balancing

balancing

Multiple Choice

In every balanced chemical equation, each side of the equation has the same number of ____.  

• coefficients
• moles
• molecules
• atoms of each element

Multiple Choice

Substances that enter into a chemical reaction (found to the left side of the arrow) 

• product
• reactant
• chemical
• balanced equation

Multiple Choice

How many total atoms are represented?         4Al₂O₃

• 2
• 8
• 5
• 20

Multiple Choice

Balance this equation:  H₂ + N₂ → NH₃

•  H₂ + 4N₂ → NH₃
•  H₂ + 3N₂ → 2NH₃
•  3H₂ + N₂ → 2NH₃
•  2H₂ + 2N₂ → 2NH₃

Multiple Choice

Balance this equation,            Al₂O₃ ---> Al + O₂ 

• Cannot be balanced
• 2Al₂O₃ ---> 2Al + 3O₂ 
• 2Al₂O₃ ---> 4Al + 3O₂ 
• 3Al₂O₃ ---> 2Al + O₂ 

Multiple Choice

_NaF + _Br₂ →_NaBr + _F₂

• 1NaF + 2 Br₂ →1 NaBr + 2 F₂
• 2NaF + 2 Br₂ → 2 NaBr + 2 F₂
• 2 NaF + 3 Br₂ → 1 NaBr + 2 F₂
• 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂

Multiple Choice

_K + _Cl₂ →_KCl

• 2 K + 16 Cl₂ → 8 KCl
• 2 K + 1 Cl₂ → 2 KCl
• 3 K + 4 Cl₂ → 3 KCl
• 1 K + 1 Cl₂ →1 KCl

Multiple Choice

_Al + _HCl →_H₂ + _AlCl₃

• 2 Al + 2 HCl → 2 H₂ + 6 AlCl₃
• 3 Al + 3 HCl → 6 H₂ + 2 AlCl₃
• 1 Al + 1 HCl → 3 H₂ + 1 AlCl₃
• 2 Al + 6 HCl → 3 H₂ + 2 AlCl₃

Multiple Choice

_SO₂ + _Li₂Se →_SSe₂ + _Li₂O

• 1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
• 1 SO₂ + 1 Li₂Se → 2 SSe₂ + 2 Li₂O
• 2 SO₂ + 2 Li₂Se → 2 SSe₂ +  2 Li₂O
• 2 SO₂ + 2 Li₂Se → 1 SSe₂ + 1 Li₂O

Multiple Choice

_AlBr₃ + _K₂SO₄ → _KBr + _Al₂(SO₄)₃

• 6 AlBr₃ + 1 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃
• 2 AlBr₃ + 3 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃
• 1 AlBr₃ + 1 K₂SO₄ → 2 KBr + 3 Al₂(SO₄)₃
• 2 AlBr₃ + 3 K₂SO₄ → 1 KBr + 2 Al₂(SO₄)₃

Multiple Choice

_BaS + _PtF₂ → _BaF₂ + _PtS

• 1 BaS + 1 PtF₂ → 1 BaF₂ + 1 PtS
• 4 BaS + 2 PtF₂ → 1 BaF₂ +  1 PtS
• 1 BaS + 2 PtF₂→ 2 BaF₂ +  2 PtS
• 1 BaS + 3 PtF₂ →1 BaF₂ +  2 PtS

Multiple Choice

_AgNO₃ + _Cu →_Cu(NO₃)₂ + _Ag

• 2 AgNO₃ + 2 Cu → 3 Cu(NO₃)₂ + 1 Ag
• 2 AgNO₃ + 1 Cu → 1 Cu(NO₃)₂ + 2 Ag
• 1 AgNO₃ + 2 Cu → 2 Cu(NO₃)₂ + 1 Ag
• 3 AgNO₃ + 2 Cu → 3 Cu(NO₃)₂ + 2 Ag

Multiple Choice

_P₄+_O₂ →  _P₂O₃

• 3 P₄+1 O₂ → 2 P₂O₃
• 1 P₄+1 O₂ → 2 P₂O₃
• 1 P₄+ 3 O₂ → 2 P₂O₃
• 1 P₄+ 2 O₂ → 3 P₂O₃