
Permutations
Presentation
•
Mathematics
•
10th Grade
•
Hard
Joseph Anderson
FREE Resource
6 Slides • 4 Questions
1
Permutations Part 2
More Examples
By Danica Antiquina
2
Multiple Choice
Example #1.
How many ways can 8 people sit around a circular table?
5,040
10,080
40,320
80,640
3
Example #1
How many ways can 8 people sit around a circular table?
Given: n = 8
Solution: P = (n-1)!
= (8 - 1)!
= 7!
= 7×6×5×4×3×2×1
= 5,040
4
Multiple Choice
Example #2.
How many ways can 8 people sit around a circular table if 4 people insist on sitting beside each other?
376
476
576
676
5
Example #2
How many ways can 8 people sit around a circular table if 4 people insist on sitting beside each other?
Given: n = 5
Solution: P = (n-1)!
= (5 - 1)! 4!
= 4! 4!
= 4×3×2×1×4×3×2×1
= 576
6
Multiple Choice
Example #3.
How many ways can the letters
of the word H I G H S C H O O L be arranged?
151,200
302,400
604,800
1,209,600
7
Example #3
How many ways can the letters of the word
H I G H S C H O O L be arranged?
Given: n = 10
letter H = 3
letter O = 2
Solution: P=n!/(p!q!r!…)
= 10!
3! 2!
= 10×9×8×7×6×5×4×3×2×1
3×2×1×2×1
= 302,400
8
Multiple Choice
Example #4.
How many ways can the letters
of the word P R E S E N T A T I O N be arranged?
7,484,400
14,968,800
29,937,600
59,875,200
9
Example #3
How many ways can the letters of the word
P R E S E N T A T I O N be arranged?
Given: n = 12
letter E = 2
letter N = 2
letter T = 2
Solution: P=n!/(p!q!r!…)
= 12!
2! 2! 2!
= 12×11×10×9×8×7×6×5×4×3×2×1
2×1×2×1×2×1
= 59,875,200
10
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Permutations Part 2
More Examples
By Danica Antiquina
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