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5.2

5.2

Assessment

Presentation

Chemistry

10th Grade

Hard

Created by

Ray Dennis

FREE Resource

10 Slides • 10 Questions

1

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2

Solution

p1v1=p2v2

v2=p1v1/p2

v2=(3.2)(2)/(1)

v2=6.4

3

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4

Solution

p1v1=p2v2

p2=p1v1/v2

p2=(1.5)(5.6)/(4.8)

p2=1.75

5

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6

Solution

p1v1/t1=p2v2/t2 k=273+c

v2=p1v1t2/t1p2

v2=(120000)(276)/(288)(150)

v2=766.67

7

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8

Solution

p1v1/t1=p2v2/t2 k=273+c

v2=p1v1t2/t1p2

v2=(1.05)(5)(258)/(293)(0.65)

v2=7.11

9

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10

Solution

p1/t1=p2/t2 k=273+c

p2=p1t2/t1

p2=(1200)/(273)

p2=4.396

11

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12

Solution

p1/t1=p2/t2 k=273+c

t2=p2t1/p1

t2=(100)(293)/(136)

t2=215.441

13

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14

Solution

p1/t1=p2/t2 k=273+c

p2=p1t2/t1

p2=(1.2)(253)/(293)

p2=1.04

15

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16

Solution

p1v1/t1=p2v2/t2 k=273+c

v2=p1v1t2/t1p2

v2=(1.2)(2)(438)/(293)(1) [no balloon = no pressure]

v2=3.59

17

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18

Solution

p1v1/t1=p2v2/t2 k=273+c

v2=p1v1t2/t1p2

v2=(13)(217)(3)/(293)(1.3*10-16)

v2=2.22*1017

19

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20

Solution

p1/t1=p2/t2

p2=p1t2/t1

p2=(9.6)(2473)/(197)

p2=120.512

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