PC - 1.4 (Day 1) Practice

The red graph is y=x².  What is the equation of the blue graph?

• y=(x-2)²
• y=(x+2)²
• y=x⁴
• something else

If the red graph is f(x) what could the blue graph be?

• f(x-3)

• f(4x)

• f(x)

• something else

The red graph is f(x).  What could the blue graph be?

• f(3x)
• f(x)+1
• f(x-3)+1
• f(x+3)+1

Tags

CCSS.HSF.BF.B.3

CCSS.HSF.IF.B.4

The red graph is f(x).
Which graph is f(-x)?

• Orange
• Red
• Blue
• Green

This is the graph of f(x).
If we drew f(x-2)+3 then where would the black blob move to?

• Stay the same
• Up 3
• To (2,4)
• To (-2,4)

What is the vertex of the following function?
y=2|x-3|+1

• (2,3)
• (-3,1)
• (2,-3)
• (3,1)

Tags

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

Write an absolute value function given the following transformations:

Reflection over the x-axis,

Vertical shift down 7 units,

Horizontal shift right 2 units

• y = -|x + 2| - 7

• y = |x - 2| - 7

• y = -|x - 2| - 7

• y = -|x - 2| + 7

Write an absolute value function given the following transformations:

Vertical Stretch (skinnier) of 2,

Horizontal shift left 1 unit,

Vertical shift down 9 units

• $f\left(x\right)=\frac{1}{2}\left|x+1\right|-9$

• $f\left(x\right)=\left|\frac{1}{2}x+1\right|-9$

• f(x) = 2|x + 1| - 9

• f(x) = 2|x - 1| - 9

What is the equation of this graph?

• y= 2 |x-3| + 1

• y= 2 |x-1| + 3

• y= - 2 |x-3| + 1

• y= - 2 |x-1| + 3

Write an absolute value function given the following transformations:

Vertical Stretch (skinnier) of 3

Horizontal shift left 9 unit

Vertical shift up 2 units

• y = 3|(x + 9)| + 2

• y = 3|(x - 9)| + 2

• y = |3x - 9| + 2

• y = |3x + 9| + 2