
Solubility
Presentation
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Science
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12th Grade
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Practice Problem
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Medium
Michael Broadhead
Used 12+ times
FREE Resource
46 Slides • 11 Questions
1
2
3
Take a moment to read through the summary and ask questions if any part is confusing.
4
Multiple Choice
Which of the following is an ionic compound?
KCl
CH4
CO2
H2O
5
Categorize
NaCl
CuCl2
C6H12O6
O2
CH4
NaNO3
6
Solutions are made when you dissolve a chemical called solute into another chemical called the solvent.
7
Explore this simulation to compare how salt (NaCl, ionic) and sugar (C12H22O11, covalent)
Ionic compounds dissociate into individual ions.
Covalent compounds form molecular solutions, where atoms remain part of molecules.
8
Draw
Draw how LiF would dissolve in water.
9
Draw
Draw how CO2 would dissolve in water.
10
Electrolytes: Electrolytes are solutions that conduct electricity. Materials are only able to conduct electricity if there have:
Freely moving cations (ie, Ca2+, NH4+)
Freely moving anions (ie, Cl-, SO42-)
Freely moving electrons (negatively charged)
11
Categorize
LiCl
FeCl3
Soluble Ionic Compound
Conducts electricity.
O2
H2O
Does not conduct electricity.
Covalent compounds.
Sort the following:
12
Soluble ionic compounds are electrolytes, while most covalent compounds are non-electrolytes (except weak acids, covered in next unit).
Ionic(aq) = electrolyte
Anything else = nonelectrolyte
13
In general the concentration is measured as:
14
Concentration Terminology:
Dilute Solution (Unsaturated): Small amount of solute in a large amount of solvent.
Concentrated Solution (Unsaturated): Lots of solute in a small amount of solvent (all dissolves).
15
Saturated Solution: The maximum amount of solute dissolved in a given amount of solvent at a given temperature. To make a saturated solution you add more solute than can be dissolved.
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Multiple Choice
Numbering from the left, which is most dilute?
1
2
3
4
5
17
Multiple Choice
How do you know if a solution is saturated?
When you see some undissolved solute at the bottom that doesn't disappear if you stir it.
When it is darker colored.
When it is transparent.
When you can dissolve more solute if you stir it.
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To calculate concentration we can use this formula:
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What is the molarity of a NaCl solution in which 0.17 mol of NaCl is dissolved to make a 2 L solution?
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21
Fill in the Blanks
What is the concentration (M) of 0.520 mol of CaBr2 dissolved in 500 mL of solution?
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Fill in the Blanks
What is the concentration of a KNO3 solution in which 2.13 g is dissolved in 200 mL of solution?
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Once we write a balanced dissociation equation, we can use the coefficients to calculate the concentration of the ions if we assume the solute fully dissociates.
1NaCl → 1Na+(aq) + 1Cl-(aq)
For every 1 NaCl dissolved,
1 Na+ and 1Cl- are produced.
CaCl2 → Ca2+(aq) + 2Cl-(aq)
For every 1 CaCl2 dissolved,
1 Ca2+ and 2 Cl- are produced.
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While all substances have solubility to a certain extent, the course defines soluble if it will form a 0.1 M or higher solution at 25 degrees Celsius. Below that = insoluble.
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You try #38 to 48.
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Double displacement reactions that produce a precipitate. For a precipitation reaction to occur, 2 conditions must be met:
Both reactants must be soluble ionic compounds
At least 1 of the new ionic compounds produced must be insoluble.
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31
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Step 1: Write out both reactants, using criss-cross method to predict formulas if given names only.
Step 2: Check that both reactants are soluble. If not, stop here as there will be no reaction when mixed.
Step 3: Swap the cations and ions using the criss-cross method to predict the formulas of two new ionic compounds.
Step 4: Check the solubility, at least one must be insoluble (precipitate).
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You Try #57 - 72
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Complete ionic equations are when you write soluble ionic compounds as separate ions rather than as a compound:
Spectator Ions: In a full ionic equation, soluble ions that appear as both products and reactants are called spectator ions. This is because they do not participate in a reaction producing a precipitate.
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Write complete ionic equations for the following & identify the spectator ions.
Hint: Ensure everything is balanced!
36
You try #73 - 77
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Precipitation reactions can be used to separate soluble ions from one another. By making one ion precipitate, we can then filter accordingly.
The filtrate will contain the soluble ion(s)
The residue caught in the filter will hold the insoluble ion.
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39
Note: it won't go perfectly, but gives the idea.
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You Try #78 - 87, 111 - 119
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As saturated solutions are at equilibrium, Le Chatelier’s Principle can be applied to predict which side will be favored (shifted to) if a stress is added.
No effect
left
right
right
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You Try #88 to 110
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When a saturated solution is at equilibrium, we can calculate an equilibrium constant as shown below:
You Try: Problems 123 to 128
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They are summarized in the data booklet. Just as with the equilibrium constant:
a large Ksp means equilibrium lies to the right (the substance is highly soluble).
a small Ksp means equilibrium lies to the left (the substance is insoluble)
You Try #49 to 56
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Step 1: Write the dissociation equation & balance it.
Step 2: Write the Ksp expression.
Step 3: Substitute in the concentrations, taking into account the mole ratios.
Try Problems
129 to 143
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Step 1: Write the dissociation equation & balance it.
Step 2: Let x = concentration of each ion & multiply each by coefficient.
Step 3: Write the Ksp expression & substitute in the concentrations (in terms of x)
Step 4: Evaluate using algebra.
You Try 145 to 152
48
In the previous question, calculate the mass of Ag2CrO4 dissolved in 500 mL of saturated solution (in other words, maximum mass that can be dissolved). Continue steps of previous question...
Step 5: Multiply [ CrO42- ] by volume to get moles. n=cV
Step 6: Moles of CrO42- = moles Ag2CrO4 due to 1:1 mole ratio.
Step 7: Convert to mass using m = nM
You Try: 144, 161
49
To calculate new concentrations after chemicals are combined, we use this equation:
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51
Fill in the Blanks
What volume (in mL) of 5 M NaOH is needed to create a 100 mL solution of 1 M NaOH?
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Qsp is like Q for K. Qsp uses non-equilibrium concentrations, while Ksp uses equilibrium concentrations. The expressions are the same and just like with Q and K, we compare the values to determine which side the system will shift towards.
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Multiple Choice
If Ksp = 1.4 x 10-12, will a precipitate form if Qsp is found to be 1.4 x 10-5?
Yes
No
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55
56
You Try: 153 to 160
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You Try: 161 to 168
What is maximum [Ca2+] in a 0.10 M solution of Na2SO4 without a precipitate forming?
Step 1: Determine what precipitate forms.
Step 2: Write the dissociation equation & balance it.
Step 3: Substitute in the Ksp (from data booklet), the given concentration & assign “x” to the unknown.
Step 4: Use algebra to solve
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