Test over solving equations - Pre-Algebra

What is the value of x that satisfies this equation?:  $9x-2=25$  

• x = 1

• x = 2

• x = 3

• x = 4

Tags

CCSS.7.EE.B.4A

A student solved this problem. What mistakes, if any, were made?

• On step 1, he added 4 to both sides. You cannot add the same number to both sides of an equation.

• On step 2, he moved the = sign. He should have 5m + 10 = 0 instead of 5m = 10.

• On step 3, he divided both sides by 5. He should have divided both sides by 5.

• There are no mistakes.

Tags

CCSS.HSA.REI.A.1

What is the value of x that makes this equation true?  $-10h+1=-19$  

• h = 2

• h = -2

• h = 3

• infinitely many solutions

Solve:  $7\left(x\ +\ 2\right)=35$  

• x = 3

• x = 4

• x = 5

• no solution

Tags

CCSS.7.EE.B.4A

Solve:  $\frac{1}{5}\left(5x+10\right)=10$  

• x = 8

• x = 9

• x = -1

• x = 2

Tags

CCSS.7.EE.B.4A

Solve:  $0.5\left(4x+8\right)=24$  

• x = 6

• x = -3

• x = 4

• x = 10

Tags

CCSS.7.EE.B.4A

A student solved this problem. Which, if any, describe the mistake(s) made?

• He distributed incorrectly on step 1. 6(x + 2) = 6x + 8

• He added 3x twice to the left side and added nothing to the right side. He made the scale unbalanced.

• On step 4, he should have added 12 to get rid of an added 12.

• There are no mistakes

Tags

CCSS.HSA.REI.A.1

Solve:   $8x+2\left(3x-2\right)=10$  

• x = 2

• x = -5

• x = 1

• x = 3

Tags

CCSS.8.EE.C.7B

A student solved this problem. Find any mistakes if there are any.

• On step 2, the student eliminated the m's when they don't eliminate. -2m - 2m does not equal 0.

• On step 3, the student added 1 to get rid of the subtracted 1. He should have subtracted 1.

• On step 4, the student added 6 and 1 incorrectly.

• There are no mistakes in this problem.

Solve:  $9x-4=2x+10$  

• x = 1

• x =2

• x = 3 

• no solution