Review for Log Test December 2019

Write the equation of the function f(x)=log₃x after the following transformations:

Translate 6 units left and 4 units up.

• g(x)=log₃(x+6)+4

• g(x)=log₃(x+4)-6

• g(x)=log₃(x-6)+4

• g(x)=3log(x+6)+4

Tags

CCSS.HSF.BF.B.3

Write the equation of the function f(x)=log(x+5)-6 after the following transformations:

Translate 3 units left and 2 units up.

• f(x)=log(x+2)+2

• f(x)=log(x+2)-4

• f(x)=log(x+8)-4

• f(x)=log(x+8)+2

Tags

CCSS.HSF.BF.B.3

CCSS.HSG.CO.A.2

Write as a single log: log 12 + 2 log x

• log (12 + 2x)
• log (14x)
• log (12 * 2x)
• log (12x²)

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.IF.C.8

Given log₂(x + 5) = 3 the first step to solve this equation is

• 2³ = x + 5

• 3² = x + 5

• 2^x = 3 - 5

• none of these

Tags

CCSS.HSF.BF.B.5

Condense:
 log4- logx- log5+log3

• log(20/3x)
• log(12x/5)
• log(12/5x)
• log(5x/12)

Tags

CCSS.HSA.SSE.B.3

CCSS.HSF.LE.A.4

Solve

2³ⁿ = 4 by re-writing as 2³ⁿ = 2² then n =

• 2

• 3

• 2/3

• 4

Log with a base "e" (log_e) is the same thing as...

• "e"
• Natural Logarithm (LN)
• Common Logarithm (Log)
• Natural Log, base "e"
  LN_e

Tags

CCSS.HSF.BF.B.5

evaluate: log₈8²

• -2

• 2

• 16

• 64

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

The first step to solve 8 = 2^5x+7 is

• 8 = 5x + 7

• 2³ = 5x + 7

• 2³ = 2^{5x + 7}

• none of these

Solve 8 = 2^5x+7

• x = ⅘

• x = ¼

• x = -⅘

• x = -¼

Tags

CCSS.7.EE.B.4A