Area, Surface Area, & Volume Formulas

Area, Surface Area, & Volume Formulas

10th - 11th Grade

9 Qs

quiz-placeholder

Similar activities

Week 7 Review

Week 7 Review

9th - 12th Grade

10 Qs

Area and Surface Area

Area and Surface Area

6th Grade - University

14 Qs

Factor Trinomials

Factor Trinomials

9th - 12th Grade

14 Qs

Factoring a > 1

Factoring a > 1

8th - 10th Grade

10 Qs

Surface Area of Spheres

Surface Area of Spheres

8th - 11th Grade

8 Qs

Surface Area of Spheres

Surface Area of Spheres

9th - 12th Grade

10 Qs

Chapter 12 Review

Chapter 12 Review

10th Grade

12 Qs

(8-1) Review 01 (Geo XC)

(8-1) Review 01 (Geo XC)

10th - 12th Grade

13 Qs

Area, Surface Area, & Volume Formulas

Area, Surface Area, & Volume Formulas

Assessment

Quiz

Mathematics

10th - 11th Grade

Medium

CCSS
7.G.B.6, 8.G.C.9, 6.G.A.1

+2

Standards-aligned

Used 49+ times

FREE Resource

9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Indicate the correct formula to find the area of the figure. What is the area?

A=πr2A=\pi r^2  A=26.42 ft.2A=26.42\ ft.^2  

 A=bh2A=\frac{bh}{2}   A=8.41π ft.2A=8.41\pi\ ft.^2  

 A=πr2A=\pi r^2   A=9.11 ft.2A=9.11\ ft.^2  

 A=bh2A=\frac{bh}{2}   A=26.42 ft.2A=26.42\ ft.^2  

Tags

CCSS.7.G.B.4

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Choose the correct formula to find the volume of this figure. What is its volume?

 V=πr2hV=\pi r^2h   V=1696.46 mm3V=1696.46\ mm^3  

 V=πr2h3V=\frac{\pi r^2h}{3}  V=540π mm3V=540\pi\ mm^3  

 V=πr2hV=\pi r^2h   V=135π mm3V=135\pi\ mm^3  

V=πr2h3V=\frac{\pi r^2h}{3}  V=424.12 mm3V=424.12\ mm^3  

Tags

CCSS.8.G.C.9

CCSS.HSG.GMD.A.3

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Indicate the correct formula to find the volume of the figure? What is its volume

 V=Bh3V=\frac{Bh}{3}   V=29.27π m3V=29.27\pi\ m^3  

 V=43πr3V=\frac{4}{3}\pi r^3   V=53.75 m3V=53.75\ m^3  

V=Bh3V=\frac{Bh}{3}  V=91.95π m3V=91.95\pi\ m^3  

V=43πr3V=\frac{4}{3}\pi r^3  V=91.95 m3V=91.95\ m^3  

Tags

CCSS.8.G.C.9

CCSS.HSG.GMD.A.3

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Choose the correct formula to find the surface area of the figure. What is its surface area?

 SA=2πr2+2πrhSA=2\pi r^2+2\pi rh  V=280π yd2V=280\pi\ yd^2  

 SA=4πr2SA=4\pi r^2  SA=184π yd2SA=184\pi\ yd^2  

 SA=2πr2+2πrhSA=2\pi r^2+2\pi rh  SA=578.05 yd2SA=578.05\ yd^2  

 SA=4πr2SA=4\pi r^2  SA=879.65 yd2SA=879.65\ yd^2  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Choose the correct formula to find the area of the figure. What is its area?

A=bh2A=\frac{bh}{2}  A=815.68 m2A=815.68\ m^2  

 A=bh2A=\frac{bh}{2}   A=833.85 m2A=833.85\ m^2  

A=h(b1+b2)2A=\frac{h\left(b_1+b_2\right)}{2}  A=833.85 m2A=833.85\ m^2  

 A=h(b1+b2)2A=\frac{h\left(b_1+b_2\right)}{2}   A=815.68 m2A=815.68\ m^2  

Tags

CCSS.6.G.A.1

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Choose the correct formula to find the area of the figure. What is its area?

A=bh2A=\frac{bh}{2}  A=216 cm2A=216\ cm^2  

 A=lwA=lw   A=216 cm2A=216\ cm^2  

 A=bh2A=\frac{bh}{2}   A=282.15 cm2A=282.15\ cm^2  

A=lwA=lw  A=282.15 cm2A=282.15\ cm^2  

Tags

CCSS.6.G.A.1

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Choose the correct formula to find the surface area of the figure. What is its surface area?

SA=2lw+2lh+2hwSA=2lw+2lh+2hw SA=542 ft.2SA=542\ ft.^2

SA=2lw+2lh+2hwSA=2lw+2lh+2hw SA=819 ft.2SA=819\ ft.^2

SA=12lp+BSA=\frac{1}{2}lp+B SA=542 ft.2SA=542\ ft.^2

SA=12lp+BSA=\frac{1}{2}lp+B SA=819 ft.2SA=819\ ft.^2

Tags

CCSS.7.G.B.6

8.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Choose the correct formula to find the volume of the figure. What is its volume?

V=BhV=Bh V=124.71 in.3V=124.71\ in.^3

V=BhV=Bh V=374.13 in.3V=374.13\ in.^3

V=Bh3V=\frac{Bh}{3} V=374.13 in.3V=374.13\ in.^3

V=Bh3V=\frac{Bh}{3} V=124.71 in.3V=124.71\ in.^3

Tags

CCSS.7.G.B.6

9.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Choose the correct formula to use to find the surface area of the figure. What is its surface area?

SA=12lp+BSA=\frac{1}{2}lp+B SA=185 in.2SA=185\ in.^2

SA=2lw+2lh+2hwSA=2lw+2lh+2hw SA=185 in.2SA=185\ in.^2

SA=2lw+2lh+2hwSA=2lw+2lh+2hw SA=99 in.2SA=99\ in.^2

SA=12lp+BSA=\frac{1}{2}lp+B SA=99 in.2SA=99\ in.^2

Tags

CCSS.7.G.B.6