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Trig Ratios 2- Calculator & Solving for a side

Trig Ratios 2- Calculator & Solving for a side

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

CCSS
HSG.SRT.C.8, HSG.SRT.C.6, HSG.SRT.C.7

+1

Standards-aligned

Created by

Jamie Chenoweth

Used 7+ times

FREE Resource

18 Slides • 33 Questions

1

Trig Ratios 2- Calculator & Solving Triangles

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2

Scientific Calculators

  • To do calculations, you will need a scientific calculator ( sin, cos, tan)

  • you can also use your phone calc, turn it sideways

  • you can also use Desmos, Geogebra or Google Calc

  • have your calc ready, we're gonna need it

3

Solving for a Side

suppose you have this problem, and youre asked to solve for x. The Pythagorean Theorem can always be used when you have two sides, but we only have a side and an angle...

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4

Setup the Ratio

Notice that in Reference to the angle of 18, x is adjacent and 17 is hypotenuse. Since Adj/Hyp or a/h is the cosine, we can write  


 cos(18)=x17\cos\left(18\right)=\frac{x}{17}  

and if we multiply both sides by 17 

 17cos(18) =x17\cos\left(18\right)\ =x  

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5

Time to Calculate

Try entering that into your calculator

 17cos(18) =x17\cos\left(18\right)\ =x  




if you need help using your calculator, try google 

6

Multiple Choice

 Calculate

 17cos(18) =x17\cos\left(18\right)\ =x 

1

0.956

2

0.951

3

17.21

4

16.16

7

Let's try another One

practice = Mo Betta

8

How do we Solve for a

hint: start with the given angle, then write a ratio

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9

Multiple Choice

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Which will correctly Solve for a?

1

 sin(20)=a35\sin\left(20\right)=\frac{a}{35}  

2

 cos(35)=a20\cos\left(35\right)=\frac{a}{20}  

3

 sin(35)=a20\sin\left(35\right)=\frac{a}{20}  

4

 cos(20)=a35\cos\left(20\right)=\frac{a}{35}  

10

Multiple Choice

Which statement is a correct rearrangement to solve for a?

 sin(35)=a20\sin\left(35\right)=\frac{a}{20}  


1

 20(sin35)=a20\left(\sin35\right)=a  

2

  20(sin35)20=a\ \frac{20\left(\sin35\right)}{20}=a  

3

 35sin(20)=a35\sin\left(20\right)=a  

4

  (sin35)20=a\ \frac{\left(\sin35\right)}{20}=a  

11

Multiple Choice

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Solve for the length of side a (we just set it up)

1

11.97

2

11.47

3

0.57

4

0.34

12

What if X is in the denominator?

      setup the ratio
1) ____ (57)=oh\left(57\right)=\frac{o}{h}  


      substitute, rearrange to solve

2)  sin(57)=10.8x\sin\left(57\right)=\frac{10.8}{x}  

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13

When x is the denominator... use algebra

 sin(57)=10.8x\sin\left(57\right)=\frac{10.8}{x}             multiply both sides by x

 x sin(57)=10.8x\ \sin\left(57\right)=10.8          then divide by sin(57)

 x=10.8sin(57)x=\frac{10.8}{\sin\left(57\right)}         ....or just cross multiply

14

Multiple Choice

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Which equation could be used to solve for the variable....

1
2
3
4

15

Multiple Choice

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now Solve for x...

1

5.88

2

19.8

3

12.88

4

13.2

5

9.06

16

Multiple Choice

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Set up an equation that could be used to solve for the variable.

1
2
3
4

17

Multiple Choice

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Solve for x

1

5.5

2

19.05

3

9.52

4

7.8

18

Multiple Choice

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What is the length of side x?

1

6.57 cm

2

7 cm

3

7.44 cm

4

26.33 cm

19

Multiple Choice

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Solve for x. Round to the nearest tenth.

1

15.3

2

16.6

3

24.1

4

24.3

20

Multiple Choice

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Solve for x. Round to the nearest tenth.
1
19.0
2
20.0
3
21.0
4
20.5

21

Multiple Choice

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Solve for x. Round to the nearest tenth.
1
74.9
2
3.6
3
63.5
4
54.1

22

Solving for an Angle using Trig Ratios

In all of the previous problems, we have been given an angle and a side to solve for a missing side. But what if we have two sides but dont know the angles? Remember that Trig ratios relate angles to sides, so we can use what we already know, but we need one critical piece of information to understand how it works....

23

Old School Trig Tables

Suppose we had a problem which gave us this statement..

 cosA=12\cos A=\frac{1}{2}  


if we used the trig table, we could see that the cosine of 60 is 1/2

So A=  60o60^o  
..our calculator can do this for any angle...This process is called the Inverse of the Trig Function

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24

Inverse Trig Ratios

...are used to find angles

the inverse sine

 sin1(oh)=θ\sin^{-1}\left(\frac{o}{h}\right)=\theta  

..is also called the Arcsine


the inverse of cosine is arccosine and inverse tanget is arctangent

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25

Inverse Trig to find Angles: Find angles A and B

1) start with the ratio for what is given..in this case any of the three ratios could be used.
 sin(A)=35        A = sin1(0.6)\sin\left(A\right)=\frac{3}{5}\ \ \ \ \ \ \ \ A\ =\ \sin^{-1}\left(0.6\right) 
so    A=36.9oA=36.9^o  

but how did we find this?...
   

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26

Use the Inverse to find Angles

We could use tables to work backwards, but its easier to use a calculator. The Inverse function will do that...

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27

Using Calculator to Find Angle

The shift (2nd) button on TI's allows you to use the functions above each button. Above sin is inverse sine (arcsine) To calculate 

 sin(A)=35        A = sin1(0.6)\sin\left(A\right)=\frac{3}{5}\ \ \ \ \ \ \ \ A\ =\ \sin^{-1}\left(0.6\right)  

you would enter  
2nd         sin     (   3÷53\div5  )   =

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28

Multiple Choice

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Set up an equation that could be used to solve for the variable.

1
2
3
4

29

Multiple Choice

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Rearrange that equation to solve for   θ\theta  

1

 θ= sin1(96)\theta=\ \sin^{-1}\left(\frac{9}{6}\right)  

2

 θ= sin1(69)\theta=\ \sin^{-1}\left(\frac{6}{9}\right)  

3

 θ= cos1(96)\theta=\ \cos^{-1}\left(\frac{9}{6}\right)  

4

 θ= cos1(69)\theta=\ \cos^{-1}\left(\frac{6}{9}\right)  

30

Multiple Choice

Question image

 solve for   θ\theta  

1

 26o26^o  

2

 41.8o41.8^o 

3

 48.2o48.2^o  

4

 15.6o15.6^o  

5

error

31

Multiple Choice

Question image

Set up the problem so that you can solve for X.

1

sin X = 41/28

2

tan X = 41/28

3

cos X = 28/41

4

sin X = 28/41

32

Multiple Choice

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Which equation solves for X?

1

X=cos1(2841)X=\cos^{-1}\left(\frac{28}{41}\right)

2

X=sin1(2841)X=\sin^{-1}\left(\frac{28}{41}\right)

3

X=cos1(4128)X=\cos^{-1}\left(\frac{41}{28}\right)

4

X=sin1(4128)X=\sin^{-1}\left(\frac{41}{28}\right)

33

Multiple Choice

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Solve for X

1

 43.1o43.1^o   

2

 46.9o46.9^o   

3

 55.7o55.7^o  

4

 34.3o34.3^o  

34

Time to see what you've learned

...get your calculator ready

35

Multiple Choice

Question image

Solve for x.           hint:      1121-1-\sqrt{2}  


1

x = 90º

2

x = 60º

3

x = 45º

4

x = 30º

36

Multiple Choice

Question image

Solve for x.                  hint      1231-2-\sqrt{3}  

1

x = 90º

2

x = 60º

3

x = 45º

4

x = 30º

37

Multiple Choice

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Which equation would you use to solve for the unknown angle?

1

x = tan–1(24/7)

2

x = tan–1(7/24)

3

x = tan–1(25/7)

4

x = tan–1(7/25)

38

Multiple Choice

Question image

Which equation would you use to solve for the unknown angle?

1

x = sin–1(4/5)

2

x = cos–1(4/5)

3

x = cos–1(5/4)

4

x = tan–1(4/5)

39

Multiple Choice

Question image

What equation can be used to solve for x?

1

Sin(40°)= x/40

2

Sin(40º)=x/19

3

Cos(40º)=x/19

4

Tan(40°)=19/x

40

Multiple Choice

Question image

Use inverse trig ratios (SOH CAH TOA) to solve for the missing angle

1

32°

2

44°

3

61°

4

50°

41

Multiple Choice

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Find the measure of the indicated angle (?) round to the nearest tenth.
1
9.4
2
55.2
3
20.15
4
19.4

42

Multiple Choice

Question image

Solve for m∠N

1

14

2

65

3

76

4

53

43

Multiple Choice

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Solve for x. Round to the nearest tenth.
1
103.5
2
4.7
3
55.0
4
23.4

44

Multiple Choice

Question image

Solve for x. Round to the nearest tenth.

1

9.8

2

0.1

3

0.038

4

9.9

45

Multiple Choice

Question image

Solve for the missing angle

1

50

2

0.053

3

36.9

4

95

46

Multiple Choice

Question image

Find the measure of the missing angle.

1

64o

2

26o

3

61o

4

.008o

47

Multiple Choice

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Find the measure of the indicated angle.

1

9.39

2

55.2

3

20.2

4

19.4

48

Solve the Triangle: means to find all the sides and angles.

  • You can use angle Sum Theorem (=180) if you have two known angles

  • You can use the Pythagorean Theorem if you have 2 sides.

  • You can use SRT for 30-60-90 and 45-45-90

  • Trig Ratios can be used to find missing sides

  • Inverse Trig Ratios are used to find angles

49

Multiple Select

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We have been using the 3-4-5 Triangle frequently, which are True statements?

1

32+42=523^2+4^2=5^2

2

sin A=35\sin\ A=\frac{3}{5}

3

5sinA=35\sin A=3

4

A=sin1(35)A=\sin^{-1}\left(\frac{3}{5}\right)

5

A=36.87oA=36.87^o

50

Multiple Select

Question image

For the 3-4-5 Triangle, which are True?

1

 5242=325^2-4^2=3^2 

2

 cos B=35\cos\ B=\frac{3}{5} 

3

 B=sin1(45)B=\sin^{-1}\left(\frac{4}{5}\right) 

4

 cos A= sin B\cos\ A=\ \sin\ B 

5

 B=53.1oB=53.1^o 

51

Pauhana

..can go beach now

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Trig Ratios 2- Calculator & Solving Triangles

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