11/14 Lesson 2-6 Review

Determine the values of a, b, and c for the quadratic equation:

4x² – 8x = 3

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

Use the quadratic formula to solve 2x² + 2x - 12.

• -2, 3

• 2, 3

• 2, -3

• -2, -3

Tags

CCSS.HSA-REI.B.4B

Use the quadratic formula to find the solutions for

y = -x² - 5x + 12

• No Real Solution

• 
• 
• 

Tags

CCSS.HSA-REI.B.4B

Solve 2x² + 7x - 15 = 0

• -3/2 or 5

• No Solution

• -5 or 3/2

• 0.7 or 5

Tags

CCSS.HSA-REI.B.4B

Solve Using the Quadratic Formula
 x² + 4x - 40 = -8

• -10 & -4
• -4 & 10
• -8 & 4
• 8 & -4

Tags

CCSS.HSA-REI.B.4B

What should you do first in solving this equation?

x² + 6x - 13 = 3

• Factor

• Write down: a = 1, b = 6, c = -13

• Subtract 3 from both sides.

• Add 3 to both sides.

Tags

CCSS.HSA-REI.B.4B

Solve using the quadratic formula...

9x² = 4 + 7x

• 
• 
• 
• No solution

Tags

CCSS.HSA-REI.B.4B

Solve Using the Quadratic Formula
 x² + 4x - 40 = -8

• -10 & -4
• -4 & 10
• -8 & 4
• 8 & -4

Tags

CCSS.HSA-REI.B.4B

Solve using the quadratic formula...
9x² = 4 + 7x

• x = 2 and x = 3
• x = -1 and x = .25
• x = 1 and x = -.45
• x = 1.16, and x = -.38

Tags

CCSS.HSA-REI.B.4B

If the discriminant is zero you will have

• no real solutions
• two real solutions
• 1 real solution
• 1 imaginary solution

Tags

CCSS.HSA-REI.B.4B