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Unit 5 Review

Unit 5 Review

Assessment

Presentation

Mathematics

7th - 10th Grade

Medium

CCSS
HSG.SRT.A.2, 7.G.A.1, 8.EE.A.2

+8

Standards-aligned

Created by

Caleb Arnold

Used 4+ times

FREE Resource

14 Slides • 25 Questions

1

Unit 5 Review

5.1 Inequalities and Triangles

5.2 Ratios, Proportions, Geometric Mean

5.3 Use Proportions in Geometry

5.4 Use Similar Polygons

5.5 Use Proportionality Theorems

5.6 Similarity Transformations

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5.1 Inequalities and Triangles

  • Not every set of 3 numbers can form a triangle

  • Any two sides of a triangle MUST be LARGER than the third

  • A very handy tool to visualize this can be found here: https://www.geogebra.org/m/pNm33AuP

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Multiple Select

Which of the following groups of side lengths could NOT create a triangle?

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5.2 Ratios

  • A Ratio is a comparison of how much there is of one thing in relation to another; below is an example of different ratios within a single data group

  • There are 10 students; 6 are left-handed while 4 are right-handed:

  • The ratio of left-handed to right-handed students is 6 to 4, or 6:4

  • The ratio of right-handed to left-handed students is 4 to 6, or 4:6

  • The ratio of left-handed students to all students is 6 to 10, or 6:10

  • The ratio of right-handed students to all students is 4 to 10, or 4:10

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5.2 Simplifying Ratios

  • Ratios can be simplified much like fractions

  •  24\frac{2}{4}  

  • Is the above a proper answer to a math problem? NO!

  •  12\frac{1}{2}  

  • That's better! Two-fourths simplifies to one-half

  • A ratio can be simplified when both terms share a common factor - an integer that can be multiplied by another whole number to make the starting number

  • If the terms share a common factor, we factor it out just as we do with a fraction. The ratio 2:4 simplifies to 1:2

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Multiple Choice

What is the largest number that will fit into both 10 and 30? This is called the greatest common factor or (GCF)

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5

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3

3

10

4

4

8

Multiple Choice

What is the MOST simplified (absolutely smallest possible numbers) version of the ratio 10:30?

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5:15

2

4:12

3

6:24

4

1:3

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5.2 Proportionality

  • If two ratios are proportional, they simplify to the same ratio

  • An example of proportional ratios would be a scaled picture, model, or map

  • The ratio of each component to all the others should be the same as in reality!

  • These would then be proportional ratios, and proportional pictures, models, or map

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Multiple Choice

Question image

This is Jamar. Hi Jamar!

Select the stick figure that is PROPORTIONAL to Jamar.

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Multiple Choice

Which of the following ratios is proportional to the ratio 5:7?

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10:21

2

3:7

3

7:5

4

15:21

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5.2 Geometric Mean

  • In Algebra 1 you learned about mean, median, and mode.

  • The mean that you learned about, also known as the average, is called the arithmetic mean.

  • The arithmetic mean is found by adding all of the values together and dividing by the total number of values.

  • For example, the mean of 2, 4, 6 is found by the equation: 2 + 4 + 63=123=4\frac{2\ +\ 4\ +\ 6}{3}=\frac{12}{3}=4  

  • The Geometric mean works similarly, but is different in a few specific, and important, ways.

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Multiple Choice

Find the Algebraic Mean of 3, 5, and 8:

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6

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16

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3

4

5

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5.2 Geometric Mean

  • If we have a set of numbers (where just represents how many numbers we have):

  • The geometric mean is found by multiplying all of the values together, and then finding the nth root of the product.

  • Remember that are not finding geometric means of more than two numbers! For these problems, always use the square root! √

  • Find the geometric mean of 2 and 8:

  •  2  8=16=4\sqrt{2\ \cdot\ 8}=\sqrt{16}=4  

  • Note how this is different from the arithmetic mean:

  •  2 + 82=102=5\frac{2\ +\ 8}{2}=\frac{10}{2}=5  

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Multiple Choice

Find the geometric mean of 16 and 4:

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8

2

10

3

12

4

20

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Multiple Choice

Find the geometric mean of 4 and 36:

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8

2

10

3

12

4

20

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5.3 Use Proportions

  • When we know that two things are proportional, we know that the ratio between those two simplify to the same values.

  • We can create an equation that sets proportional ratios equal to each other, and solve for a missing value! Remember that we cross-multiple to solve.

  • Let's return to our left-handed and right-handed students example. There are 10 students, 6 left-handed and 4 right-handed

  • If I gain some students, and now have 12 left-handed students, but the ratio stays proportional, how right-handed students do I have? How many total?

  •  64=12x    =>   6x = 124   =>   x = 486   =>  x=8\frac{6}{4}=\frac{12}{x}\ \ \ \ =>\ \ \ 6x\ =\ 12\cdot4\ \ \ =>\ \ \ x\ =\ \frac{48}{6}\ \ \ =>\ \ x=8 

  •  610=12x  =>  6x = 12  10 =>  x = 1206  =>  x = 20\frac{6}{10}=\frac{12}{x}\ \ =>\ \ 6x\ =\ 12\ \cdot\ 10\ =>\ \ x\ =\ \frac{120}{6}\ \ =>\ \ x\ =\ 20  

  • 8 right-handed students and 20 total students!

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5.3 Similarity and Corresponding Parts

  • Two object are similar when they have the same shape but not necessarily the same side.

  • Similar figures will have proportional ratios

  • One of the most important skills in using proportions in geometry is the ability to find corresponding parts of figures

  • Corresponding parts are those that are in the same relative place on different figures

  • Thinking back to our stick figures - corresponding parts would be body parts! The heads correspond to each other - the right arms correspond to each other - etc.

21

Multiple Choice

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Find the corresponding angle to angle a:

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Multiple Choice

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Find the side corresponding to side fg:

 fg\overline{fg}  

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Use Proportions in Geometry

  • With similar polygons, we can create ratios between sides, and compare those ratios with the corresponding ratios in similar figures.

  • We can set up proportional relationships between corresponding parts of similar figures, just as we set up proportional relationships with the numbers of students.

  • Then we can solve for missing components!

24

Multiple Choice

Question image

What is the ratio from side ab to side bc?

 ab\overline{ab} to  bc\overline{bc}  
Remember that order is important!

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6:4

2

4:5

3

5:6

4

6:5

25

Multiple Choice

Question image

What is the ratio from side ab to side bc?

 de\overline{de} to  ef\overline{ef}  
Remember that order is important!

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x:8

2

8:12

3

12:x

4

x:12

26

Multiple Choice

Question image

What is the proportion of the following ratios:

 abbc=deef\frac{\overline{ab}}{\overline{bc}}=\frac{\overline{de}}{\overline{ef}}  


1

 45=812\frac{4}{5}=\frac{8}{12}  

2

 65=12x\frac{6}{5}=\frac{12}{x}  

3

 65=x12\frac{6}{5}=\frac{x}{12}  

4

 x8 =12x\frac{x}{8\ }=\frac{12}{x}  

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5.4 Similar Polygons

  • For this section we focus on the idea of scale factor

  • The scale factor is the number that one similar figure's values can be multiplied by to get the values of another figure

  • Returning to the student example: if my classroom goes for 10 students to 20 students, what is the scale factor?

  • To find the scale factor, divide the end value by the beginning value: in this case, divide 20 by 10. The scale factor is 2.

  • What is my class goes from 20 students down to 4? Divide the end value (4) by the beginning value (20): 20 divided by 4 is 1/5. The scale factor is 1/5.

  • When we know the scale factor between similar figures, we can find missing values.

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32

Multiple Choice

Question image

If the scale factor between these similar figures is 5, what are the side lengths of figure b?

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24

2

5

3

30

4

65

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5.5 Proportionality Theorems (Triangles)

  • We learned about two proportionality theorems: Side-splitter and Angle bisector

  • The side-splitter theorem states that, in a triangle with an interior line parallel to one side of the triangle, the sides split by that line are proportional

  • The angle-bisector theorem that, when a line in a triangle bisects one of the interior angles, the segments it creates are proportional to the adjacent sides.

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Multiple Choice

Select the picture showing the side-splitter theorem:

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35

Multiple Choice

Select the picture showing the angle bisector theorem:

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2

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5.6 Similarity Transformations

  • In this section we learned about dilations, changing the size of a figure in relation to a specific point.

  • To dilate a figure, we measure the distances of each point from the center of dilation and then multiply that distance by the dilation factor

  • The resulting numbers are then added to the coordinates of the center of dilation to find the new location of the point

37

Multiple Choice

Which of the following is a dilation of point A from the origin (0,0) by a dilation factor of 2?

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38

Multiple Choice

Which of the following is a dilation of point A from the origin (0,0) by a dilation factor of 1/2?

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39

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Unit 5 Review

5.1 Inequalities and Triangles

5.2 Ratios, Proportions, Geometric Mean

5.3 Use Proportions in Geometry

5.4 Use Similar Polygons

5.5 Use Proportionality Theorems

5.6 Similarity Transformations

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