

Stoichiometry
Presentation
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Science
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7th Grade
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Practice Problem
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Medium
Lauren Allen
Used 1+ times
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5 Slides • 3 Questions
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Stoichiometry
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1 Mole- 6.022*1023 of any element is equal to 1 Mol of that element
Example- 1 mole of oxygen is 6.022*1023 (16g) which is the same as its atomic mass on the periodic table of elements
Avogadros constant
1/12th of the relative mass of carbon- AMU- Atomic Mass number
This is the mass on the periodic table elements
Relative Atomic Mass
Vocabulary!!!
4
Finding the Molar mass is looking up each individual element of an equation and adding them all together
C12H22O11= (12*Molar mass of carbon)+(22*molar mass of Hydrogen)+(11* Molar mass of oxygen)= (12*12.01 g/mol) + (22*1.01 g/mol)+ (11 * 16.00 g/mol)= 342.30 g/mol
Molar Mass
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All Equations must be balanced- Nothing is created and nothing is destroyed- everything is changed to a different form-
Law of Conservation of Mass
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Labelling
Label the equation
Products
Reactants
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Fill in the Blanks
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Fill in the Blanks
Stoichiometry
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