
Concavity and The Second Derivative Test Lesson
Presentation
•
Mathematics
•
10th Grade
•
Easy
Standards-aligned
Larry Cooper
Used 5+ times
FREE Resource
17 Slides • 24 Questions
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"Life is always in session. That is why you always have to pay attention to the lesson."
By. Mr. C.
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Match
Match the following. #8
Finding a derivative means...
Evaluating an integral means...
The 1st Derivative Test uses...
The 2nd Derivative Test uses...
Critical points are...
finding the slope of a tangent line.
finding the area under a curve.
the first derivative to determine if a critical point is a local extrema and if so what type.
the 2nd derivative to determine if a critical point is a local extrema and if so what type.
where the 1st derivative equals 0 or is undefined.
finding the slope of a tangent line.
finding the area under a curve.
the first derivative to determine if a critical point is a local extrema and if so what type.
the 2nd derivative to determine if a critical point is a local extrema and if so what type.
where the 1st derivative equals 0 or is undefined.
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Multiple Choice
The concavity of a function is described by its _______________. #1
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Multiple Choice
What will be true at an inflection point? (select the best answer) #2
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Multiple Choice
For a function g(x), g''(3)=-8 indicates that g(x) is ____________ at x=3. #3
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Multiple Choice
If f''(x)>0, then what will be true about f'(x) over that same interval? #4
f '(x) is constant
f '(x) is increasing
f '(x) is decreasing
f '(x) must have an inflection point in that interval
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Multiple Choice
f(x) is pictured. Inflection points are most likely at which x values? #5
x=0 and 1.5
x=2 and 2.5
x=2.25
x=1
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Multiple Choice
Which of the following describes an interval of f(x) that is both decreasing and concave up? #6
f '(x) < 0 and f "(x) < 0
f '(x) < 0 and f "(x) > 0
f '(x) > 0 and f "(x) > 0
f '(x) > 0 and f "(x) < 0
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Multiple Choice
Find the second derivative of the function: #7
f (x) = 2x - 5x6
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Multiple Choice
Where is the point of inflection for the function f(x)=x3+6x2 ? #9
x=0
x=−4
x=−2
x=2
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Multiple Choice
Determine the concavity of the function: f(x)=x4−6x3−60x2+5x−12 Determine when the function is concave DOWN (interval notation). #10
(−∞,−2) and (5,∞)
(−∞,−2)
(−2,5)
(5,∞)
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Multiple Choice
If the function f has a critical number at x=3 and f′′(3)=5 which of the following would be true? #11
f has a local maximum at x=3
f has a local minimum at x=3
f has neither a local maximum or minimum at x=3
there is not enough information to know if there is a local maximum or minimum at x=3
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Multiple Choice
What does the concept of concavity mean in calculus? #12
Concavity in calculus refers to the color of the graph
Concavity in calculus refers to the number of x-intercepts on the graph
Concavity in calculus refers to the length of the graph
Concavity in calculus refers to the shape of a graph, specifically whether the graph is curving upwards (concave up) or downwards (concave down).
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Multiple Choice
How do you use the second derivative to find inflection points? #14
By finding the integral of the function and using the concavity test to determine potential inflection points.
By finding the second derivative of the function and using the concavity test to determine potential inflection points.
By finding the first derivative of the function and using the concavity test to determine potential inflection points.
By finding the average rate of change of the function and using the concavity test to determine potential inflection points.
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Multiple Choice
What are inflection points in calculus? #13
Inflection points are points where the curve intersects the x-axis
Inflection points are points where the curve intersects the y-axis
Inflection points are points where the curve is at its highest or lowest
Inflection points in calculus are points on a curve where the concavity changes, indicating a change in the direction of the curve's curvature.
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Multiple Choice
Which of the following uses the 2nd Derivative Test for relative extrema correctly? #20
f'(c)=0.
f''(c)>0.
Thus, f(x) must have a relative maximum at x=c.
f'(c)=0.
f''(c)<0.
Thus, f(x) must have a relative minimum at x=c.
f'(c)=0.
f''(c)>0.
Thus, f(x) must have a relative minimum at x=c.
f''(c)=0.
f''(x) changes from + to - at x=c.
Thus, f(x) has a point of inflection at x=c.
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Multiple Choice
Find the point(s) of inflection (if it exists) of the function:
f(x)=2x3+6x2−4 #26
Where x = -1
Where x = 1
Where x = - 2
Where x = 0
No point of inflection
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Multiple Choice
For a function f(x), f''(4)=0 indicates that x=4 is _____________. #27
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Multiple Choice
Find the concavity of the function f(x)=17e(6x) when x=3 ...#33
the function is concave upward
the function is concave downward
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Multiple Choice
Find the second derivative of f(x) = x2 + ex - cosx. #39
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Multiple Select
Find the point(s) of inflection (if it exists) of the graphed function. #46
No point of inflection
Points C, D and E
Points A, C, E and G
Points A, B, C, D, E, F and G
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Multiple Select
Find the point(s) of inflection (if it exists) of the graphed function. #47
No point of inflection
Points A and B
Points A, B and Z
Points X, A, Y, B, Z
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Match
Match the following functions with their derivatives. #55
f(x) = sin x
f(x) = cos x
f(x) = tan x
f(x) = sec x
f(x) = csc x
f'(x) = cos x
f'(x) = -sin x
f'(x) = sec 2 x
f'(x) = sec x tan x
f'(x) = -csc x cot x
f'(x) = cos x
f'(x) = -sin x
f'(x) = sec 2 x
f'(x) = sec x tan x
f'(x) = -csc x cot x
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Multiple Choice
dxdf(g(x)) #56
f′(g(x))g′(x)
f′(x)g(x)+f(x)g′(x)
f′(g′(x))
f′(g′(x))g(x)
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Match
Match the following derivative rule with the function. #52
f(x) = x2sinx
f(x) = x+1x2−x
f(x) = x
f(x) = sin (2x)
f(x) = 2x cos (3x-1)
product rule
quotient rule
power rule
chain rule
product & chain rules
product rule
quotient rule
power rule
chain rule
product & chain rules
"Life is always in session. That is why you always have to pay attention to the lesson."
By. Mr. C.
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