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Trigo4:Combination

Trigo4:Combination

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Mathematics

•

12th Grade

•

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Created by

Thavarajah Selvarajah

Used 4+ times

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7 Slides • 20 Questions

1

Trigo4:Combination

by Thavarajah Selvarajah

2

​LEVEL 1
PIT-STOP 1+2+3
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​What you are expected to unlock?
  • ​Deciding which weapons to use for Differentiation

  • ​Next, doing it!

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Multiple Choice

Given  y=sin⁡x−2cos⁡2xy=\sin x-2\cos2x  .To find  dydx\frac{dy}{dx}  , suitable PIT-STOP to be used are

1

Direct, Chain Rule

2

Direct,Direct

3

Chain Rule, Chain Rule

4

Direct,Power Rule

5

Multiple Choice

Given  y=sin⁡x−2cos⁡2xy=\sin x-2\cos2x  ,  dydx\frac{dy}{dx}  =?

1

cos⁡x+4sin⁡2x\cos x+4\sin2x  

2

cos⁡x−2sin⁡2x\cos x-2\sin2x  

3

cos⁡x+2sin⁡2x\cos x+2\sin2x  

4

cos⁡x−4sin⁡2x\cos x-4\sin2x  

6

Multiple Choice

Given  y=sin⁡2x−cos⁡22xy=\sin2x-\cos^22x  .To find  dydx\frac{dy}{dx}  , suitable PIT-STOP to be used are

1

Chain rule, Power rule

2

Direct, Power rule

3

Chain Rule, Chain Rule

4

Direct, Direct

7

Multiple Choice

Given  y=sin⁡2x−cos⁡22xy=\sin2x-\cos^22x  ,  dydx\frac{dy}{dx}  =?

1

2cos⁡2x−2cos⁡2x2\cos2x-2\cos2x  

2

cos⁡2x+2cos⁡2xsin⁡2x\cos2x+2\cos2x\sin2x  

3

2cos⁡2x+4sin⁡2xcos⁡2x2\cos2x+4\sin2x\cos2x  

4

2cos⁡2x−4cos⁡2xsin⁡2x2\cos2x-4\cos2x\sin2x  

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Multiple Choice

Given  y=34sin⁡x−cos⁡(34x)y=\frac{3}{4}\sin x-\cos\left(\frac{3}{4}x\right)  ,to find  dydx\frac{dy}{dx}  the suitable PIT-STOP is

1

Direct, Chain Rule

2

Direct, Power Rule

3

Direct, Direct

4

Chain Rule,Chain Rule

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Multiple Choice

Given  y=34sin⁡x−cos⁡(34x)y=\frac{3}{4}\sin x-\cos\left(\frac{3}{4}x\right)  ,  dydx\frac{dy}{dx}  =?

1

34cos⁡x−34sin⁡ 34x\frac{3}{4}\cos x-\frac{3}{4}\sin\ \frac{3}{4}x  

2

34cos⁡x+34sin⁡ (34x)\frac{3}{4}\cos x+\frac{3}{4}\sin\ \left(\frac{3}{4}x\right)  

3

34sin⁡x−sin⁡ 34x\frac{3}{4}\sin x-\sin\ \frac{3}{4}x  

4

34sin⁡x+sin⁡ 34x\frac{3}{4}\sin x+\sin\ \frac{3}{4}x  

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Multiple Choice

Given  y=4cot⁡2x+3sec⁡2xy=4\cot2x+3\sec^2x  .To find  dydx\frac{dy}{dx}  , suitable PIT-STOP to be used are

1

Direct, Chain Rule

2

Direct,Power Rule

3

Chain Rule, Chain Rule

4

Chain Rule,Power Rule

11

Multiple Choice

Given  y=4cot⁡2x+3sec⁡2xy=4\cot2x+3\sec^2x  ,  dydx\frac{dy}{dx}  =?

1

4cosec⁡22x+6sec⁡x4\operatorname{cosec}^22x+6\sec x  

2

−8cosec⁡22x+6sec⁡x-8\operatorname{cosec}^22x+6\sec x  

3

4cosec⁡22x+6sec⁡2xtan⁡x4\operatorname{cosec}^22x+6\sec^2x\tan x  

4

−8cosec⁡22x+6sec⁡2xtan⁡x-8\operatorname{cosec}^22x+6\sec^2x\tan x  

12

Multiple Choice

Given  y=4cosec⁡2x−4tan⁡2xy=4\operatorname{cosec}^2x-4\tan2x  .To find  dydx\frac{dy}{dx}  , suitable PIT-STOP to be used are

1

Power Rule, Direct 

2

Direct,Chain Rule

3

Chain Rule, Chain Rule

4

Power Rule,Chain Rule

13

Multiple Choice

Given  y=4cosec⁡2x−4tan⁡2xy=4\operatorname{cosec}^2x-4\tan2x  , dydx\frac{dy}{dx}  =?

1

8cosec⁡2xcot⁡x−8sec⁡22x8\operatorname{cosec}^2x\cot x-8\sec^22x

2

−8cosec⁡2xcot⁡x−8sec⁡22x-8\operatorname{cosec}^2x\cot x-8\sec^22x  

3

8cosec⁡x−4sec⁡22x8\operatorname{cosec}x-4\sec^22x  

4

−8cosec⁡2xcot⁡x−4sec⁡22x-8\operatorname{cosec}^2x\cot x-4\sec^22x  

14

Multiple Choice

Given  y=2cot⁡(1−2x)+34sin⁡xy=2\cot\left(1-2x\right)+\frac{3}{4}\sin x  .To find  dydx\frac{dy}{dx}  , suitable PIT-STOP to be used are

1

Chain Rule, Direct 

2

Direct,Chain Rule

3

Chain Rule, Chain Rule

4

Power Rule,Chain Rule

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Multiple Choice

Given  y=2cot⁡(1−2x)+34sin⁡xy=2\cot\left(1-2x\right)+\frac{3}{4}\sin x  ,find  dydx\frac{dy}{dx}  .

1

4cosec⁡2(1−2x)+34cos⁡x4\operatorname{cosec}^2\left(1-2x\right)+\frac{3}{4}\cos x   

2

−4cosec⁡2(1−2x)+34cos⁡x-4\operatorname{cosec}^2\left(1-2x\right)+\frac{3}{4}\cos x  

3

−2cosec⁡2(1−2x)+34cos⁡x-2\operatorname{cosec}^2\left(1-2x\right)+\frac{3}{4}\cos x

4

2cosec⁡2(1−2x)+34cos⁡x2\operatorname{cosec}^2\left(1-2x\right)+\frac{3}{4}\cos x

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​LEVEL 2:
COMBINATION OF PIT-STOP 1+2+3
with
other Rules
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​Instruction...

​For each of the question,

you are required to find y' followed by y''

18

Multiple Choice

Find  y′y'  of  y=sin⁡ (x2+1)y=\sin\ \left(x^2+1\right)  

1

cos⁡(x2+1)\cos\left(x^2+1\right)  

2

2xcos⁡(x2+1)2x\cos\left(x^2+1\right)

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Multiple Choice

Find  y′′y^{''}   for  y=sin⁡(x2+1)y=\sin\left(x^2+1\right)  

1

2cos⁡(x2+1)−2xsin⁡(x2+1)2\cos\left(x^2+1\right)-2x\sin\left(x^2+1\right)  

2

2cos⁡(x2+1)+2xsin⁡(x2+1)2\cos\left(x^2+1\right)+2x\sin\left(x^2+1\right)  

3

2cos⁡(x2+1)−4x2sin⁡(x2+1)2\cos\left(x^2+1\right)-4x^2\sin\left(x^2+1\right)  

4

2cos⁡(x2+1)+2xsin⁡(x2+1)2\cos\left(x^2+1\right)+2x\sin\left(x^2+1\right)

20

Multiple Choice

Given  y=sin⁡xcos⁡3xy=\sin x\cos3x  , find  y′y'  

1

cos⁡3xcos⁡x+sin⁡3xsin⁡x\cos3x\cos x+\sin3x\sin x  

2

−3sin⁡3xsin⁡x+cos⁡3xcos⁡x-3\sin3x\sin x+\cos3x\cos x  

3

cos⁡xcos⁡3x−sin⁡xsin⁡3x\cos x\cos3x-\sin x\sin3x  

4

cos⁡3xcos⁡x+3sin⁡3xsin⁡x\cos3x\cos x+3\sin3x\sin x  

21

Multiple Choice

Given  y=sin⁡xcos⁡3xy=\sin x\cos3x  , find  y′′y''  

1

−6sin⁡3xcos⁡x−10cos⁡3xsin⁡x-6\sin3x\cos x-10\cos3x\sin x  

2

−4sin⁡xcos⁡3x−4sin⁡3xcos⁡x-4\sin x\cos3x-4\sin3x\cos x  

3

−2sin⁡3xcos⁡x−2cos⁡3xsin⁡x-2\sin3x\cos x-2\cos3x\sin x  

4

−8cos⁡3xsin⁡x-8\cos3x\sin x  

22

Multiple Select

Find  y′y'  of  y=(tan⁡3x)2y=\left(\tan3x\right)^2   

1

2tan⁡3xsec⁡23x2\tan3x\sec^23x  

2

6tan⁡3xsec⁡23x6\tan3x\sec^23x  

3

6tan⁡3x(sec⁡3x)26\tan3x\left(\sec3x\right)^2  

4

2tan⁡3x2\tan3x  

23

Multiple Choice

Find  y′′y''  of  y=(tan⁡3x)2y=\left(\tan3x\right)^2   

1

18sec⁡43x+36sec⁡23xtan⁡23x18\sec^43x+36\sec^23x\tan^23x  

2

6sec⁡43x+12sec⁡23xtan⁡3x6\sec^43x+12\sec^23x\tan3x  

3

18sec⁡43x+12tan⁡3xsec⁡3x18\sec^43x+12\tan3x\sec3x  

4

18sec⁡43x+12sec⁡23xtan⁡23x18\sec^43x+12\sec^23x\tan^23x  

24

Multiple Choice

Find  y′y'  for  y=−cosec⁡2xy=-\operatorname{cosec}2x  

1

−2cosec⁡2xcot⁡2x-2\operatorname{cosec}2x\cot2x  

2

2cosec⁡2xcot⁡2x2\operatorname{cosec}2x\cot2x  

3

−cosec⁡2xcot⁡2x-\operatorname{cosec}2x\cot2x  

4

cosec⁡2xcot⁡2x\operatorname{cosec}2x\cot2x  

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Multiple Choice

Find y′′y''  for y=−cosec⁡2xy=-\operatorname{cosec}2x  

1

−2cosec⁡2xcot⁡22x−4cosec⁡32x-2\operatorname{cosec}2x\cot^22x-4\operatorname{cosec}^32x  

2

−4cosec⁡2xcot⁡22x−4cosec⁡32x-4\operatorname{cosec}2x\cot^22x-4\operatorname{cosec}^32x  

3

−2cot⁡22xcosec⁡2x−2cosec⁡32x-2\cot^22x\operatorname{cosec}2x-2\operatorname{cosec}^32x  

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​Hope it went well! review the ones you had trouble. Remember lecturer is watching ur progress :)
pattern-tertiary
Trigo4:Combination

by Thavarajah Selvarajah

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