Retake Pythagorean Theorem --> Distance Between Two Points

Retake Pythagorean Theorem --> Distance Between Two Points

Assessment

Flashcard

Mathematics

8th Grade

Practice Problem

Hard

CCSS
HSG.GPE.B.7, 8.G.B.8, HSG.GPE.B.6

+1

Standards-aligned

Created by

Wayground Content

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15 questions

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1.

FLASHCARD QUESTION

Front

What is the Pythagorean Theorem?

Back

The Pythagorean Theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). It can be expressed as: c² = a² + b².

Tags

CCSS.8.G.B.8

2.

FLASHCARD QUESTION

Front

How do you calculate the distance between two points (x1, y1) and (x2, y2)?

Back

The distance d between two points (x1, y1) and (x2, y2) can be calculated using the formula: d = √((x2 - x1)² + (y2 - y1)²).

Tags

CCSS.HSG.GPE.B.7

3.

FLASHCARD QUESTION

Front

What is the distance between the points (1, 2) and (4, 6)?

Back

Using the distance formula: d = √((4 - 1)² + (6 - 2)²) = √(3² + 4²) = √(9 + 16) = √25 = 5.

Tags

CCSS.HSG.GPE.B.7

4.

FLASHCARD QUESTION

Front

If the coordinates of point A are (3, 4) and point B are (7, 1), what is the distance between them?

Back

Using the distance formula: d = √((7 - 3)² + (1 - 4)²) = √(4 + 9) = √13 ≈ 3.6.

Tags

CCSS.HSG.GPE.B.7

5.

FLASHCARD QUESTION

Front

What is the significance of the Pythagorean Theorem in real-life applications?

Back

The Pythagorean Theorem is used in various fields such as architecture, construction, navigation, and computer graphics to calculate distances and ensure structures are built correctly.

Tags

CCSS.8.G.B.8

6.

FLASHCARD QUESTION

Front

What is a right triangle?

Back

A right triangle is a triangle that has one angle measuring 90 degrees. The side opposite the right angle is called the hypotenuse.

7.

FLASHCARD QUESTION

Front

What are the coordinates of the midpoint between the points (2, 3) and (4, 7)?

Back

The midpoint M can be calculated as: M = ((x1 + x2)/2, (y1 + y2)/2) = ((2 + 4)/2, (3 + 7)/2) = (3, 5).

Tags

CCSS.HSG.GPE.B.6

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