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Probability

Probability

Assessment

Presentation

Mathematics

12th Grade

Hard

Normal Distribution

Standards-aligned

Created by

Joseph Anderson

FREE Resource

4 Slides • 10 Questions

1

PROBABILITY CLASS 12

by Indu Khurana

2

Probability of binomial distribution

​Where P is the probability of success and q is the probability of failure

​n and p are called parameters of binomial distribution

​ =

Mean of binomial distribution= nxp

Variance of binomial distribution= npq

Standard deviation of binomial distribution= √npq

3

​Poisson Distribution

​Probability P(r)= ,

​Recurrence formula: P(r+1)=

​Mean and variance=

Standard deviation =

4

​Normal distribution

5

Multiple Choice

If X is a normal distribution random variable with  μ=10\mu=10   and  σ=2\sigma=2  , find P(X  <9.8<9.8  )

1

0.4602

2

0.4206

3

0.4620

4

0.4260

6

Multiple Choice

If X is a normal distribution random variable with  μ=10\mu=10   and  σ=2\sigma=2  , find

P( 12<12<  X  <14.5<14.5  )

1

0.1546

2

0.1456

3

0.1465

4

0.1645

7

Multiple Choice

If Z is a standard normal variable, find  P(2.38<Z<1.45)P\left(-2.38<Z<-1.45\right)  

1

F(1.45)F(2.38)F\left(1.45\right)-F\left(-2.38\right)  

2

F(1.45)F(2.38)F\left(-1.45\right)-F\left(-2.38\right)  

3

F(1.45)F(2.38)F\left(-1.45\right)-F\left(2.38\right)  

4

F(2.38)F(1.45)F\left(-2.38\right)-F\left(-1.45\right)  

8

Multiple Choice

The standard deviation of a poisson variate X is √3. Find the probability X=2, given  e3=0.0498e^{-3}=0.0498  

1

0.2142

2

0.2421

3

0.2214

4

0.2241

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13

Multiple Choice

A die is tosses 3 times. Getting an even number is success. Find the binomial distribution and its variance.

1

(12+12)3, 14\left(\frac{1}{2}+\frac{1}{2}\right)^3,\ \frac{1}{4}  

2

(12+12)3, 34\left(\frac{1}{2}+\frac{1}{2}\right)^3,\ \frac{3}{4}  

3

(12+12)3, 24\left(\frac{1}{2}+\frac{1}{2}\right)^3,\ \frac{2}{4}  

4

(12+12)3, 32\left(\frac{1}{2}+\frac{1}{2}\right)^3,\ \frac{3}{2}  

14

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PROBABILITY CLASS 12

by Indu Khurana

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