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Laws of Exponents

Laws of Exponents

Assessment

Presentation

Mathematics

8th Grade

Practice Problem

Medium

CCSS
8.EE.A.1, HSA.APR.A.1

Standards-aligned

Created by

Tosha Franks

Used 575+ times

FREE Resource

6 Slides • 6 Questions

1

Laws of Exponents

a-n is the reciprocal of an. For example, 42 and

4-2 are inverses or reciprocals.

42  = 4(4) = 16   4-2 = 1 / 4(4) =1 / 16


If this is the case, if 33 = 27, then 3-3

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2

Multiple Choice

If  33 = 27, then 3 3 = ?3^{3\ }=\ 27,\ then\ 3\ ^{-3\ }=\ ?  

1

 133\frac{1}{3^3}  

2

-3

3

-27

4

 133\frac{1}{3^{-3}}  

3

Negative Exponents...

represent fractions or numbers less than 1. We can simplify negative exponents by making them positive. To do this, move the negative exponents to the denominator where they become positive.

 24 = 1242^{-4\ }=\ \frac{1}{2^4}   =

4

Multiple Choice

 If 24= 124, then 52 = ?If\ 2^{-4}=\ \frac{1}{2^4},\ then\ 5^{-2\ }=\ ?   

1

-25

2

 152\frac{1}{5^2}  

3

-5

4

 152\frac{1}{5^{-2}}  

5

The power of 0

~ raising a nonzero number to the power of 0 = 1.

100 = 1, 50 = 1, -70 = 1

6

Fill in the Blank

150 = _____

7

Multiplying Exponents

When multiplying exponents, you simply add the exponents.


23(25) expanded out is 2(2)(2) times 2(2)(2)(2)(2)


You keep the base, 2, and add the exponents 3 + 5 = 8. 23+5 = 28


This rule applies to variables as well.

8

Multiple Choice

Simplify a4(a5).

1

a4+5 = a9

2

a4-5 = a-1

3

a4(5) = a20

4

2a4+5 = 2a9

9

Dividing Exponents



When dividing exponents, you keep the base and subtract the exponents.

 105103\frac{10^5}{10^3}  =  10(53)10^{\left(5-3\right)}  =  10210^2  



10

Multiple Choice

 126124= ?\frac{12^6}{12^4}=\ ?  

1

12

2

1

3


 12(6+4) = 121012^{\left(6+4\right)}\ =\ 12^{10}  

4

 12(6  4) = 12212^{\left(6\ -\ 4\right)}\ =\ 12^2  

11

Negative Exponents & Dividing Fractions

When dividing fractions, you multiply by the reciprocal.  The expression 32 ÷ 33 = 132÷333^{-2}\ \div\ 3^{3\ }=\ \frac{1}{3^2}\div3^3 .  This is the same as  19÷27\frac{1}{9}\div27 since  32 = 132 or 13(3) or 19.3^{-2\ }=\ \frac{1}{3^2}\ or\ \frac{1}{3\left(3\right)\ }or\ \frac{1}{9.} To divide this, you would rewrite as  19 (127)\frac{1}{9\ }\left(\frac{1}{27}\right)  since the reciprocal of 27 is  127.\frac{1}{27.}   19(127) = 1243.\frac{1}{9}\left(\frac{1}{27}\right)\ =\ \frac{1}{243.}  

12

Fill in the Blank

 Solve 43 ÷ 42Solve\ 4^{-3\ \div}\ 4^2  Write answer in standard form (as a whole number).

Laws of Exponents

a-n is the reciprocal of an. For example, 42 and

4-2 are inverses or reciprocals.

42  = 4(4) = 16   4-2 = 1 / 4(4) =1 / 16


If this is the case, if 33 = 27, then 3-3

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