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Applications of Linear Systems:  Standard Form

Applications of Linear Systems: Standard Form

Assessment

Presentation

Mathematics

8th Grade

Medium

CCSS
8.EE.C.8B, HSA.CED.A.3, 8.EE.C.8C

+2

Standards-aligned

Created by

Jennifer Ferrara

Used 9+ times

FREE Resource

5 Slides • 16 Questions

1

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2

Multiple Choice

Choose the equation that represents STANDARD FORM

1

y = mx + b

2

Ax + By = C

3

y - y1 = m(x - x1)

4

y = Ax + By

3

Multiple Choice

Which equation is written in STANDARD form?
1

y = 1/2x + 2

2

y - 3 = -5(x + 2)

3

7x + 2y = 9

4

3x + 2 = y

4

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Warm-Up
&
Review

5

Multiple Choice

5x + y = 4

6x + 2y = 1

Explain how to achieve COMMON COEFFICIENTS in the system.

Common Coefficients: opposite numbers OR the same numbers

1

Multiply the TOP equation by 2 or -2.

2

Multiply the TOP equation by 6 or -6.

3

Multiply the BOTTOM equation by 5 or -5.

4

Multiply the BOTTOM equation by 4 or -4.

6

Multiple Choice

Choose one way to achieve common coefficients in the system.

6x + 3y = 5

5x - 4y = 10

1

Multiply the top equation by 6 and the bottom by 5.

2

Multiply the top equation by 3 and the bottom by -4.

3

Multiply the top equation by 4 and the bottom by 3.

4

Multiply the top equation by -5.

7

Multiple Choice

Choose the strategy to solve the system by elimination.

-15x - 4y = 11

5x + 4y = -14

1

Add to eliminate y

2

Add to eliminate x

3

Subtract to eliminate y

4

Subtract to eliminate x

5

none of these

8

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Page 25 - Unit 6

Oil Change Problem

9

Multiple Choice

Question image

DEFINE THE VARIABLES.

The total charge for an oil change at a service center includes a fee (x) for the oil change service and the cost of oil. Each quart of oil costs y dollars.

1

x = oil change fee

y = Cost for 1 quart of oil

2

x = Cost for 1 quart of oil

y = oil change fee

3

x = total charge for the oil change

y = # of quarts of oil

10

Multiple Choice

Question image

WRITE AN EQUATION.

The RED car required 7 quarts of oil. The total cost of the oil change was $66.35.

x = oil change fee

y = Cost for 1 quart of oil

1

7x+y=66.357x+y=66.35  

2

x+y=66.35x+y=66.35  

3

x+7y=66.35x+7y=66.35  

11

Multiple Choice

Question image

WRITE AN EQUATION.

The BLUE car required 5 quarts of oil. The total cost of the oil change was $55.39.

x = oil change fee

y = Cost for 1 quart of oil

1

5x+y=55.395x+y=55.39  

2

x+5y=55.39x+5y=55.39  

3

y=5x+55.39y=5x+55.39  

12

Multiple Choice

Question image

x+7y=66.42x+7y=66.42  

x+5y=55.39x+5y=55.39  

What strategy could be used to solve the system?

1

Subtract to eliminate x.

2

Add to eliminate x.

3

Subtract to eliminate y.

4

Add to eliminate y.

13

Multiple Choice

Question image

x+7y=66.35x+7y=66.35  

x+5y=55.39x+5y=55.39  

Subtract and solve for y.

1

12y=121.7812y=121.78  

y=10.15y=10.15  

2

2y=121.782y=121.78  

y=60.89y=60.89  

3

2y = 10.962y\ =\ 10.96  

y=5.48y=5.48  

14

Multiple Choice

Question image

x+7y=66.35x+7y=66.35  

x+5y=55.39x+5y=55.39  

y = 5.48y\ =\ 5.48  

Solve for x.

1

 

x=27.99x=27.99   

2

 

x=9.98x=9.98   

3

x=8.84x=8.84  

15

Multiple Choice

Interpret the solution.

x = 27.99, y = 5.48

1

The fee for an oil change is $5.48 and the cost for oil is $27.99.

2

The fee for an oil change is $27.99 and the cost per quart of oil is $5.48.

3

The total cost of an oil change is $27.99.

16

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Page 26 Problem #1

The Culinary Shop

17

Multiple Choice

Question image

Write a system to represent Problem #1 on page 26.

1

2x+2y=176.502x+2y=176.50

x+3y=163.25x+3y=163.25

2

2x+2y=176.502x+2y=176.50

3x+y=163.253x+y=163.25

3

2x+2y=163.252x+2y=163.25

x+3y=176.50x+3y=176.50

18

Open Ended

Explain how you would multiply one or both equations to achieve common coefficients.

2x+2y=176.502x+2y=176.50

x+3y=163.25x+3y=163.25

19

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Page 26, Problem #2

Water

Wizz

20

Multiple Choice

Question image

Write a system of equations to represent problem #2 on page 26.

1

5c+22s=10905c+22s=1090

3c+15s=7353c+15s=735

2

5x+22y=10905x+22y=1090

3x+15y=7353x+15y=735

3

5c+22s=7355c+22s=735

3c+15s=10903c+15s=1090

21

Open Ended

Explain how to multiply and achieve common coefficients.

5c+22s=10905c+22s=1090

3c+15s=7353c+15s=735

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