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Trigonometric Derivatives

Trigonometric Derivatives

Assessment

Presentation

•

Mathematics

•

11th - 12th Grade

•

Practice Problem

•

Medium

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CCSS
HSF.TF.A.2

Standards-aligned

Created by

Catherine Wascheck

Used 37+ times

FREE Resource

11 Slides • 9 Questions

1

Trigonometric Derivatives

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2

Multiple Choice

Warm up: What is 


 sin⁡(3π2)\sin\left(\frac{3\pi}{2}\right)  

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1

2

-1

3

0

4

Undefined

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Today we will learn...

  • How to differentiate trigonometric functions

4

It's important to remember with trigonmetric derivatives that all differentiation rules remain in place

This includes product rule, chain rule, quotient rule, etc.

5

 ddx[sin⁡x]=cos⁡x\frac{d}{dx}\left[\sin x\right]=\cos x  
With chain rule, 
 ddx[sin⁡(f(x))]=cos⁡(f(x))f′(x)\frac{d}{dx}\left[\sin\left(f\left(x\right)\right)\right]=\cos\left(f\left(x\right)\right)f'\left(x\right)  


6

Multiple Choice

 ddx[sin⁡(2x)]\frac{d}{dx}\left[\sin\left(2x\right)\right]  

1

 cos⁡(2x)\cos\left(2x\right)  

2

 2sin⁡(2x)2\sin\left(2x\right)  

3

 2cos⁡(2x)2\cos\left(2x\right)  

7

Multiple Choice

 ddx[sin⁡(x2+x)]\frac{d}{dx}\left[\sin\left(x^2+x\right)\right]  

1

 (2x+1)cos⁡(x2+x)\left(2x+1\right)\cos\left(x^2+x\right)  

2

 cos⁡(2x+1)\cos\left(2x+1\right)  

3

 cos⁡(x2+x)\cos\left(x^2+x\right)  

8

 ddx[cos⁡x]=−sin⁡x\frac{d}{dx}\left[\cos x\right]=-\sin x  

With chain rule, 

 ddx[cos⁡(f(x))]=−sin⁡(f(x))f′(x)\frac{d}{dx}\left[\cos\left(f\left(x\right)\right)\right]=-\sin\left(f\left(x\right)\right)f'\left(x\right)  

9

Multiple Choice

 ddx[cos⁡(ex)]\frac{d}{dx}\left[\cos\left(e^x\right)\right]  

1

 −sin⁡(ex)-\sin\left(e^x\right)  

2

 exe^x  

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 −exsin⁡(ex)-e^x\sin\left(e^x\right)  

10

Multiple Choice

 ddx[sin⁡xcos⁡x]\frac{d}{dx}\left[\sin x\cos x\right]  

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1

2

 −sin⁡xcos⁡x-\sin x\cos x  

3

 cos⁡2x−sin⁡2x\cos^2x-\sin^2x  

11

Multiple Choice

 ddx[sin⁡2 (2x)]\frac{d}{dx}\left[\sin^{2\ }\left(2x\right)\right]  

1

 4sin⁡(2x)cos⁡(2x)4\sin\left(2x\right)\cos\left(2x\right)  

2

 2cos⁡(2x)2\cos\left(2x\right)  

3

 4cos⁡(2x)4\cos\left(2x\right)  

12

Rewrite  tan⁡x\tan x  using  a trig identity and try to find its derivative using quotient rule

13

 ddx[tan⁡x]=sec⁡2x\frac{d}{dx}\left[\tan x\right]=\sec^2x  

With Chain Rule

 ddx[tan⁡(f(x))]=sec⁡2(f(x))f′(x)\frac{d}{dx}\left[\tan\left(f\left(x\right)\right)\right]=\sec^2\left(f\left(x\right)\right)f'\left(x\right)  

14

Rewrite  cot⁡x\cot x  using  a trig identity and try to find its derivative using quotient rule

15

 ddx[cot⁡x]=−csc⁡2x\frac{d}{dx}\left[\cot x\right]=-\csc^2x  

With Chain Rule

 ddx[cot⁡(f(x))]=−csc⁡2(f(x))f′(x)\frac{d}{dx}\left[\cot\left(f\left(x\right)\right)\right]=-\csc^2\left(f\left(x\right)\right)f'\left(x\right)  

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18

Multiple Choice

Find the derivative f(x) = tanxcosx
1
f'(x) = sec2xcosx - tanxsinx
2
f'(x) = sec2xcosx + tanxsinx
3
f'(x) = sec2xsinx
4
f'(x) = sec2xcosx - tanxcosx

19

Multiple Choice

Question image
Determine the derivative of:  f(x) = x4sinx
1
x4 cosx - 4x3sinx
2
x4 cosx + 4x3sinx
3
4x3cosx
4
-4x3cosx

20

Multiple Choice

 ddx[cos⁡2 (x)]\frac{d}{dx}\left[\cos^{2\ }\left(\sqrt{x}\right)\right]  

1

 2cos⁡xsin⁡x2\cos\sqrt{x}\sin\sqrt{x}  

2

 −cos⁡xsin⁡xx-\frac{\cos\sqrt{x}\sin\sqrt{x}}{\sqrt{x}}  

3

 cos⁡2 (x)2x\frac{\cos^{2\ }\left(\sqrt{x}\right)}{2\sqrt{x}}  

4
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Trigonometric Derivatives

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