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Lesson 19 Beyond Circles

Lesson 19 Beyond Circles

Assessment

Presentation

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Mathematics

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8th - 12th Grade

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Medium

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CCSS
5.G.A.2, HSG.SRT.C.8

Standards-aligned

Created by

Andrew Witczak

Used 5+ times

FREE Resource

10 Slides • 11 Questions

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Lesson 19 Beyond Circles

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Fill in the Blanks

 f(t)=2sin⁡(2πt24)f\left(t\right)=2\sin\left(\frac{2\pi t}{24}\right)  The water level f, in feet, at a certain beach is modeled by the function f(t), where t is the number of hours since the level was measured.


What is the amplitude of the function, in feet.


Type the number only.



Type answer...

12

Fill in the Blanks

 f(t)=2sin⁡(2πt24)f\left(t\right)=2\sin\left(\frac{2\pi t}{24}\right)  The water level f, in feet, at a certain beach is modeled by the function f(t), where t is the number of hours since the level was measured.


What is the period of the function in hours?


Type the number only.



Type answer...

13

Open Ended

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 f(t)=2sin⁡(2πt24)f\left(t\right)=2\sin\left(\frac{2\pi t}{24}\right)  The water level f, in feet, at a certain beach is modeled by the function f(t), where t is the number of hours since the level was measured.


Sketch a graph on the function over the first 72 hours.

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Multiple Select

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Open Ended

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Multiple Select

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Fill in the Blanks

 h(x)=15+4sin⁡(θ)h\left(x\right)=15+4\sin\left(\theta\right)  

The function h given by h(x)models the height, in feet, at the tip of a windmill blade that has rotated through an angle .
What is the height of the windmill?

Type the number only.



Type answer...

18

Fill in the Blanks

 h(x)=15+4sin⁡(θ)h\left(x\right)=15+4\sin\left(\theta\right)  

The function h given by h(x)models the height, in feet, at the tip of a windmill blade that has rotated through an angle .
What is the length of the windmill blade.

Type the number only.



Type answer...

19

Multiple Choice

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Write an equation describing the vertical position on a Ferris wheel that is the same size as the Ferris wheel described by f but spins twice as quickly.

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g(t)=80sin⁡(2πt15)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{15}\right)+95

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g(t)=80sin⁡(2πt30)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{30}\right)+95

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g(t)=80sin⁡(2πt45)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{45}\right)+95

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g(t)=80sin⁡(2πt60)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{60}\right)+95

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Multiple Choice

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Write an equation describing the vertical position on a Ferris wheel that spins the same speed as the Ferris wheel described by f but whose radius is twice as large.

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 g(t)=160sin⁡(2πt15)+95g\left(t\right)=160\sin\left(\frac{2\pi t}{15}\right)+95 

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 g(t)=160sin⁡(2πt30)+175g\left(t\right)=160\sin\left(\frac{2\pi t}{30}\right)+175 

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 g(t)=160sin⁡(2πt30)+95g\left(t\right)=160\sin\left(\frac{2\pi t}{30}\right)+95 

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g(t)=80sin⁡(2πt60)+95g\left(t\right)=80\sin\left(\frac{2\pi t}{60}\right)+95

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Multiple Select

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Lesson 19 Beyond Circles

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