
Gas Laws
Presentation
•
Chemistry
•
10th Grade
•
Medium
Mihir Paranjape
Used 34+ times
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6 Slides • 6 Questions
1
Gas Laws
By Mihir Paranjape
2
Pressure
Pressure = Force/Area
Pressure in a gas is caused by the collisions of gas molecules with the walls of the container. The molecules are constantly moving in random directions and exert a force when they collide with a wall. Pressure is the result of millions of collisions occurring between the Gas molecules and the wall of the container. Faster the molecules move, the more force they will exert and cause an increase in pressure.
3
Pressure Conversions
There are many units of Pressure, we use atmospheres or atm in Chemistry.
4
Combined Gas Law.
A certain flexible weather balloon contains 5.9 L of helium gas. Initially, the temperature is 20.4oC and the barometric pressure is 560.6 torr. The balloon then is taken to the top of Pike’s Peak, where the pressure is 400 torr and the temperature is 9.7oC. What is the new volume of the balloon at the top of Pikes Peak?
Some text here about the topic of discussion
| 1 | 2 |
|---|---|---|
P | 560.6 | 400 |
V | 5.9 | ? |
T | 20.4+273 = 293.4 | 9.7+273 = 282.7 |
560.6 x 5.9 = 400 x V2
293.4 282.7
3307.54 = 400 x V2
293.4 282.7
V2 = 7.97 L
5
Multiple Choice
6
Multiple Choice
7
Multiple Choice
What is the pressure of a car tire that had an initial pressure of 1.8 atm but was heated from 38°C to 123°C?
0.9 atm
2.1 atm
1.6 atm
3.4 atm
8
Ideal Gas Law
If we are given only one value of P, V or T, we are talking about the ideal gas law.
P = atm, V = L, T = K, R = 0.0821
n = number of moles of a gas.
You can plug the values in and solve for the unknown variable.
Make sure to convert all values into proper units.
9
Ideal Gas Law
A Flask with 5.9 L of volume at 6.1 psi Pressure contains 0.36 moles of a gas. What is the Temperature in the Flask in K?
P = 6.1 psi = 6.1/14.7 = 0.415 atm
V = 5.9 L
n = moles = 0.36
T = ?
0.415 x 5.9 = 0.36 x 0.0821 x T
T = 82.8 K
10
Multiple Choice
11
Multiple Choice
12
Multiple Choice
PV=nRT
Gas Laws
By Mihir Paranjape
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