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  5. Hpc Section 4.7 Inverse Trig Functions Day 2
HPC Section 4.7 Inverse Trig Functions Day 2

HPC Section 4.7 Inverse Trig Functions Day 2

Assessment

Presentation

•

Mathematics

•

9th - 12th Grade

•

Practice Problem

•

Easy

•
CCSS
HSF.TF.B.7, HSF.IF.A.2, HSF-BF.B.4A

+3

Standards-aligned

Created by

Shane Devlin

Used 17+ times

FREE Resource

17 Slides • 17 Questions

1

Precalculus Section 4.7 Inverse Trig Functions Day 2

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Multiple Choice

Graph y = arctan x with your calculator.

What is the domain of the function?

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(-1, 1)

2

All Reals

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(−π2,π2)\left(-\frac{\pi}{2},\frac{\pi}{2}\right)  

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(−π, π)\left(-\pi,\ \pi\right)  

3

Multiple Choice

Look at the graph y = arctan x on your calculator.

What is the range of the function?

1

(-1, 1)

2

All Reals

3

(−π2,π2)\left(-\frac{\pi}{2},\frac{\pi}{2}\right)  

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(−π, π)\left(-\pi,\ \pi\right)  

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y = tangent x

What would the restriction need to be for this graph to pass the horizontal line test?


Discuss with a neighbor

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Multiple Choice

Evaluate:

The answer must be within the range for the inverse function.

arctan (-1)

1

−π4-\frac{\pi}{4}  

2

3π4\frac{3\pi}{4}  

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5π4\frac{5\pi}{4}  

4

−π2-\frac{\pi}{2}  

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Multiple Choice

Evaluate:

The answer must be within the range for the inverse function.

arccos (-1)

1

−π-\pi  

2

π\pi  

3

π2\frac{\pi}{2}  

4

−π2-\frac{\pi}{2}  

9

Multiple Choice

Evaluate:

The answer must be within the range for the inverse function.

tan⁡−1(0)\tan^{-1}\left(0\right)  

1

−π-\pi  

2

π\pi  

3

00  

4

−π2-\frac{\pi}{2}  

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π2\frac{\pi}{2}  

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Composite functions

11

Fill in the Blanks

f(x)=x2f\left(x\right)=\sqrt{x^2}   Think about this function.   Evaluate if x = 4.

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Fill in the Blanks

f(x)=x2f\left(x\right)=\sqrt{x^2}   Think about this function.   Evaluate if x = 7.

13

Fill in the Blanks

f(x)=x2f\left(x\right)=\sqrt{x^2}  

Think about this function.  

Evaluate if x = -2.

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Multiple Choice

Evaluate:

sin⁡(sin⁡−1(12))\sin\left(\sin^{-1}\left(\frac{1}{2}\right)\right)  

1

12\frac{1}{2}  

2

32\frac{\sqrt{3}}{2}  

3

π6\frac{\pi}{6}  

4

π3\frac{\pi}{3}  

18

Multiple Choice

Evaluate:

cos⁡(cos⁡−1(32))\cos\left(\cos^{-1}\left(\frac{\sqrt{3}}{2}\right)\right)  

1

12\frac{1}{2}  

2

32\frac{\sqrt{3}}{2}  

3

π6\frac{\pi}{6}  

4

π3\frac{\pi}{3}  

19

Multiple Choice

Evaluate:

cos⁡−1(cos⁡(π4))\cos^{-1}\left(\cos\left(\frac{\pi}{4}\right)\right)  

1

11  

2

22\frac{\sqrt{2}}{2}  

3

π4\frac{\pi}{4}  

4

π2\frac{\pi}{2}  

20

Multiple Choice

Evaluate:

sin⁡−1(sin⁡(90°))\sin^{-1}\left(\sin\left(90\degree\right)\right)

1

11  

2

π\pi  

3

90°90\degree  

4

0°0\degree  

21

Multiple Choice

Evaluate:

sin⁡−1(sin⁡(210°))\sin^{-1}\left(\sin\left(210\degree\right)\right)  

1

30°30\degree  

2

60°60\degree  

3

−30°-30\degree  

4

150°150\degree  

5

210°210\degree  

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So why is this not 210?

Let's evaluate from the inside out.
What is sin (210) ?

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Multiple Choice

Evaluate:

sin⁡−1(sin⁡(3π4))\sin^{-1}\left(\sin\left(\frac{3\pi}{4}\right)\right)  

1

π4\frac{\pi}{4}   

2

  −π4-\frac{\pi}{4}   

3

π6\frac{\pi}{6}  

4

π3\frac{\pi}{3}  

26

Multiple Choice

Evaluate:

sin⁡(cos⁡−1(12))\sin\left(\cos^{-1}\left(\frac{1}{2}\right)\right)  

1

12\frac{1}{2}  

2

32\frac{\sqrt{3}}{2}  

3

π6\frac{\pi}{6}  

4

π3\frac{\pi}{3}  

27

Multiple Choice

Evaluate:

cos⁡(tan⁡−1(1))\cos\left(\tan^{-1}\left(1\right)\right)  

1

12\frac{1}{2}  

2

32\frac{\sqrt{3}}{2}  

3

22\frac{\sqrt[]{2}}{2}  

4

π4\frac{\pi}{4}  

5

11  

28

Multiple Choice

Evaluate:

cos⁡(cos⁡−1(π))\cos\left(\cos^{-1}\left(\pi\right)\right)  

1

12\frac{1}{2}  

2

32\frac{\sqrt{3}}{2}  

3

π6\frac{\pi}{6}  

4

π3\frac{\pi}{3}  

5

not possible

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Homework Day 2
  • Page 322 - 325

  • #1, 2, 8, 9, 13, 14, 18, 20, 24, 28, 32, 46, 53 - 59 odd

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pattern-tertiary
Precalculus Section 4.7 Inverse Trig Functions Day 2

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