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Trigonometric Derivatives

Trigonometric Derivatives

Assessment

Presentation

Mathematics

11th - 12th Grade

Practice Problem

Medium

CCSS
HSF.TF.A.2

Standards-aligned

Created by

Catherine Wascheck

Used 34+ times

FREE Resource

11 Slides • 9 Questions

1

Trigonometric Derivatives

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2

Multiple Choice

Warm up: What is 


 sin(3π2)\sin\left(\frac{3\pi}{2}\right)  

1

1

2

-1

3

0

4

Undefined

3

Today we will learn...

  • How to differentiate trigonometric functions

4

It's important to remember with trigonmetric derivatives that all differentiation rules remain in place

This includes product rule, chain rule, quotient rule, etc.

5

 ddx[sinx]=cosx\frac{d}{dx}\left[\sin x\right]=\cos x  
With chain rule, 
 ddx[sin(f(x))]=cos(f(x))f(x)\frac{d}{dx}\left[\sin\left(f\left(x\right)\right)\right]=\cos\left(f\left(x\right)\right)f'\left(x\right)  


6

Multiple Choice

 ddx[sin(2x)]\frac{d}{dx}\left[\sin\left(2x\right)\right]  

1

 cos(2x)\cos\left(2x\right)  

2

 2sin(2x)2\sin\left(2x\right)  

3

 2cos(2x)2\cos\left(2x\right)  

7

Multiple Choice

 ddx[sin(x2+x)]\frac{d}{dx}\left[\sin\left(x^2+x\right)\right]  

1

 (2x+1)cos(x2+x)\left(2x+1\right)\cos\left(x^2+x\right)  

2

 cos(2x+1)\cos\left(2x+1\right)  

3

 cos(x2+x)\cos\left(x^2+x\right)  

8

 ddx[cosx]=sinx\frac{d}{dx}\left[\cos x\right]=-\sin x  

With chain rule, 

 ddx[cos(f(x))]=sin(f(x))f(x)\frac{d}{dx}\left[\cos\left(f\left(x\right)\right)\right]=-\sin\left(f\left(x\right)\right)f'\left(x\right)  

9

Multiple Choice

 ddx[cos(ex)]\frac{d}{dx}\left[\cos\left(e^x\right)\right]  

1

 sin(ex)-\sin\left(e^x\right)  

2

 exe^x  

3

 exsin(ex)-e^x\sin\left(e^x\right)  

10

Multiple Choice

 ddx[sinxcosx]\frac{d}{dx}\left[\sin x\cos x\right]  

1

1

2

 sinxcosx-\sin x\cos x  

3

 cos2xsin2x\cos^2x-\sin^2x  

11

Multiple Choice

 ddx[sin2 (2x)]\frac{d}{dx}\left[\sin^{2\ }\left(2x\right)\right]  

1

 4sin(2x)cos(2x)4\sin\left(2x\right)\cos\left(2x\right)  

2

 2cos(2x)2\cos\left(2x\right)  

3

 4cos(2x)4\cos\left(2x\right)  

12

Rewrite  tanx\tan x  using  a trig identity and try to find its derivative using quotient rule

13

 ddx[tanx]=sec2x\frac{d}{dx}\left[\tan x\right]=\sec^2x  

With Chain Rule

 ddx[tan(f(x))]=sec2(f(x))f(x)\frac{d}{dx}\left[\tan\left(f\left(x\right)\right)\right]=\sec^2\left(f\left(x\right)\right)f'\left(x\right)  

14

Rewrite  cotx\cot x  using  a trig identity and try to find its derivative using quotient rule

15

 ddx[cotx]=csc2x\frac{d}{dx}\left[\cot x\right]=-\csc^2x  

With Chain Rule

 ddx[cot(f(x))]=csc2(f(x))f(x)\frac{d}{dx}\left[\cot\left(f\left(x\right)\right)\right]=-\csc^2\left(f\left(x\right)\right)f'\left(x\right)  

16

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17

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18

Multiple Choice

Find the derivative f(x) = tanxcosx
1
f'(x) = sec2xcosx - tanxsinx
2
f'(x) = sec2xcosx + tanxsinx
3
f'(x) = sec2xsinx
4
f'(x) = sec2xcosx - tanxcosx

19

Multiple Choice

Question image
Determine the derivative of:  f(x) = x4sinx
1
x4 cosx - 4x3sinx
2
xcosx + 4x3sinx
3
4x3cosx
4
-4x3cosx

20

Multiple Choice

 ddx[cos2 (x)]\frac{d}{dx}\left[\cos^{2\ }\left(\sqrt{x}\right)\right]  

1

 2cosxsinx2\cos\sqrt{x}\sin\sqrt{x}  

2

 cosxsinxx-\frac{\cos\sqrt{x}\sin\sqrt{x}}{\sqrt{x}}  

3

 cos2 (x)2x\frac{\cos^{2\ }\left(\sqrt{x}\right)}{2\sqrt{x}}  

4

Trigonometric Derivatives

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