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1.9 Distance and Midpoint Formula; Circles

1.9 Distance and Midpoint Formula; Circles

Assessment

Presentation

Mathematics

11th Grade

Medium

CCSS
HSG.GPE.A.1, HSG.GPE.B.7, HSG.GPE.B.6

Standards-aligned

Created by

Larry Cooper

Used 5+ times

FREE Resource

22 Slides • 14 Questions

1

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1.9 Distance and Midpoint; Circles

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"Success is the sum of Small Efforts repeated day in and day out."

- R. Collier

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Multiple Choice

The distance between A(3,1) and B(-2,-1) written correctly is: #1

1

d=(23)2 + (11)2d=\sqrt{\left(-2-3\right)^2\ +\ \left(-1-1\right)^2}

2

d=(13)2 + (12)2d=\sqrt{\left(1-3\right)^2\ +\ \left(-1-2\right)^2}

3

d=(23)2  (11)2d=\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}

4

d=(23)2  (11)2d=\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}

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Multiple Choice

Find the distance between the points (4, 3) and (0,6). #2

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3

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4

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Fill in the Blank

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Find the distance d(P1, P2) between the points P1 and P2. Round the answer to the tenth place. #3 

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Multiple Choice

Find the distance between the pair of points R(-4, 1) and F(0, -2). #6

1

5

2

8.60

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7

4

9.22

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11

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Multiple Choice

What is the midpoint between (3, -1) and (8, -6)? #12

1

(11, -7)

2

(-5.5, -3.5)

3

(5.5, -3.5)

4

(2, -2)

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Multiple Choice

Find the midpoint of the line segment joining the points P1 and P2. #13

P1 = (-4, -3); P2 = (2, 2)

1

(1,12)\left(-1,-\frac{1}{2}\right)

2

(1,12)\left(1,\frac{1}{2}\right)

3

(1,12)\left(1,-\frac{1}{2}\right)

4

(1,12)\left(-1,\frac{1}{2}\right)

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Multiple Choice

Find the midpoint of the segment with the endpoints:(4, 12) and (-6, 14). #15

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(-1, 13)
2
(13, 1)
3
(13, -1)
4
(5, 13)

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Multiple Choice

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In the diagram, a circle centered at the origin, a right triangle, and the Pythagorean theorem are used to derive the equation of a circle, x2 + y2 = r2.

If the center of the circle were moved from the origin to the point (h, k) and point P at (x, y) remains on the edge of the circle, which could represent the equation of the new circle?

#22

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(h + x)2 + (k + y)2 = r2

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(x – h)2 + (y – k)2 = r2

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k + x)2 + (h + y)2 = r2

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(x – k)2 + (y – h)2 = r2

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Multiple Choice

What are the coordinates of the center and the radius of the circle with the equation:

(x - 4)2 + (y - 3)2 = 25 ? #23

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Center (4,3)

Radius = 5 units

2

Center (4,3)

Radius = 25 units

3

Center (-4,-3)

Radius = 25 units

4

Center (-4,-3)

Radius = 5 units

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Multiple Choice

What is the equation of the circle, with center (-2,-7) and radius 3 units? #24

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(x + 2)2 + (y + 7)2 = 3

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(x - 2)2 + (y - 7)2 = 9

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(x + 2)2 + (y + 7)2 = 9

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(x - 2)2 + (y - 7)2 = 3

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Multiple Choice

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Which graph corresponds to

x2+ (y-6)2=9? #26

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A

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B

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C

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D

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Multiple Choice

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Which graph corresponds to

(x-4)2+ (y+4)2=25? #27

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A

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B

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C

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D

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Completing the Square

Why do we sometimes need to complete the square?

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Multiple Choice

What is the center of a circle whose equation is xy2 – 12x – 2+ 12 = 0? #29

1

(–12, –2)

2

(–6, –1)

3

(6, 1)

4

(12, 2)

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Multiple Choice

Change the following equation to standard form

x2+y2-4x+12y-8=0. #34

1

(x-2)2+(y-6)2=48

2

(x-2)2+(y+6)2=48

3

(x-6)2+(y-2)2=48

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(x+2)2+(y-6)2=48

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1.9 Distance and Midpoint; Circles

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"Success is the sum of Small Efforts repeated day in and day out."

- R. Collier

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