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Laws of Exponents

Laws of Exponents

Assessment

Presentation

•

Mathematics

•

8th Grade

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Practice Problem

•

Medium

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CCSS
8.EE.A.1, HSA.APR.A.1

Standards-aligned

Created by

Tosha Franks

Used 578+ times

FREE Resource

6 Slides • 6 Questions

1

Laws of Exponents

a-n is the reciprocal of an. For example, 42 and

4-2 are inverses or reciprocals.

42  = 4(4) = 16   4-2 = 1 / 4(4) =1 / 16


If this is the case, if 33 = 27, then 3-3

Slide image

2

Multiple Choice

If  33 = 27, then 3 −3 = ?3^{3\ }=\ 27,\ then\ 3\ ^{-3\ }=\ ?  

1

 133\frac{1}{3^3}  

2

-3

3

-27

4

 13−3\frac{1}{3^{-3}}  

3

Negative Exponents...

represent fractions or numbers less than 1. We can simplify negative exponents by making them positive. To do this, move the negative exponents to the denominator where they become positive.

 2−4 = 1242^{-4\ }=\ \frac{1}{2^4}   =

4

Multiple Choice

 If 2−4= 124, then 5−2 = ?If\ 2^{-4}=\ \frac{1}{2^4},\ then\ 5^{-2\ }=\ ?   

1

-25

2

 152\frac{1}{5^2}  

3

-5

4

 15−2\frac{1}{5^{-2}}  

5

The power of 0

~ raising a nonzero number to the power of 0 = 1.

100 = 1, 50 = 1, -70 = 1

6

Fill in the Blanks

150 =

Type answer...

7

Multiplying Exponents

When multiplying exponents, you simply add the exponents.


23(25) expanded out is 2(2)(2) times 2(2)(2)(2)(2)


You keep the base, 2, and add the exponents 3 + 5 = 8. 23+5 = 28


This rule applies to variables as well.

8

Multiple Choice

Simplify a4(a5).

1

a4+5 = a9

2

a4-5 = a-1

3

a4(5) = a20

4

2a4+5 = 2a9

9

Dividing Exponents



When dividing exponents, you keep the base and subtract the exponents.

 105103\frac{10^5}{10^3}  =  10(5−3)10^{\left(5-3\right)}  =  10210^2  



10

Multiple Choice

 126124= ?\frac{12^6}{12^4}=\ ?  

1

12

2

1

3


 12(6+4) = 121012^{\left(6+4\right)}\ =\ 12^{10}  

4

 12(6 − 4) = 12212^{\left(6\ -\ 4\right)}\ =\ 12^2  

11

Negative Exponents & Dividing Fractions

When dividing fractions, you multiply by the reciprocal.  The expression 3−2 ÷ 33 = 132÷333^{-2}\ \div\ 3^{3\ }=\ \frac{1}{3^2}\div3^3 .  This is the same as  19÷27\frac{1}{9}\div27 since  3−2 = 132 or 13(3) or 19.3^{-2\ }=\ \frac{1}{3^2}\ or\ \frac{1}{3\left(3\right)\ }or\ \frac{1}{9.} To divide this, you would rewrite as  19 (127)\frac{1}{9\ }\left(\frac{1}{27}\right)  since the reciprocal of 27 is  127.\frac{1}{27.}   19(127) = 1243.\frac{1}{9}\left(\frac{1}{27}\right)\ =\ \frac{1}{243.}  

12

Fill in the Blanks

 Solve 4−3 ÷ 42Solve\ 4^{-3\ \div}\ 4^2  Write answer in standard form (as a whole number).



Type answer...

pattern-tertiary

Laws of Exponents

a-n is the reciprocal of an. For example, 42 and

4-2 are inverses or reciprocals.

42  = 4(4) = 16   4-2 = 1 / 4(4) =1 / 16


If this is the case, if 33 = 27, then 3-3

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