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Recursive and Explicit Formulas for Arithmetic Sequences

Recursive and Explicit Formulas for Arithmetic Sequences

Assessment

Presentation

Mathematics

6th - 8th Grade

Practice Problem

Hard

Created by

Ferdad Roidad

FREE Resource

7 Slides • 12 Questions

1

​Arithmetic Sequences: Recursive and Explicit Formulas

By Ferdad Roidad

2

Recursive Formula

Gives the 1st term a(1) and a rule for finding the nth term represented as a(n) given the previous term which is the (n-1)th term represented as a(n-1).

  • The recursive formula for a sequence gives the 1st term represented by a(1) and a rule for finding the nth term represented by a(n) given the previous term which is the (n-1)th term represented by a(n-1).

  • The drawback is needing all previous terms to find the nth term.

  • Any arithmetic sequence can be represented by:

    a(1), a(2), a(3), . . . , a(n-1), a(n), a(n+1), . . .

3

Recursive Formula

Gives the 1st term a(1) and a rule for finding the nth term represented as a(n) given the previous term which is the (n-1)th term represented as a(n-1).

  • Example of recursive formula for the arithmetic sequence -1, 4, 9, 14, 19, . . .

  • Recursive formula: a(1) = -1, a(n) = a(n-1) + 5

  • The 1st term a(1) is -1 and the common difference d is 5, so we show that the nth term a(n) is equal to the previous term a(n-1) + 5. This means we add 5 to the previous term to get the next term.

  • The 6th term a(6) = a(6-1) + 5 = a(5) + 5 = 19 + 5 = 24.

4

Explicit Formula

Gives the nth term without having to find all previous terms.
a(n) = a(1) + (n-1)(d), where a(1) is the 1st term and d is the common difference found by subtracting any term from the term which follows it.

  • The explicit formula allows finding the nth term represented as a(n) without having to find all previous terms.

  • The explicit formula can be written as a(n) = a(1) + (n-1)(d), where a(n) is the nth term, a(1) is the 1st term, n is the term number, and d is the common difference for the arithmetic sequence which is either given or can be calculated by subtracting any term from the term which follows it.

  • For example, d = a(2) - a(1) = 2nd term - 1st term.

5

Explicit Formula

Gives the nth term without having to find all previous terms.
a(n) = a(1) + (n-1)(d), where a(1) is the 1st term and d is the common difference found by subtracting any term from the term which follows it.

  • Example of explicit formula for the arithmetic sequence

    -1, 4, 9, 14, 19, . . .

  • Explicit formula: a(n) = a(1) + (n-1)(d), so

    a(n) = -1 + (n-1)(5) since a(1) = -1 and d = 4 - (-1) = 5.

  • The 6th term a(6) = -1+(6-1)(5) = -1+(5)(5) = -1+25 = 24.

6

Comparing Recursive and Explicit Formulas for an Arithmetic Sequence

Recursive Formula: a(1) = #, a(n) = a(n-1) + d
Explicit Formula: a(n) = a(1) + (n-1)(d)

  • Given the arithmetic sequence: 3, -1, -5, -9, . . .

  • We have the 1st term a(1) = 3 and the common difference d = -1 - 3 = -4 which means we add -4 (or subtract 4) to get the next term in the sequence. We also have a(2) = -1, a(3) = -5, a(4) = -9.

  • The recursive formula is: a(1) = 3, a(n) = a(n-1) + -4 which can also be written as a(n) = a(n-1) - 4.

  • The explicit formula is: a(n) = 3 + (n-1)(-4) which can be simplified using the distributive property to get a(n) = 3 + -4n + 4 which is a(n) = 7 - 4n.

7

Comparing Recursive and Explicit Formulas for an Arithmetic Sequence

​Recursive Formula: a(1) = #, a(n) = a(n-1) + d
Explicit Formula: a(n) = a(1) + (n-1)(d)

  • Given the arithmetic sequence: 3, -1, -5, -9, . . .

  • To find the 5th term a(5), we can use either formula since we have a(4) = -9 and the recursive formula would give a(5) = a(5-1) - 4 = a(4) - 4 = -9 - 4 = -13, so a(5) = -13 using the recursive formula.

  • The explicit formula gives a(5) = 3 + (5-1)(-4) = 3 + (4)(-4) = 3 + -16 = -13, so a(5) = -13 using the explicit formula.

  • We can check the simplified explicit formula a(n) = 7 - 4n as well to show a(5) = 7 - 4(5) = 7 - 20 = -13, so a(5) = -13.

8

Multiple Choice

Given the recursive formula of an arithmetic sequence, what is the 1st term?

a(1)=6a\left(1\right)=-6

a(n)=a(n1)+4a\left(n\right)=a\left(n-1\right)+4

1

00

2

11

3

6-6

4

2-2

5

44

9

Multiple Choice

Given the recursive formula of an arithmetic sequence, what is the common difference dd ?

a(1)=6a\left(1\right)=-6

a(n)=a(n1)+4a\left(n\right)=a\left(n-1\right)+4

1

d=10d=-10

2

d=2d=-2

3

d=6d=-6

4

d=4d=4

5

d=4d=-4

10

Multiple Choice

Given the recursive formula of an arithmetic sequence, what is the 2nd term a(2)a\left(2\right) ?

a(1)=6a\left(1\right)=-6

a(n)=a(n1)+4a\left(n\right)=a\left(n-1\right)+4

1

a(2)=10a\left(2\right)=-10

2

a(2)=2a\left(2\right)=-2

3

a(2)=6a\left(2\right)=-6

4

a(2)=5a\left(2\right)=5

5

a(2)=2a\left(2\right)=2

11

Multiple Choice

Given the recursive formula of an arithmetic sequence, what is the 3rd term a(3)a\left(3\right) ?

a(1)=6a\left(1\right)=-6

a(n)=a(n1)+4a\left(n\right)=a\left(n-1\right)+4

1

a(3)=14a\left(3\right)=-14

2

a(3)=7a\left(3\right)=7

3

a(3)=3a\left(3\right)=3

4

a(3)=2a\left(3\right)=2

5

a(3)=2a\left(3\right)=-2

12

Multiple Choice

Given the recursive formula of an arithmetic sequence, what is the explicit formula for this sequence?

a(1)=6a\left(1\right)=-6

a(n)=a(n1)+4a\left(n\right)=a\left(n-1\right)+4

Hint: a(n)=a(1)+(n1)(d)a\left(n\right)=a\left(1\right)+\left(n-1\right)\left(d\right) is the explicit formula for an arithmetic sequence.

1

a(n) = -6 + (n-1)(-4)

2

a(n) = -6 - (n - 1)(4)

3

a(n) = -6 + (n - 1)(4)

4

a(n) = -6 + (n+1)(4)

5

a(n) = 4 + (n - 1)(-6)

13

Multiple Choice

Given the explicit formula for an arithmetic sequence, what is the 1st term a(1)a\left(1\right) ?

a(n)=8+(n1)(3)a\left(n\right)=8+\left(n-1\right)\left(3\right)

Hint: In general, the explicit formula for an arithmetic sequence is a(n)=a(1)+(n1)(d)a\left(n\right)=a\left(1\right)+\left(n-1\right)\left(d\right)

1

a(1)=1a\left(1\right)=1

2

a(1)=4a\left(1\right)=4

3

a(1)=8a\left(1\right)=8

4

a(1)=11a\left(1\right)=11

5

a(1)=3a\left(1\right)=3

14

Multiple Choice

Given the explicit formula for an arithmetic sequence, what is the common difference dd ?

a(n)=8+(n1)(3)a\left(n\right)=8+\left(n-1\right)\left(3\right)

Hint: In general, the explicit formula for an arithmetic sequence is a(n)=a(1)+(n1)(d)a\left(n\right)=a\left(1\right)+\left(n-1\right)\left(d\right)

1

d=8d=8

2

d=11d=11

3

d=1d=-1

4

d=5d=5

5

d=3d=3

15

Multiple Choice

Given the explicit formula for an arithmetic sequence, what is the 2nd term a(2)a\left(2\right) ?

a(n)=8+(n1)(3)a\left(n\right)=8+\left(n-1\right)\left(3\right)

Hint: Replace nn with 22 in the given explicit formula, then simplify.

1

a(2)=8a\left(2\right)=8

2

a(2)=11a\left(2\right)=11

3

a(2)=27a\left(2\right)=27

4

a(2)=3a\left(2\right)=3

5

a(2)=14a\left(2\right)=14

16

Multiple Choice

Given the explicit formula for an arithmetic sequence, what is the 31st31st term a(31)a\left(31\right) ?

a(n)=8+(n1)(3)a\left(n\right)=8+\left(n-1\right)\left(3\right)

Hint: Replace nn with 3131 in the given explicit formula, then simplify.

1

a(31)=38a\left(31\right)=38

2

a(31)=39a\left(31\right)=39

3

a(31)=41a\left(31\right)=41

4

a(31)=98a\left(31\right)=98

5

a(31)=114a\left(31\right)=114

17

Multiple Choice

a(n)=8+(n1)(3)a\left(n\right)=8+\left(n-1\right)\left(3\right) ; a(101)=8+(1011)(3)a\left(101\right)=8+\left(101-1\right)\left(3\right)

a(101)=8+(100)(3)=(108)(3)=324a\left(101\right)=8+\left(100\right)\left(3\right)=\left(108\right)\left(3\right)=324

A student found the 101st101st term of the arithmetic sequence with the above explicit formula by replacing nn with 101101 .

Select the appropriate choice.

1

The student's work and answer are both correct.

2

The student should have replaced nn with 100100 .

3

The student should have multiplied 100 by 3, then added 8 to get 308.

4

The student should have added 8 with 101 to get 109, then subtracted 3 to get 106.

5

The student should have found the first 100 terms, then added 8 to the 100th term.

18

Multiple Choice

Given the explicit formula for an arithmetic sequence is a(n)=1+(n1)(6)a\left(n\right)=-1+\left(n-1\right)\left(6\right) , determine the simplified representation of this explicit formula by applying the distributive property and combining like terms (numbers). Multiply 6 by (n - 1), then combine like terms.

1

a(n)=8na\left(n\right)=-8n

2

a(n)=6n2a\left(n\right)=6n-2

3

a(n)=5n6a\left(n\right)=5n-6

4

a(n)=6n7a\left(n\right)=6n-7

5

a(n)=7n6a\left(n\right)=-7n-6

19

Multiple Choice

Given the explicit formula for an arithmetic sequence is a(n)=12+(n1)(4)a\left(n\right)=12+\left(n-1\right)\left(-4\right) , determine the simplified representation of this explicit formula by applying the distributive property and combining like terms (numbers). Multiply -4 by (n - 1), then combine like terms.

1

a(n)=7na\left(n\right)=7n

2

a(n)=164na\left(n\right)=16-4n

3

a(n)=12na\left(n\right)=12n

4

a(n)=48+4na\left(n\right)=-48+4n

5

a(n)=84na\left(n\right)=8-4n

​Arithmetic Sequences: Recursive and Explicit Formulas

By Ferdad Roidad

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