Equation of circles

What is the equation of a circle with radius 2 and center (3, 4)?

• (x+3)² + (y+4)² = 2
• (x-3)² + (y-4)² = 2
• (x+3)² + (y+4)² = 4
• (x-3)² + (y-4)² = 4

Tags

CCSS.HSG.GPE.A.1

What is the equation of a circle with radius 4 and center (0, 8)?

• x² + (y-8)² = 16
• (x-8)² + y² = 4
• x² + (y-8)² = 4
• x² + (y+8)² = 16

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 3

• x²+y²=3
• x²+y²=6
• x²+y²=9

Tags

CCSS.HSG.GPE.A.1

What is the center of the circle with equation x² + y² = 1?

• (1, 1)
• (0, 0)
• not enough information

Tags

CCSS.HSG.GPE.A.1

What is the equation of a circle with radius 4 and center (0, 8)?

• x² + (y-8)² = 16
• (x-8)² + y² = 4
• x² + (y-8)² = 4
• x² + (y+8)² = 16

In the equation (x-3)²+(y+4)²=121, the radius of the circle is

• 242
• 11
• 121
• 22

See Picture

• A
• B
• C
• D

Tags

CCSS.HSG.GPE.A.1

See Picture

• A
• B
• C

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36
• (x - 5)² + (y + 2)² = 6
• (x + 5)² + (y - 2)² = 36
• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1

Find the equation of the circle with center (−8,3) and (2,−5) is on the circle?
Hint: you need to find the radius by plugging in values for four variables 
x=
y=
h=
k=
in (x-h)²+(y-k)²=r²

• (x+8)²+(y−3)²=164^.5.
• (x+3)²+(y−8)²=164.
• (x)²+(y)²=164.
• (x+8)²+(y−3)²=164.