Search Header Logo
Limit Fungsi Aljabar

Limit Fungsi Aljabar

Assessment

Presentation

•

Mathematics

•

12th Grade

•

Practice Problem

•

Hard

Created by

Novita Sari

FREE Resource

5 Slides • 110 Questions

1

Multiple Choice

lim⁡x→−5 ⁡(2x4+3x3−25)\lim_{x\rightarrow-5}\ ⁡(2x^4+3x^3-25)  adalah ....

1

1.650

2

1.600

3

1.400

4

875

5

850

2

Multiple Choice

Nilai lim⁡x→1 x2 − 5x + 4x − 1 \lim_{x\rightarrow1}\ \frac{x^2\ -\ 5x\ +\ 4}{x\ -\ 1}\  adalah ....

1

− 5-\ 5

2

− 4-\ 4

3

− 3-\ 3

4

00

5

55

3

Multiple Choice

lim⁡x→16 x − 4x − 16\lim_{x\rightarrow16}\ \frac{\sqrt{x}\ -\ 4}{x\ -\ 16}  = ....

1

00

2

18\frac{1}{8}

3

14\frac{1}{4}

4

12\frac{1}{2}

5

∞\infty

4

Multiple Choice

lim⁡x→2 x2−42x2+4x−16 =....\lim_{x\rightarrow2}\ \frac{x^2-4}{2x^2+4x-16}\ =....  

1

0

2

14\frac{1}{4}  

3

13\frac{1}{3}  

4

12\frac{1}{2}  

5

1

5

Multiple Choice

Question image
1

-2

2

-1

3

1

4

2

5

4

6

Multiple Choice

lim⁡x→2  x2−5x+6x2+2x−8 = ....\lim_{x\rightarrow2}\ \ \frac{x^2-5x+6}{x^2+2x-8}\ =\ ....  

1

2

2

1

3

16\frac{1}{6}  

4

−16-\frac{1}{6}  

5

−112-\frac{1}{12}  

7

Multiple Choice

tentukan hasil dari lim⁡x→1(x−2x+3)=\lim_{x\rightarrow1}\left(\frac{x-2}{x+3}\right)=  

1

−23-\frac{2}{3}  

2

−14-\frac{1}{4}  

3

12\frac{1}{2}  

4

23\frac{2}{3}  

5

1

8

Multiple Choice

Nilai dari

lim⁡x→−4 x2−6x+8x−4=....\lim_{x\rightarrow-4}\ \frac{x^2-6x+8}{x-4}=....  

1

-6

2

0

3

2

4

6

5

8

9

Multiple Choice

lim⁡x→1 2x2−x−33x2+8x+5=\lim_{x\rightarrow1}\ \frac{2x^2-x-3}{3x^2+8x+5}=  

1

−18-\frac{1}{8}  

2

314\frac{3}{14}  

3

23\frac{2}{3}  

4

−45-\frac{4}{5}  

5

2

10

Multiple Choice

lim⁡x→3 x2−10x+21x2−9=\lim_{x\rightarrow3}\ \frac{x^2-10x+21}{x^2-9}=  

1

−43-\frac{4}{3}  

2

−23-\frac{2}{3}  

3

00  

4

23\frac{2}{3}  

5

-1

11

Multiple Choice

lim⁡x→5 10 =.....\lim_{x\rightarrow5}\ 10\ =.....  

1

0

2

5

3

10

4

20

5

25

12

Multiple Choice

lim⁡x→3 2x+4= .....\lim_{x\rightarrow3}\ 2x+4=\ .....  



1

6

2

8

3

9

4

10

5

12

13

Multiple Choice

lim⁡x→2 x2−4x−2=.....\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}=.....  

1

0

2

4

3

∼\sim  

4

−2-2  

5

−4-4  

14

Multiple Choice

lim⁡x→2(2x3+5x2+2x+1)=....\lim_{x\rightarrow2}\left(2x^3+5x^2+2x+1\right)=....  

1

38

2

39

3

40

4

41

5

45

15

Multiple Choice

Nilai lim⁡x→1 x2 − 5x + 4x − 1 \lim_{x\rightarrow1}\ \frac{x^2\ -\ 5x\ +\ 4}{x\ -\ 1}\  adalah ....

1

− 5-\ 5

2

− 4-\ 4

3

− 3-\ 3

4

00

5

55

16

Multiple Choice

Question image
1

3

2

0

3

−3-3

4

− 6-\ 6

5

−8-8

17

Multiple Choice

lim⁡x→2 x2−42x2+4x−16 =....\lim_{x\rightarrow2}\ \frac{x^2-4}{2x^2+4x-16}\ =....  

1

0

2

14\frac{1}{4}  

3

13\frac{1}{3}  

4

12\frac{1}{2}  

5

1

18

Multiple Choice

lim⁡x→2  x2−5x+6x2+2x−8 = ....\lim_{x\rightarrow2}\ \ \frac{x^2-5x+6}{x^2+2x-8}\ =\ ....  

1

2

2

1

3

16\frac{1}{6}  

4

−16-\frac{1}{6}  

5

−112-\frac{1}{12}  

19

Multiple Choice

Nilai dari lim⁡x→5 3x2−4x=....\lim_{x\rightarrow5}\ 3x^2-4x=....  

1

45

2

55

3

60

4

65

5

70

20

Multiple Choice

Jika diketahui lim⁡x→a x2−3x+2x−2=1 \lim_{x\rightarrow a}\ \frac{x^2-3x+2}{x-2}=1\  , maka nilai dari a = ....

1

1

2

2

3

3

4

4

5

5

21

Multiple Choice

lim⁡x→5 10 =.....\lim_{x\rightarrow5}\ 10\ =.....  

1

5

2

10

3

0

4

50

22

Multiple Choice

lim⁡x→3 2x+4= .....\lim_{x\rightarrow3}\ 2x+4=\ .....  



1

6

2

8

3

10

4

9

23

Multiple Choice

lim⁡x→2 x2−4x−2=.....\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}=.....  

1

0

2

4

3

∼\sim  

4

-2

24

Multiple Choice

lim⁡x→2(2x3+5x2+2x+1)=....\lim_{x\rightarrow2}\left(2x^3+5x^2+2x+1\right)=....  

1

38

2

39

3

40

4

41

25

Multiple Choice

Nilai lim⁡x→1 x2 − 5x + 4x − 1 \lim_{x\rightarrow1}\ \frac{x^2\ -\ 5x\ +\ 4}{x\ -\ 1}\  adalah ....

1

− 5-\ 5

2

− 4-\ 4

3

− 3-\ 3

4

00

5

55

26

Multiple Choice

lim⁡x→4 3x3 − 48xx2 − 16\lim_{x\rightarrow4}\ \frac{3x^3\ -\ 48x}{x^2\ -\ 16}  adalah ....

1

44

2

1212

3

1616

4

2424

5

4848

27

Multiple Choice

lim⁡x→16 x − 4x − 16\lim_{x\rightarrow16}\ \frac{\sqrt{x}\ -\ 4}{x\ -\ 16}  = ....

1

00

2

18\frac{1}{8}

3

14\frac{1}{4}

4

12\frac{1}{2}

5

∞\infty

28

Multiple Choice

lim⁡x→6 2x + 4 − 3x − 2x − 6\lim_{x\rightarrow6}\ \frac{\sqrt{2x\ +\ 4}\ -\ \sqrt{3x\ -\ 2}}{x\ -\ 6}  = ....

1

14\frac{1}{4}

2

18\frac{1}{8}

3

00

4

− 116-\ \frac{1}{16}

5

− 18-\ \frac{1}{8}

29

Multiple Choice

lim⁡x→5 2x2−17x+35x−5=....\lim_{x\rightarrow5}\ \frac{2x^2-17x+35}{x-5}=....  

1

3

2

5

3

7

4

9

30

Multiple Choice

lim⁡x→3   2−x+1x−3 =....\lim_{x\rightarrow3}\ \ \ \frac{2-\sqrt{x+1}}{x-3}\ =....  

1

−14-\frac{1}{4}  

2

−12-\frac{1}{2}  

3

1

4

2

5

3

31

Multiple Choice

lim⁡x→0 5x3−9+x= ....\lim_{x\rightarrow0}\ \frac{5x}{3-\sqrt{9+x}}=\ ....  

1

-30

2

-27

3

15

4

27

5

30

32

Multiple Choice

lim⁡x→3 (−3x+9x2−9)\lim_{x\rightarrow3}\ \left(\frac{-3x+9}{x^2-9}\right)  

1

−35-\frac{3}{5}  

2

25\frac{2}{5}  

3

−39-\frac{3}{9}  

4

13\frac{1}{3}  

5

−12-\frac{1}{2}  

33

Multiple Choice


lim⁡x→0 (4x2−5x−1) adalah .....\lim_{x\rightarrow0}\ \left(4x^2-5x-1\right)\ adalah\ .....  

1

−5-5  

2

−1-1  

3

11  

4

44  

5

55  

34

Multiple Choice

lim⁡x→5(x+12x−4) adalah .....\lim_{x\rightarrow5}\left(\frac{x+1}{2x-4}\right)\ adalah\ .....  

1

2

2

3

3

4

4

1

5

5

35

Multiple Choice

lim⁡x→1x2−1x−1=....\lim_{x\rightarrow1}\frac{x^2-1}{x-1}=....  

1

2

2

3

3

4

4

5

5

6

36

Multiple Choice

Question image
1

-1

2

1

3

2/3

4

-1/2

5

-2/3

37

Multiple Choice

Question image
1

2

2

1

3

1/6

4

-1/6

5

6

38

Multiple Choice

Question image
1

-1

2

-1/2

3

8

4

-8

5

-3/2

39

Multiple Choice

lim⁡x→2 x2−42x2+4x−16 =....\lim_{x\rightarrow2}\ \frac{x^2-4}{2x^2+4x-16}\ =....  

1

0

2

14\frac{1}{4}  

3

13\frac{1}{3}  

4

12\frac{1}{2}  

5

1

40

Multiple Choice

lim⁡x→2  x2−5x+6x2+2x−8 = ....\lim_{x\rightarrow2}\ \ \frac{x^2-5x+6}{x^2+2x-8}\ =\ ....  

1

2

2

1

3

16\frac{1}{6}  

4

−16-\frac{1}{6}  

5

−112-\frac{1}{12}  

41

Multiple Choice

lim⁡x→∞ 1−2x+2x3x3+x+1= ...\lim_{x\rightarrow\infty}\ \frac{1-2x+2x^3}{x^3+x+1}=\ ...  

1

- 4

2

- 2

3

1

4

2

5

∞\infty  

42

Multiple Choice

lim⁡x→∞ 3x2+x+2x3+2x2+1 = ...\lim_{x\rightarrow\infty}\ \frac{3x^2+x+2}{x^3+2x^2+1}\ =\ ...  

1

0

2

1,5

3

2

4

3

5

∞\infty  

43

Multiple Choice

lim⁡x→∞ 3x2+x+2x3+2x2+1 = ...\lim_{x\rightarrow\infty}\ \frac{3x^2+x+2}{x^3+2x^2+1}\ =\ ...  

1

0

2

1,5

3

2

4

3

5

∞\infty  

44

Multiple Choice

lim⁡x→∞ 6x3+x2+22x3+x+1 =  ...\lim_{x\rightarrow\infty}\ \frac{6x^3+x^2+2}{2x^3+x+1}\ =\ \ ...  

1

0

2

1

3

3

4

4

5

∞\infty  

45

Multiple Choice

Nilai dari lim⁡x→∞(x2+7x+5−x2−2x+3)\lim_{x\rightarrow\infty}\left(\sqrt{x^2+7x+5}-\sqrt{x^2-2x+3}\right)  adalah ....

1

801280\frac{1}{2}  

2

70 1270\ \frac{1}{2}  

3

60 1260\ \frac{1}{2}  

4

50 1250\ \frac{1}{2}  

5

40 1240\ \frac{1}{2}  

46

Multiple Choice

Question image
1

-2

2

-1

3

1

4

2

5

4

47

Multiple Choice

Question image
1

7

2

5

3

4

4

2

5

∞\infty

48

Multiple Choice

Nilai dari lim⁡x→1x2+2x−82x2−5x+2 Nilai\ dari\ \lim_{x\rightarrow1}^{ }\frac{x^2+2x-8}{2x^2-5x+2\ }  adalah

1

- 4

2

−25\frac{-2}{5}  

3

0

4

12\frac{1}{2}  

5

5

49

Multiple Choice

Question image

Nilai limit dari

1

7

2

4

3

6

4

3

5

2

50

Multiple Choice

Nilai dari lim⁡x→∞ (2x + 3) − (4x2 + 3x + 6) = ....\lim_{x\rightarrow\infty}\ \left(2x\ +\ 3\right)\ -\ \left(\sqrt{4x^2\ +\ 3x\ +\ 6}\right)\ =\ ....   

1

34\frac{3}{4}  

2

2

3

94\frac{9}{4}  

4

72\frac{7}{2}  

5

74\frac{7}{4}  

51

Multiple Choice

Nilai dari  lim⁡x→1 2−4x1−x2 adalah .......\lim_{x\rightarrow1}\ \frac{2-\sqrt{4x}}{1-x^2}\ adalah\ .......  

1

0

2

14\frac{1}{4}  

3

12\frac{1}{2}  

4

1

5

4

52

Multiple Choice

lim⁡x→3 (3x − 2) = .....\lim_{x\rightarrow3\ }\left(3x\ -\ 2\right)\ =\ .....  

1

4

2

5

3

6

4

7

5

8

53

Multiple Choice

lim⁡x→−5 ⁡(2x4+3x3−25)\lim_{x\rightarrow-5}\ ⁡(2x^4+3x^3-25)  adalah ....

1

1.650

2

1.600

3

1.400

4

875

5

850

54

Multiple Choice

Nilai lim⁡x→1 x2 − 5x + 4x − 1 \lim_{x\rightarrow1}\ \frac{x^2\ -\ 5x\ +\ 4}{x\ -\ 1}\  adalah ....

1

− 5-\ 5

2

− 4-\ 4

3

− 3-\ 3

4

00

5

55

55

Multiple Choice

lim⁡x→16 x − 4x − 16\lim_{x\rightarrow16}\ \frac{\sqrt{x}\ -\ 4}{x\ -\ 16}  = ....

1

00

2

18\frac{1}{8}

3

14\frac{1}{4}

4

12\frac{1}{2}

5

∞\infty

56

Multiple Choice

lim⁡x→3(2x−5)=....\lim_{x\rightarrow3}\left(2x-5\right)=....  

1

3

2

1

3

-1

4

-3

5

2

57

Multiple Choice

lim⁡x→2(2x3+5x2+2x+1)=....\lim_{x\rightarrow2}\left(2x^3+5x^2+2x+1\right)=....  

1

38

2

39

3

40

4

41

5

42

58

Multiple Choice

lim⁡x→3 x2+4x−21x−3=....\lim_{x\rightarrow3}\ \frac{x^2+4x-21}{x-3}=....  

1

6

2

8

3

10

4

12

5

14

59

Multiple Choice

lim⁡x→2 x2−5x+6x2+2x−8=....\lim_{x\rightarrow2}\ \frac{x^2-5x+6}{x^2+2x-8}=....  

1

1

2

13\frac{1}{3}  

3

12\frac{1}{2}  

4

−16-\frac{1}{6}  

5

-1

60

Multiple Choice

lim⁡x→5 2x2−17x+35x−5=....\lim_{x\rightarrow5}\ \frac{2x^2-17x+35}{x-5}=....  

1

3

2

5

3

7

4

9

5

8

61

Multiple Choice

Question image
1

-2

2

-1

3

1

4

2

5

4

62

Multiple Choice

tentukan hasil dari lim⁡x→1(x−2x+3)=\lim_{x\rightarrow1}\left(\frac{x-2}{x+3}\right)=  

1

−23-\frac{2}{3}  

2

−14-\frac{1}{4}  

3

12\frac{1}{2}  

4

23\frac{2}{3}  

5

1

63

Multiple Choice

Nilai dari

lim⁡x→−4 x2−6x+8x−4=....\lim_{x\rightarrow-4}\ \frac{x^2-6x+8}{x-4}=....  

1

-6

2

0

3

2

4

6

5

8

64

Multiple Choice

lim⁡x→2 3x2+4x−2=....\lim_{x\rightarrow2}\ 3x^2+4x-2=....  

1

16

2

17

3

18

4

19

5

20

65

Multiple Choice

lim⁡x→∞ x2−8x+154x+3=.....\lim_{x\rightarrow\infty}\ \frac{x^2-8x+15}{4x+3}=.....  

1

-2

2

∞\infty  

3

0

4

1

5

2

66

Multiple Choice

lim⁡x→5 10 =.....\lim_{x\rightarrow5}\ 10\ =.....  

1

0

2

5

3

10

4

20

5

25

67

Multiple Choice

lim⁡x→3 2x+4= .....\lim_{x\rightarrow3}\ 2x+4=\ .....  



1

6

2

8

3

9

4

10

5

12

68

Multiple Choice

lim⁡x→7x2−49x−7=...\lim_{x\rightarrow7}\frac{x^2-49}{x-7}=...  

1

11

2

12

3

13

4

14

5

15

69

Multiple Choice

lim⁡x→3x2−9x−3=...\lim_{x\rightarrow3}\frac{x^2-9}{x-3}=...  

1

0

2

1

3

6

4

9

5

12

70

Multiple Choice

lim⁡x→2 3x2−6xx−2\lim_{x\rightarrow2}\ \frac{3x^2-6x}{x-2}  adalah ....

1

12

2

6

3

3

4

2

5

0

71

Multiple Choice

lim⁡x→2 (x2+2x−3) =.......\lim_{x\rightarrow2}\ \left(x^2+2x-3\right)\ =.......  

1

3

2

4

3

5

4

6

5

7

72

Multiple Choice

lim⁡x→9 5 =.......\lim_{x\rightarrow9}\ 5\ =.......  

1

0

2

5

3

9

4

14

5

45

73

Multiple Choice

lim⁡x→1 (x−2x+3) =........\lim_{x\rightarrow1}\ \left(\frac{x-2}{x+3}\right)\ =........  

1

−23-\frac{2}{3}  

2

−14-\frac{1}{4}  

3

12\frac{1}{2}  

4

23\frac{2}{3}  

5

1

74

Multiple Choice

lim⁡x→3 x2 + x3 =.......\lim_{x\rightarrow3}\ \frac{x^2\ +\ x}{3}\ =.......  

1

7

2

6

3

4

4

3

5

2

75

Multiple Choice

Nilai dari lim⁡x→−32x +lim⁡x→−1(x2+5x)2 =.......Nilai\ dari\ \lim_{x\rightarrow-3}2x\ +\lim_{x\rightarrow-1}\left(x^2+5x\right)^2\ =.......

1

42

2

30

3

10

4

5

5

0

76

Multiple Choice

lim⁡x→3 x2 −8x +15x−3=..............\lim_{x\rightarrow3}\ \frac{x^2\ -8x\ +15}{x-3}=..............  

1

3

2

-2

3

-3

4

-6

5

-7

77

Multiple Choice

lim⁡x→1  x2−5x +4x2−1 =.............\lim_{x\rightarrow1\ }\ \frac{x^2-5x\ +4}{x^2-1}\ =.............  

1

1

2

23\frac{2}{3}  

3

−12-\frac{1}{2}  

4

-1

5

−32-\frac{3}{2}  

78

Multiple Choice

Nilai dari lim⁡x→3 x2−9x2−2x−3 =.........Nilai\ dari\ \lim_{x\rightarrow3}\ \frac{x^2-9}{x^2-2x-3}\ =.........  

1

−32-\frac{3}{2}  

2

−23-\frac{2}{3}  

3

0

4

23\frac{2}{3}  

5

32\frac{3}{2}  

79

Multiple Choice

lim⁡x→2 x2−5x+6x2+2x−8 =.......\lim_{x\rightarrow2}\ \frac{x^2-5x+6}{x^2+2x-8}\ =.......  

1

1

2

12\frac{1}{2}  

3

13\frac{1}{3}  

4

−13-\frac{1}{3}  

5

−16-\frac{1}{6}  

80

Multiple Choice

lim⁡x→16 x−4x − 16 =........\lim_{x\rightarrow16}\ \frac{\sqrt{x}-4}{x\ -\ 16}\ =........  

1

0

2

18\frac{1}{8}  

3

14\frac{1}{4}  

4

12\frac{1}{2}  

5

∞\infty  

81

Multiple Choice

lim⁡x→0 5x3−9+x=.....\lim_{x\rightarrow0}\ \frac{5x}{3-\sqrt{9+x}}=.....  

1

30

2

27

3

15

4

-27

5

-30

82

Multiple Choice

lim⁡x→0 3x9+x −9−x=............\lim_{x\rightarrow0}\ \frac{3x}{\sqrt{9+x}\ -\sqrt{9-x}}=............  

1

3

2

6

3

9

4

12

5

15

83

Multiple Choice

Jika lim⁡x→p x2+1x+3=5, maka nilai p =.......Jika\ \lim_{x\rightarrow p}\ \frac{x^2+1}{x+3}=5,\ maka\ nilai\ p\ =.......  

1

-7

2

-2

3

7

4

-2 atau 7

5

-7 atau 2

84

Multiple Choice

lim⁡x→2 x−2x+7−3 =........\lim_{x\rightarrow2}\ \frac{x-2}{\sqrt{x+7}-3}\ =........  

1

0

2

1

3

2

4

4

5

6

85

Multiple Choice

lim⁡x→1 1−x2−x+3 =.......\lim_{x\rightarrow1}\ \frac{1-x}{2-\sqrt{x+3}}\ =.......  

1

8

2

6

3

4

4

3

5

2

86

Multiple Choice

Nilai lim⁡x→1 x2−5x+4x−1 adalah.......Nilai\ \lim_{x\rightarrow1}\ \frac{x^2-5x+4}{x-1}\ adalah.......  

1

-5

2

-4

3

-3

4

0

5

5

87

Multiple Choice

dari gambar fungsi berikut manakah yang mempunyai nilai limit pada x yang ditunjuk

1
2
3
4
5

88

Multiple Choice

lim⁡x→2 x2−4x−2=.............\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}=.............  

1

0

2

∞\infty  

3

-4

4

2

5

4

89

Multiple Choice

lim⁡x→1 x2−5x+4x3−1 = ....\lim_{x\rightarrow1}\ \frac{x^2-5x+4}{x^3-1}\ =\ ....  

1

-1

2

1

3

23\frac{2}{3}  

4

−12-\frac{1}{2}  

5

−23-\frac{2}{3}  

90

Multiple Choice

Jika diketahui lim⁡x→a x2−3x+2x−2=1 \lim_{x\rightarrow a}\ \frac{x^2-3x+2}{x-2}=1\  , maka nilai dari a = ....

1

1

2

2

3

3

4

4

5

5

91

Konsep Limit Fungsi Aljabar

By Afiatul Latifah

92

Multiple Choice

Question image

Untuk x=0,8x=0,8   maka nilai f(x)=...f\left(x\right)=...  

1

2,8

2

2,7

3

2,6

93

Multiple Choice

Question image

Untuk x=1,001x=1,001   maka nilai f(x)=...f\left(x\right)=...  

1

3,001

2

3,01

3

3,1

94

Fill in the Blanks

media image

Maka diperoleh, jika nilai x mendekati 1, maka nilai f(x) mendekati

Type answer...

95

media

96

media
Soal kedua

​Some text here about the topic of discussion.

97

Multiple Choice

Question image

Untuk x=1,99x=1,99  maka nilai f(x)=...f\left(x\right)=...  

1

3,8

2

3,9

3

3,99

98

Multiple Choice

Question image

Untuk x=2,001x=2,001  maka nilai f(x)=...f\left(x\right)=...  

1

4,001

2

4,01

3

4,1

99

Fill in the Blanks

media image

Maka diperoleh, jika nilai x mendekati 2, maka nilai f(x) mendekati

Type answer...

100

media

101

Soal ketiga

​Some text here about the topic of discussion.

102

Multiple Choice

Question image

Untuk x=1,99x=1,99  maka nilai f(x)=...f\left(x\right)=...  

1

-796,01

2

-36,2

3

-76,1

103

Multiple Choice

Question image

Untuk x=2,001x=2,001  maka nilai f(x)=...f\left(x\right)=...  

1

84,1

2

804,01

3

8004,001

104

Fill in the Blanks

media image

Apakah jika didekati dari kiri dan kanan nilai f(x) sama?

Type answer...

105

Multiple Choice

Karena limit kiri dan limit kanan untuk x mendekati 2 tidak sama, maka dapat dikatakan limit fungsi f(x) untuk x mendekati 2 ...............

1

Ada

2

Tidak ada

106

Multiple Choice

lim⁡x→c−f(x) = lim⁡x→c+f(x) = L\lim_{x\rightarrow c^-}f\left(x\right)\ =\ \lim_{x\rightarrow c^+}f\left(x\right)\ =\ L  

Bentuk di atas memiliki arti bahwa ...

1

lim⁡x→c−f(x)=L\lim_{x\rightarrow c^-}f\left(x\right)=L  

2

lim⁡x→c+f(x)=L\lim_{x\rightarrow c^+}f\left(x\right)=L  

3

lim⁡x→cf(x)=L\lim_{x\rightarrow c^{ }}f\left(x\right)=L  

4

lim⁡x→cf(x)≠L\lim_{x\rightarrow c^{ }}f\left(x\right)\ne L  

5

f(x) tidak memiliki nilai limit

107

Multiple Choice

lim⁡x→c−f(x)=lim⁡x→c+f(x)=L\lim_{x\rightarrow c^-}f\left(x\right)=\lim_{x\rightarrow c^+}f\left(x\right)=L  

Bentuk di atas adalah ...

1

definisi limit

2

teorema limit

3

rumus limit

4

pengertian limit

5

aksioma limit

108

Multiple Choice

Ada berapa metode yang dapat digunakan untuk menyelesaikan limit fungsi aljabar yang sudah kamu pelajari?

1

1

2

2

3

3

4

4

5

5

109

Multiple Choice

lim⁡x→4x2−x−12x2−7x+12\lim_{x\rightarrow4}\frac{x^2-x-12}{x^2-7x+12}  

Bentuk di atas dapat diselesaikan dengan menggunakan metode ...

1

substitusi

2

eliminasi

3

grafik

4

memfaktorkan

5

kali akar sekawan

110

Multiple Choice

lim⁡x→32x2−x+3x+3\lim_{x\rightarrow3}\frac{2x^2-x+3}{x+3}  

Bentuk di atas dapat diselesaikan menggunakan metode

1

substitusi

2

eliminasi

3

memfaktorkan

4

kali akar sekawan

5

cramer

111

Multiple Choice

lim⁡x→a(f(x) +g(x) )= lim⁡x→af(x)+lim⁡x→ag(x)\lim_{x\rightarrow a}\left(f\left(x\right)\ +g\left(x\right)\ \right)=\ \lim_{x\rightarrow a}f\left(x\right)+\lim_{x\rightarrow a}g\left(x\right)  

Bentuk di atas sesuai dengan ...

1

definisi limit

2

teorema limit

3

konsep limit

4

pengertian limit

5

rumus limit

112

Multiple Choice

Nilai dari lim⁡x→5 10 =... .\lim_{x\rightarrow5}\ 10\ =...\ .  

1

0

2

5

3

10

4

20

5

25

113

Multiple Choice

Nilai dari lim⁡x→4x2−16x−4= ...\lim_{x\rightarrow4}\frac{x^2-16}{x-4}=\ ...  

1

16

2

8

3

4

4

-4

5

-8

114

Multiple Choice

lim⁡x→22−x2−x+2=...\lim_{x\rightarrow2}\frac{2-x}{2-\sqrt[]{x+2}}=...  

Bentuk di atas dapat diselesaikan dengan menggunakan metode ...

1

substitusi

2

eliminasi

3

grafik

4

memfaktorkan

5

mengali akar sekawan

115

Multiple Choice

lim⁡x→−2(5x2 + 2x −3)=\lim_{x\rightarrow-2}\left(5x^2\ +\ 2x\ -3\right)=  

1

20

2

15

3

13

4

 10

5

7 

pattern-tertiary

lim⁡x→−5 ⁡(2x4+3x3−25)\lim_{x\rightarrow-5}\ ⁡(2x^4+3x^3-25)  adalah ....

1

1.650

2

1.600

3

1.400

4

875

5

850

Show answer

Auto Play

Slide 1 / 115

MULTIPLE CHOICE