
Quadratic equation: zero principle
Presentation
•
Mathematics
•
University
•
Medium
+6
Standards-aligned
Jill Kaniewski
Used 1+ times
FREE Resource
9 Slides • 33 Questions
1
Quadratic equation: zero principle
The first part of this lesson covers factoring completely. The second part will be the graphic organizer for the quadratic equation. The last part of this lesson is the review for chapter 6. All parts must be complete to receive full credit.
2
Factoring completely
Over the last few lessons we factored using the GCF, then by grouping and finally we looked at special cases of factoring. When factoring, there are instances that you may have to use all the methods mentioned. This will be called factoring completely.
Factoring completely:
1. Identify if there are any GCF in the equation and factor them pulling the GCF to the front of the equation.
2. Identify how many terms you are factoring and apply the correct method.
3. Can those factors be factored again? If so factor them.
3
Ex:
24m2 −42my + 9y21. Is there a GCF?
3 (8m2 −14my + 3y2)
2. Identify how many terms and factor.
Multiples of 8x3 that add to -14
-12 x -2 = 24 -12 + -2 = -14
8m2 − 12my − 2my + 3y2
Group the pairs and factor the GCF.
4
((8m2 − 12my) + (−2my + 3y2))
4m(2n -3y) -1y(2m - 3y)
(4m - y)( 2m - 3y)
Complete factor: 3(4m - y)(2n-3y)
5
Multiple Choice
2c2 + 4c - 84
6
Multiple Choice
3x2 + 18x +15
7
Multiple Choice
8
Solving quadratic equations using the zero-factor property
When given an equation set it equal to zero.
You may have to move terms to the left of the equation to set it to zero.
Factor completely. Since they are set to zero, each factored term can be set to zero to solve for the variable.
Your graphic organizer has split this process into two branches. Those that are already factored and only need to be solve which is on the left of the organizer and those that need to be set to zero which is on the right. Fill in the blanks on the organizer by looking at your book starting on page 463.
9
Ex:
y2= 9y − 8Put this back into standard form and set it equal to zero
y2 − 9y + 8 =0
Now factor the equation: ( y -8)(y-1)
To solve for y: y-8=0 and y - 1 = 0
Solutions for y = {8, 1}
This is how to use the zero-factor property.
Remember to always get the equation in standard form then factor.
10
You will need to use all of your factoring knowledge to solve these equations.
There are cases where there is a double solution when solving the equation.
Ex:
x2 + 16x + 64 = 0When factored you will have (x+8)2
The solution for x will just be {-8} which is a double solution.
11
Multiple Choice
Solve:
x2+6x+5=−3
x=1 or 5
x=−5 or −1
x=−4 or −2
x=2 or 4
12
Multiple Choice
Solve:
x2−5x−14=0
x=2 or 7
x=−7 or −2
x=−2 or 7
x=−7 or 2
13
Multiple Choice
Solve:
z(z−15)=0
z=0 or 15
z=−15 or 0
z=−15
z=15
14
Multiple Choice
Solve:
(x−5)(x−2)=0
x=−5 or 2
x=2 or 5
x=−2 or 5
x=−5 or −2
15
Multiple Choice
Solve:
(x+4)(x+7)=0
x=4 or 7
x=−4 or 7
x=−7 or 4
x=−7 or −4
16
Multiple Choice
What is the first step in solving
(x+2)(x−3)=0 ?
Plug in zero for x
Solve for x
FOIL
Set each binomial factor equal to zero
17
Multiple Choice
x2-5x+6=0 are
18
We have come to the end of chapter 6. The next slides will be review for the test on Thursday. You may take notes on the slides. Remember the test will be a zoom class with open camera and sound.
19
Multiple Choice
5x2 - 13x + 6
20
Multiple Choice
4h² - 17h + 4
21
Multiple Choice
r2 -16r + 60
22
Multiple Choice
23
Multiple Choice
x2 + 81
not factorable
( x - 9 ) ( x + 9 )
( x + 9 ) ( x + 9 )
( x - 9 ) ( x - 9 )
24
Multiple Choice
x2 - 9
25
Multiple Choice
5n³-10n²+3n-6
26
Multiple Choice
What is the GCF of the trinomial?
6x5y4+24x6y2-36x3y3
6x3y2
6xy
6x6y4
6x3y
27
Multiple Choice
4b5 + 4b3 + 16b2
28
Multiple Choice
80x5-70x2-60x7
29
Multiple Choice
56a3-8a
30
Multiple Choice
x³+7x²-2x-14
31
Multiple Choice
Factor Completely:
2n3 + 7n2 - 2n - 7
cannot be factored
(n - 1)2(2n + 7)
(n2 - 1)(2n + 7)
(n + 1)(n - 1)(2n + 7)
32
Multiple Choice
16x2 - 20xy
33
Multiple Choice
Factor Completely:
x4 - 9x2
x2(x + 3)(x - 3)
(x2 + 3x)(x2 - 3x)
(x2 + 9)(x - 3)(x + 3)
x2(x2 - 9)
34
Multiple Choice
Factor Completely:
x2 - 17x + 72
(x - 9)(x + 8)
(x - 9)(x - 8)
x(x - 3)
(x + 9)(x + 8)
35
Multiple Choice
x3 - 5x2 + 5x - 25
(x2 - 5)(x - 5)
(x2 + 5)(x - 5)
(x2 + 5)(x + 5)
(x2 - 1)(x - 25)
36
Multiple Choice
Factor by grouping
x3 + 4x2 + 4x + 16
(x + 4)(x + 2)
(x - 4)(x2 - 4)
(x + 4)(x2 + 4)
(x - 4)(x - 2)
37
Multiple Choice
Solve the equation by factoring.
x = {-5,-3}
x = {5,-3}
x = {-5,3}
x = {5,3}
38
Multiple Choice
Solve the equation by factoring.
x = {1}
x = {-1}
x = { }
no solution
39
Multiple Choice
Solve the equation by factoring.
x = {3,8}
x = {-3,8}
x = {3,-8}
x = {-3,-8}
40
Multiple Choice
3x2 - 192 = 0
41
Multiple Choice
42
This completes today's lesson.
See you on Thursday in the zoom room.
Quadratic equation: zero principle
The first part of this lesson covers factoring completely. The second part will be the graphic organizer for the quadratic equation. The last part of this lesson is the review for chapter 6. All parts must be complete to receive full credit.
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