7.EEI.4 Test Review

7.EEI.4 Test Review

Ms. Randolph's 7th Grade Test Review

Part One: Solving Equations

Multiple Choice

Students were asked to solve the following: 4x + 8 = 48. Their responses are below:

Dasher: x = 10

Dancer: x = 14

Prancer: x = 4

Vixen: x = 9

Who was correct?

• Dasher

• Dancer

• Prancer

• Vixen

Check your work!

Multiple Choice

Students were asked to solve the following: 10x + 7 = 67. Their responses are below:

Comet: x = 10

Cupid: x = 5

Donner: x = 6

Blitzen: x = 7.4

Who was correct?

• Comet

• Cupid

• Donner

• Blitzen

Multiple Choice

What is the value of x in the equation -3x + 12 = 51?

• -13

• 12

• 13

• -11

Check your work!

Multiple Choice

What is the value of x in the equation -6x + 7 = 49?

• 7

• 6

• 9.333...

• -7

Multiple Choice

Solve 58 = 4x - 10 for x.

• x = 14

• x = 17

• x = 12

• x = 4

Check your work!

Multiple Choice

Solve 115 = 8x + 3 for x.

• x = 115/8

• x = 118/8

• x = 16

• x = 14

Multiple Choice

Which equation has the same solution as 9x + 4 = 58?

• 2x = 14

• $\frac{x}{4}=\ 10$

• 3x = 18

• 5x = 30 - 5

Check your work!

Multiple Choice

Which equation has the same solution as 8x - 15 = 25?

• 3x = 20 - 5

• 4x = 16

• $\frac{x}{3}=\ 2$

• 5x = 20

Multiple Choice

What is the value of x in the equation:

 $\frac{1}{5}x\ +\ 5\ =\ -4?$  

• x = -45

• x = -5

• x = -54

• x = 5

Check your work!

Multiple Choice

What is the value of x in the equation:

 $\frac{1}{3}x\ +\ 3\ =\ -7$  

• x = -12

• x = -10/3

• x = -4

• x = -30

Part Two: Inequalities

Multiple Choice

What would you need to do next in the following situation: While solving -4x > 8, you first divide by -4 on both sides of the inequality...

• Add 8 to both sides of the inequality

• Reverse the inequality sign

• Change the answer from a negative number to a positive number

• Multiply both sides of the inequality by x

Check your work!

Multiple Choice

Solve the following inequality for x:

 $-\frac{1}{2}x\ +\ 5\ <\ 9$  

• x < -8

• x > 8

• x < -2

• x > -8

Multiple Choice

Sandy sold 22 tickets to the school barbecue. She sold more than twice the number of tickets Teresa sold. This situation can be represented by the inequality 2t < 22 where t is the number of tickets Teresa sold. Given this inequality we know Teresa sold less than ______ tickets.

• 9

• 44

• 22

• 11

Check your work!

Multiple Choice

Which inequality represents the following situation: Sam has 3 bottles of water. Dave has b bottles of water. Altogether, Sam and Dave have more than 13 bottles of water.

• 3b > 13

• 3 + b > 13

• 3 - b > 13

• 3 + b < 13

Multiple Choice

What is the solution set of the inequality given? -6x - 14 > 22

• x < -6

• x > 7

• x > -6

• x < -7

Check your work!

Multiple Choice

What is the solution set of the inequality given?

 $-3x\ +\ 40\ \le\ 67$  

•  $x\ \le9$  

•  $x\ge8$  

•  $x\ge-9$  

•  $x\le-8$  

Multiple Choice

Which of the following inequalities is represented by the graph below?

• 4x > 16

• $2x\ \ge8$

• $9x\ \le36$

• 3x < 12

Multiple Choice

Which of the following inequalities is represented by the graph below?

• $\frac{1}{3}x\ >\ 6$

• 4x > 8

• 3x < 6

• $\frac{1}{2}x\ge1$

Multiple Choice

I was solving 5p + 5 < 45 on the board. I added 5 on both sides and got 5p < 50 and then divided by 5 on both sides and got p < 10 as my solution set. What, if anything did I do wrong?

• Nothing, this is correct!

• I should have subtracted 5 on both sides first rather than adding 5

• I should have multiplied by 5 on both sides rather than dividing by 5

• I should have reversed the inequality sign

Multiple Choice

I was solving

 $\frac{1}{2}m\ -\ 6\ >\ 4$  . I added 6 on both sides and got  $\frac{1}{2}m\ >\ 10$ . I then divided by 2 on both sides and got m > 5. What, if anything did I do wrong?

• Nothing, this is correct!

• I should have subtracted 6 on both sides rather than adding 6

• I should have multiplied by 2 on both sides rather than dividing by 2

• I should have reversed the inequality sign.

Multiple Choice

I was solving

 $\frac{1}{2}m\ -\ 6\ >\ 4$  . I added 6 on both sides and got  $\frac{1}{2}m\ >\ 10$ . I then divided by 2 on both sides and got m > 5. What, if anything did I do wrong?

• Nothing, this is correct!

• I should have subtracted 6 on both sides rather than adding 6

• I should have multiplied by 2 on both sides rather than dividing by 2

• I should have reversed the inequality sign.