Slope Review

Convert the standard form equation into slope-intercept form.
4x - 3y = 15

• y = (4/3)x - 5
• y = ⅔x - 5
• x = ¾
• y = 27, 239, 430

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Convert the standard form equation into slope-intercept form.
5x - 4y = -20

• y = (5/4)x + 5
• y = -5x - 4
• x = 20
• y = 27, 239, 430

Tags

CCSS.HSA.CED.A.4

Which of these represents point-slope form of a linear equation?

• y - y₁ = m(x - x₁)
• Ax + By = C
• y = mx + b

Which of these represents slope-intercept form of a linear equation?

• y - y₁ = m(x-x₁)
• Ax + By = C
• y = mx + b

Tags

CCSS.8.EE.B.6

CCSS.8.F.A.3

Write the equation in point-slope form of the line that passes through the given point and has the given slope:
 (-2, -1); m= -3

• y + 1 = -3(x - 2)
• y + 1 = -3(x + 2)
• y - 1 = 3(x - 1)
• y + 2 = -3(x + 1)

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GPE.B.5

Write the equation in point-slope form of the line that passes through the given point and has the given slope.
(4, -7); m = -1/4

• y +7 = -1/4(x - 4)
• y - 4 = -1/4(x + 7)
• y+ 7 = 4(x - 4)
• y - 7 = -1/4(x - 4)

Tags

CCSS.HSA.CED.A.2

Write the equation in point-slope form of the line that passes through the given point and has the given slope.

(4, 0); m = 7

• y - 4 = 7(x + 0)

• y - 0 = 7(x - 4)

• y = 7x + 4

• y = 7x + 0

Tags

CCSS.HSA.CED.A.2

CCSS.HSG.GPE.B.5

What is the equation of the line that goes through the points (3,-1) and (2,-4)?

• y = 3x - 4
• y = -3x + 8
• y = 3x - 1
• y = 3x - 10

Tags

CCSS.HSA.CED.A.2

What is the x and y intercept for the following equation ?
4x - 10y = 20

• x - int = 4    
  y-int = -10
• x-int = 5
  y-int = 2
• x - int = 5
  y int = -2
• x -int = 4
  y -int = -10

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSA.REI.D.11

What is the y-intercept for the given graph?

• -5
• 5
• 1
• -1

Tags

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

CCSS.HSS.ID.C.7