
Grade 12 Lesson 15.10 Sallts
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Chemistry
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12th Grade
•
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nahla idress
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27 Slides • 10 Questions
1
15.10: Acid-base properties of salts
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What is a solution of HCl called ?
3
Multiple Choice
What is a solution of HCl called ?
alkaline solution
acidic solution
neutral solution
4
Multiple Choice
What is a solution of NaOH called?
neutral solution
acidic solution
basic solution
5
Multiple Choice
What do we call
the following compounds?
Acids
Salts
Alkalis
Bases
6
Salt is an ionic compound formed by acid-base neutralization reaction.
Acid + Base → salt + water
Lesson 15.10:
Acid-Base Properties of Salts
7
Hint to identify the acid and base that form the salt
1- Write the dissociation reaction of salt.
2- Always add H+ to negative ion to know the acid.
3- If the positive ion is group 1A or 2A add OH- to know the base.
- If Not remove H+ to know the base.
Example: NaNO3 → Na+ + NO3-
-
(NaOH) ( HNO3)
Strong base Strong acid
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Open Ended
Identify the acid and base that form the following salts:
1- NH4Cl
2- NaClO3
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SHOW ME
identify the acid and base that form the following salts:
a- NH4Cl
b- NaClO3
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●
●What will happen when salt is dissolved in water?
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●Conjugate bases of strong acid or cations of group 1A and 2A cannot make hydrolysis with water.
These are spectator ions: Cl-, NO3-,Na+.
●Conjugate bases of weak acids and conjugate acids of weak bases can behave as acids or bases by reacting with water.
This reaction is hydrolysis reaction
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NaNO3 is a salt:
Dissociation reaction: NaNO3→ Na+ + NO3
-
A Solution containing Na+ and NO3-
ions is: neutral, PH= 7
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A) Salts produce neutral solutions:
pH=7
Strong acid + Strong base = neutral salt
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LiOH NaOH
KOH RbOH
CsOH Ba(OH)2
Sr(OH)2
15
Multiple Choice
The solution of NaBr is, .....
acidic
basic
has pH = 7
has pH above 7
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B) Salts that produce basic solution
•The solution of a salt derived from strong base and weak acid is basic.
•acetic acid + sodium hydroxide 🡪 sodium acetate + water
CH3COOH + NaOH 🡪 CH3COONa + H2O
(weak acid) (strong base) (Salt)
•Dissociation reaction of sodium acetate in water:
CH3COONa (s) 🡪 CH3COO- (aq) + Na+ (aq)
Na+ : neither donates or accepts H+ ions
CH3COO- : is conjugate base of weak acid CH3COOH stronger than H2O
in base property and therefore has affinity for H+ .
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•Hydrolysis reaction of CH3COO- :
CH3COO- + H2O ⇄ CH3COOH + OH-
Because this reaction produce OH- ions, the
sodium acetate solution is basic
To find the pH of basic salts use the following
shortcut:
pH= 14 + log ⎷Kb x [salt]0
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Multiple Choice
The solution of KSO3 is, .....
neutral
acidic
pH < 7
basic
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•The solution of a salt derived from strong acid (HCl) and weak
base (NH3) is acidic.
•For example when solid NH4Cl is dissolved in water, NH4 + and Cl- ions are present
•Dissociation reaction of NH4Cl:
NH4Cl 🡪 NH4 + + Cl-
Cl-: conjugate base of strong acid HCl
Cl- have no affinity for H+ in water
NH4+ : strong conjugate acid of weak base NH3
NH4+ is a donor for H+ (stronger than water in acidity)
C) Salts that produce acidic solution
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Hydrolysis reaction :
NH4+ ⇄ NH3 + H+
solution is acidic
Because this reaction
produces H+ , NH4Cl
solution is acidic
To find the pH of acidic salts use the
following shortcut:
PH= - log ⎷Ka x [salt]0
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Multiple Choice
The solution of NH4NO2 is, .....
neutral
pH < 7
basic
pH =7
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25
Open Ended
Think Pair Share
Classify the following salts as acidic, basic, or neutral: NaCl, NH4Cl, KNO3.
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Salts in which both anion and cation hydrolyze
•Salts derived from weak acid and weak base , both cation and anion hydrolyze
•pH of the solution containing such a salt depends on the relative strength of
weak acid and weak base.
•Ka = Kb solution will be neutral
•Ka > Kb solution will be acidic because cation hydrolysis will be more
important than anion hydrolysis
•Kb > Ka Solution will be basic because the anion will hydrolyze to greater
extent than the cation. At equilibrium, there will be more OH- than H+ ions
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Predict whether aqueous solution of each of the following salts will be
acidic, basic, or neutral
A- NH4C2H3O2
B- NH4CN
C- NaNO2
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A- NH4C2H3O2
Ions in solution are NH4
+ and C2H3O2
-
•Ka for NH4
+ is 5.6 x 10 -10
•Kb for C2H3O2
- is 5.6 x 10 -10
Ka = Kb the solution will be neutral
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-
B- NH4CN
Ions in solution are NH4
+ and CN-
Ka for NH4
+ is 5.6 x 10 -10
Kb for CN- is 1.6 x 10-5
Kb > ka the solution will be basic
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C- NaNO2
Ions in solution are Na+ and NO2
-
Na+ : do not hydrolyze
NO2- : weak conjugate base of weak acid HNO2
Hydrolysis reaction:
NO2- + H2O ⇄ HNO2 + OH-
This hydrolysis reaction produce:
OH- the pH of NaNO2 solution will be basic
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Open Ended
Think Pair Share
Calculate the pH of a 0.1 M sodium chloride (NaCl) solution.
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Some anions can act either as an acid or as a base.
EXAMPLE:
HCO3
- ion that is amphoteric and acts like acid or base
Because Kb > ka we predict that more OH- are produced.
Thus a solution of sodium bicarbonate NaHCO3 will be basic
HCO3 - + H2O ⇄ CO3 2- + H3O+ Ka= 4.8 x 10 -11 HCO3 - + H2O ⇄ H2CO3 + OH- Kb= 2.4 x 10 -8
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34
Arrange the following from the most acidic to the most
basic:
CaBr2 , KNO2 , HClO4 , NH4ClO4 , HNO2
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Open Ended
Arrange the following from the most acidic to the most
basic: CaBr2 , KNO2 , HClO4 , NH4ClO4 , HNO2
36
Arrange the following from the most acidic to the most
basic:
CaBr2 , KNO2 , HClO4 , NH4ClO4 , HNO2
solution:
HClO4 ---HNO2 ---NH4ClO4 ---CaBr2 ---KNO2
Strong acid weak acid acidic salt neutral salt basic salt
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15.10: Acid-base properties of salts
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