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Molarity of Solution

Molarity of Solution

Assessment

Presentation

Chemistry

10th Grade

Hard

Created by

Joseph Anderson

FREE Resource

5 Slides • 7 Questions

1

2 Step Molarity

Today we will be combining the knowledge we gained during the mole calculations and the molarity

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2

Open Ended

How many moles are present in 300 grams of CaCO3 (gram formula mass = 100 g/mol)


Remember:

moles =

mass =

gfm =


moles = (mass/gfm)

3

Multiple Choice

What is the molarity of a 1.5 L solution containing 3 moles of CaCO3?


What is the molarity in this question?

1

3 moles

2

1.5 L

3

unknown

4

Multiple Choice

What is the molarity of a 1.5 L solution containing 3 moles of CaCO3?


What is the liters of solution in this problem?

1

3 moles

2

1.5 L

3

unknown

5

Multiple Choice

What is the molarity of a 1.5 L solution containing 3 moles of CaCO3?


What is the moles of solute in the problem?

1

3 moles

2

1.5 L

3

unknown

6

Open Ended

What is the molarity of a 1.5 L solution containing 3 moles of CaCO3?


Molarity = M

moles of solution = 3

Liters of solution = 1.5


Remember:


Molarity = moles of solute/liters of solution

7

Why 2 steps?

  • Some questions will ask for the molarity, but instead of giving you the number of moles, it will provide you with the mass and the gram formula mass.

  • Step 1: Find the # of moles

    # of moles = given mass

                        gram formula mass


  • Step 2: Find the molarity of the solution

    Molarity = moles of solute

                     Liters of solution


8

Sample Problem 1:

What is the molarity of a 2.0 L solution containing 145 grams of NaCl (gram formula mass = 58 g/mol)









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9

Sample Problem 2:

What is the molarity of a 6 L solution containing 303 grams of KNO3 (gram formula mass = 101 g/mol)?


mass =

gfm =

moles =




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10

Open Ended

Step 1: Find the number of moles.


mass = 303

gfm = 101

moles = mol


Remember: moles = mass/gfm

11

Sample Problem 2:

What is the molarity of a 6 L solution containing 303 grams of KNO3 (gram formula mass = 101 g/mol)?


moles = 3

Liters of solution =

Molarity =



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12

Open Ended

Step 2: Find the molarity


moles = 3 mol

liters of solution = 6L

Molarity = M


Remember:

Molarity = moles of solute/Liters of solution

2 Step Molarity

Today we will be combining the knowledge we gained during the mole calculations and the molarity

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