Circles

In the equation (x+2)²+(y-3)²=4, the center of the circle is at...

• (-2, 3)
• (-3, 2)
• (2, -3)
• (3, -2)

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

Tags

CCSS.HSG.GPE.A.1

Change the following equation to standard form
x²+y²-4x+12y-8=0

• (x+2)²+(y-6)²=48
• (x-2)²+(y+6)²=48
• (x-6)²+(y-2)²=48
• (x+2)²+(y-6)²=48

Tags

CCSS.HSG.GPE.A.1

What is the equation of a circle with radius 4 and center (0, 8)?

• x² + (y-8)² = 16
• (x-8)² + y² = 4
• x² + (y-8)² = 4
• x² + (y+8)² = 16

Tags

CCSS.HSG.GPE.A.1

See Picture

• A
• B
• C
• D

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36
• (x - 5)² + (y + 2)² = 6
• (x + 5)² + (y - 2)² = 36
• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1

Find the equation of the circle with center (−8,3) and (2,−5) is on the circle?

• (x+8)²+(y−3)²=164^.5.
• (x+3)²+(y−8)²=164.
• (x)²+(y)²=164.
• (x+8)²+(y−3)²=164.

Tags

CCSS.HSG.GPE.A.1

The endpoints of a diameter of a circle are (3,1) and (9,5).Find the equation of the circle?

• (x−6)²+(y−3)²=13
• (x−3)²+(y−6)²=13²
• (x−5)²+(y−9)²=13
• (x−9)²+(y−5)²=169/4

Tags

CCSS.HSG.GPE.A.1

Which graph corresponds to 
(x+2)²+ (y-3)²=36

• A
• B
• C
• D

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GPE.A.1