = 2$$ , and substituting back gives the y-coordinate.

What is the relationship between the coefficients and the roots of a quadratic equation?

The sum of the roots is $$-\frac{b}{a}$$ and the product of the roots is $$\frac{c}{a}$$ .

Quadratic Formula Practice - Game #2 Flashcards

Student preview

15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

Back

a = 2, b = -3, c = -5

2.

FLASHCARD QUESTION

Front

Back

3.

FLASHCARD QUESTION

Front

Back

4.

FLASHCARD QUESTION

Front

Back

5.

FLASHCARD QUESTION

Front

Back

a = 4, b = -8, c = -3

6.

FLASHCARD QUESTION

Front

What is the quadratic formula?

Back

7.

FLASHCARD QUESTION

Front

What does the discriminant tell us in a quadratic equation?

Back

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