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Chapter 2.1 - Distance

Chapter 2.1 - Distance

Assessment

Presentation

Mathematics

University

Hard

Created by

Katherine Morris

Used 2+ times

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3 Slides • 4 Questions

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Chapter 2.1 - Distance

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​Distance Formula

  • Distance can be found by picturing a right triangle

  • Find points with |A – B| or |B – A|

  • Horizontal leg of the triangle can be found |x2 – x1|

  • Vertical leg of the triangle can be found |y2 – y1|

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Multiple Choice

What is the distance between the two points: (-5, 1) and (7, -3)?

First, we need to identify x1, x2, y1, and y2. Which is correct?

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(-5, 1) and (7, -3)

(x1, y1) and (x2, y2)

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(-5, 1) and (7, -3)

(x1, x2) and (y1, y2)

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(-5, 1) and (7, -3)

(y1, x2) and (y2, x1)

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(-5, 1) and (7, -3)

(x1, y2) and (x2, y1)

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Multiple Choice

What is the distance between the two points: (-5, 1) and (7, -3)?

Next, we need to use the distance formula. What is it?

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(x2x2)2+(x1x1)2\sqrt[]{\left(x_2-x_2\right)^2+\left(x_1-x_1\right)^2}  

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(x2y1)2+(y2x1)2\sqrt[]{\left(x_2-y_1\right)^2+\left(y_2-x_1\right)^2}  

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(x2x1)2+(y2y1)2\sqrt[]{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}  

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(y2x1)2+(x2y1)2\sqrt[]{\left(y_2-x_1\right)^2+\left(x_2-y_1\right)^2}  

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Multiple Choice

What is the distance between the two points: (-5, 1) and (7, -3)?

Next, we need to plug the points into the distance formula. What is it?

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(75)2+(31)2\sqrt[]{\left(7-5\right)^2+\left(-3-1\right)^2}  

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(7y(5))2+(31)2\sqrt[]{\left(7-y\left(-5\right)\right)^2+\left(-3-1\right)^2}  

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(31)2+(75)2\sqrt[]{\left(-3-1\right)^2+\left(7-5\right)^2}  

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(57)2+(13)2\sqrt[]{\left(-5-7\right)^2+\left(-1-3\right)^2}  

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Multiple Choice

What is the distance between the two points: (-5, 1) and (7, -3)?

When we do the math, we get 160\sqrt[]{160}  . What is the exact answer?

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160\sqrt[]{160}  

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12.6512.65  

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16 1016\ \sqrt[]{10}  

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4 104\ \sqrt[]{10}  

Chapter 2.1 - Distance

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